MATHS M.C.Q. [1 Marks Each]

If we arrange the given numbers in ascending order, we get $0.015 < 0.105 < 0.15 < 0.501$

According to number system, every fraction in $\frac{\text{P}}{\text{q}}$ form can be converted into decimal number. and vice versa.

A decimal number is read by first reading the whole number part, then the decimal point and the digits of the decimal part one by one.
Hence, the decimal number $9.6$ is read as Nine point six

$\because 0.4 + 0.004 + 4.4$
$= 4.804$

$2+\frac{3}{10}+\frac{4}{100}$
$=2+0.3+0.04$
$=2.34$

Among $2.600, 2.006, 2.660,2.080, 2.660$ is the largest.

We know that to add numbers with different decimal places we expand all the numbers to the same decimal places by expanding zeroes.
So, the sum of $0.5, 12.56$ and $0.003$ is
$0.500 + 12.560 + 0.003 = 13.063$

$=2.06$
$(2\times1)+\Big(6\times\frac{1}{100}\Big)$
$=2+\frac{6}{100}$

$\because 3.5 + 4.05 - 6.005$
$= 3.500 + 4.050 - 6.005$
$= 7.550 - 6.005$
$= 1.545$

The fraction $\frac{3}{1000}$ in decimal form is $0.003.$

$\frac{3}{100}=0.03$ (here, we have the denominator $100,$ so we mark the decimal such that $3$ is in the hundredth place).
$\frac{5}{10000}=0.0005$ (here, we have the denominator $10000$, so we mark the decimal such that $5$ is in the ten thousandth place).
Therefore, $\frac{3}{100}+\frac{5}{10000}=0.03+0.0005$
$=0.0305$

Distance between points $= 4.5 - (-2.3) = 6.8$

To find the percent of a given number, we will multiply it with $100.$
Let the number in decimal be $x$
When converted to percent, the number becomes $x \times 100 = 62.9$
$\Rightarrow\text{x}=\frac{62.9}{100}$
$\Rightarrow\text{x}=0.629$

Converting all the given decimals into like decimals:
$2.600, 2.006, 2.660$ and $2.080$
Among these given like decimals, $2.660$ is the largest.

$\frac{4}{100}+\frac{7}{10000}$
$=0.04+0.0007$
$=0.0407$

$\frac{5}{10}+\frac{3}{100}$
$=0.5+0.03$
$=0.53$

$36.2<\text{br}/>\Rightarrow 36+0.2 = \frac {362} {10} = 36\frac {2} {10}$

When the prime factorization of the denominator of a fraction has only factors of $2$ and factors of $5$, then the number is a terminating decimal. If there are prime factors in the denominator other than $2$ or $5$, then the decimals repeat.

$2\frac{19}{100}=\frac{219}{100}$
$=\frac{200+19}{100}$
$=\frac{200}{100}+\frac{19}{100}$
$=2+0.19$
$=2.19$

$\frac{-1}{2}=0.5$

$=3\frac{5}{1000}$
$=3+\frac{5}{1000}$
$=3+0.005$
$=3.005$

$0.000000375=375\times { 10 }^{ -9 }=\\3.75\times { 10 }^{ -7 }=\cfrac { 375 }{ 100 } \times { 10 }^{ -7 }$
$=\cfrac { 15 }{ 4 } \times { 10 }^{ -7 }=3\cfrac { 3 }{ 4 } \times { 10 }^{ -7 }$

$4\frac{7}{8}=\frac{39}{8}=4.875$

$\frac{4}{10}+\frac{2}{1000}= 0.4+0.002=0.402$

$0.004=\frac{0.004}{1}$
Here, we have three numbers after decimal point.
So, we multiply by both numerator and denominator by $1000.$
$=\frac{0.004\times1000}{1\times1000}$
$=\frac{4}{1000}$
$\therefore$ Fraction for 0.004 is $\frac{4}{1000}$

We know that $1000m = 1km.$
Therefore, $1\text{m}=\frac{1}{1000}\text{m}=0.001\text{km.}$

In $16.534$, place value of $3$
$= 3$ hundredths $= 0.03$
$=\frac{3}{100}$

$\frac{4}{100}+\frac{7}{10000}$
$= 0.04 + 0.0007$
Converting into like decimals:
$0.0400 + 0.0007 = 0.0407$

We know that $1000g = 1kg.$
Therefore, $1\text{g}=\frac{1}{1000}\text{kg}=0.001\text{kg}$
$5\text{g}=\frac{5}{1000}\text{kg}=0.005\text{kg}$
Therefore, $2kg 5gm$
$= 2kg + 0.005kg$
$= 2.005kg$

Let $3889 + 12.952 - x = 3854.002$
Then $x = (3889 + 12.952) - 3854.002$
$= 3901.952 - 3854.002$
$= 47.95$

$\frac{5}{100}=.05$

$4\frac{3}{1000}=4.03$