Question 11 Mark
Write the following divisions as fractions: $125\div50$
Answer
View full question & answer→$\frac{125}{50}$
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Question 21 Mark
Write the fraction representing the shaded portion.
Answer
View full question & answer→Fraction of the shaded portion $=\frac{\text{ Number of shaded parts}}{\text{Total number of parts}}$
Total number of parts $=7$
Number of shaded parts $=3$
Fraction of the shaded portion $ =\frac{3}{7}$
Total number of parts $=7$
Number of shaded parts $=3$
Fraction of the shaded portion $ =\frac{3}{7}$
Question 31 Mark
What fraction of an hour is $20$ minutes?
Answer
View full question & answer→Minutes in an hour $= 60 20$ minutes of an hour $= 2060 = 13$
Question 41 Mark
Arrange the following fractions in the ascending order: $\frac{2}{9},\frac{7}{9},\frac{3}{9},\frac{4}{9},\frac{1}{9},\frac{6}{9},\frac{5}{9}$
Answer
View full question & answer→When the denominators are the same and numerators are different, then the fraction with greater numerator has a larger value. $\frac{1}{9}<\frac{2}{9}<\frac{3}{9}<\frac{4}{9}<\frac{5}{9}<\frac{6}{9}<\frac{7}{9}$
Question 51 Mark
Colour the part according to the fraction given: $\frac{4}{9}$
Answer
View full question & answer→$\frac{4}{9}$
Question 61 Mark
Convert the following into an improper fraction:$12\frac{7}{15}$
Answer
View full question & answer→$12\frac{7}{15}=\frac{12\ \times\ 15\ +\ 7}{15}=\frac{187}{15}$
Question 71 Mark
Write the following fractions as divisions:$\frac{1}{5}$
Answer
View full question & answer→$1\div5$
Question 81 Mark
Mark $\frac{2}{6},\frac{4}{6},\frac{8}{6}$ and $\frac{6}{6}$ on the number line and put appropriate signs between fractions given below: $\frac{8}{6}....\frac{5}{6}$
Answer
$\frac{8}{6}>\frac{5}{6}$ because $8 > 5$ and denominator is the same.
View full question & answer→$\frac{8}{6}>\frac{5}{6}$ because $8 > 5$ and denominator is the same.
Question 91 Mark
Write the fraction representing the shaded portion.
Answer
View full question & answer→Fraction of the shaded portion $=\frac{\text{ Number of shaded parts}}{\text{Total number of parts}}$
Total number of parts $=9$
Number of shaded parts $=8$
Fraction of the shaded portion $ =\frac{8}{9}$
Total number of parts $=9$
Number of shaded parts $=8$
Fraction of the shaded portion $ =\frac{8}{9}$
Question 101 Mark
Convert the following into a mixed fraction:$\frac{226}{15}$
Answer
View full question & answer→$\frac{226}{15}$Quotient $= 15$, Remainder $= 1,$ Denominator $= 15$
$\Rightarrow\frac{226}{15}=15\frac{1}{15}$
$\Rightarrow\frac{226}{15}=15\frac{1}{15}$
Question 111 Mark
Mark $\frac{2}{6},\frac{4}{6},\frac{8}{6}$ and $\frac{6}{6}$ on the number line and put appropriate signs between fractions given below: $\frac{3}{6}....\frac{0}{6}$
Answer
$\frac{3}{6}>\frac{0}{6}$ because $3 > 0$ and denominator is the same.
View full question & answer→$\frac{3}{6}>\frac{0}{6}$ because $3 > 0$ and denominator is the same.
Question 121 Mark
Convert the following into a mixed fraction:$\frac{128}{5}$
Answer
View full question & answer→$\frac{128}{5}$Quotient $= 25$, Remainder $= 3$, Denominator $= 5$
$\Rightarrow\frac{128}{5}=25\frac{3}{5}$
$\Rightarrow\frac{128}{5}=25\frac{3}{5}$
Question 131 Mark
Write the following fractions as divisions:$\frac{90}{63}$
Answer
View full question & answer→$90\div63$
Question 141 Mark
Represent $\frac{2}{5}$ on a number line.
View full question & answer→Question 151 Mark
Fill in the missing fractions: $\frac{7}{10}-\Box=\frac{3}{10}$
Answer
View full question & answer→$\frac{7}{10}-\frac{2}{5}=\frac{3}{10}$Solution:
Given, $\frac{7}{10}-\Box=\frac{3}{10}$ $\Rightarrow\frac{7}{10}-\frac{3}{10}=\Box$ $\Rightarrow\frac{7-3}{10}=\Box$ $\Rightarrow\Box=\frac{4}{10}$ $\Box=\frac{2}{5}$
Given, $\frac{7}{10}-\Box=\frac{3}{10}$ $\Rightarrow\frac{7}{10}-\frac{3}{10}=\Box$ $\Rightarrow\frac{7-3}{10}=\Box$ $\Rightarrow\Box=\frac{4}{10}$ $\Box=\frac{2}{5}$
Question 161 Mark
Fill in the missing fractions: $\Box-\frac{3}{21}=\frac{5}{21}$
Answer
View full question & answer→$\frac{8}{21}-\frac{3}{21}=\frac{5}{21}$Solution:
Given, $\Box-\frac{3}{21}=\frac{5}{21}$ $\Rightarrow\Box=\frac{5}{21}+\frac{3}{21}$ $\Rightarrow\Box=\frac{5+3}{21}$ $\Box=\frac{8}{21}$
Given, $\Box-\frac{3}{21}=\frac{5}{21}$ $\Rightarrow\Box=\frac{5}{21}+\frac{3}{21}$ $\Rightarrow\Box=\frac{5+3}{21}$ $\Box=\frac{8}{21}$
Question 171 Mark
Write the fraction representing the shaded parts.
Answer
View full question & answer→Fraction of the shaded portion $=\frac{\text{ Number of shaded parts}}{\text{Total number of parts}}$
Total number of parts $=8$
Number of shaded parts $=4$
Fraction of the shaded portion $=\frac{4}{8}=\frac{1}{2}$
Total number of parts $=8$
Number of shaded parts $=4$
Fraction of the shaded portion $=\frac{4}{8}=\frac{1}{2}$
Question 181 Mark
Colour the part according to the fraction given: $\frac{2}{4}$
Answer
View full question & answer→$\frac{2}{4}$
Question 191 Mark
Write some equivalent fractions which contain all digits from $1$ to $9$ once only.
Answer
View full question & answer→$\frac{2}{4}=\frac{3}{6}=\frac{79}{158}$$\frac{3}{9}=\frac{2}{6}=\frac{58}{174}$
Question 201 Mark
Replace $\Box$ of the following by the correct number:$\frac{2}{7}=\frac{6}{\Box}$
Answer
View full question & answer→$\frac{2}{7}=\frac{6}{21}$
MCQ 211 Mark
Mark the correct alternative of the following:Which of the following is a fraction equivalent of $\frac{2}{3}?$
- A$\frac{4}{5}$
- B$\frac{8}{6}$
- C$\frac{10}{25}$
- ✓$\frac{10}{15}$
Answer
View full question & answer→Correct option: D.
$\frac{10}{15}$
$\Rightarrow\frac{10}{15}=\frac{2}{3}$
$\Rightarrow10\times3=2\times15$
$\Rightarrow30=30$
$\Rightarrow10\times3=2\times15$
$\Rightarrow30=30$
Question 221 Mark
Convert the following into an improper fraction:$7\frac{1}{4}$
Answer
View full question & answer→$7\frac{1}{4}=\frac{7\ \times\ 4\ +\ 1}{4}=\frac{29}{4}$
Question 231 Mark
Convert the following into an improper fraction:$8\frac{5}{7}$
Answer
View full question & answer→$8\frac{5}{7}=\frac{8\ \times\ 7\ +\ 5}{7}=\frac{61}{7}$
Question 241 Mark
Write the fraction representing the shaded portion.
Answer
View full question & answer→Fraction of the shaded portion $=\frac{\text{ Number of shaded parts}}{\text{Total number of parts}}$ Total number of parts $=4$ Number of shaded parts $=2$ Fraction of the shaded portion $ =\frac{2}{4} =\frac{1}{2}$
Question 251 Mark
Compare the following fractions and put an appropriate: $\frac{3}{6}....\frac{5}{6}$
Answer
View full question & answer→$\frac{3}{6}<\frac{5}{6}$ because $3 < 6$ and denominator is the same.
Question 261 Mark
Replace $\Box$ of the following by the correct number:$\frac{4}{5}=\frac{\Box}{20}$
View full question & answer→Question 271 Mark
Arrange the following fractions in the ascending order: $\frac{37}{47},\frac{37}{50},\frac{37}{100},\frac{37}{1000},\frac{37}{85},\frac{37}{41}$
Answer
View full question & answer→When numerator are the same and denominators are different, the fraction with greater denominator has a smaller value.$\frac{37}{1000}<\frac{37}{100}<\frac{37}{85}<\frac{37}{50}<\frac{37}{47}<\frac{37}{41}$
Question 281 Mark
Colour the part according to the fraction given: $\frac{1}{6}$ 
Answer
View full question & answer→$\frac{1}{6}$ 
Question 291 Mark
Mark $\frac{2}{6},\frac{4}{6},\frac{8}{6}$ and $\frac{6}{6}$ on the number line and put appropriate signs between fractions given below: $\frac{1}{6}....\frac{6}{6}$
Answer
$\frac{1}{6}<\frac{6}{6}$ because $6 > 1$ and denominator is the same.
View full question & answer→$\frac{1}{6}<\frac{6}{6}$ because $6 > 1$ and denominator is the same.
Question 301 Mark
Colour the part according to the fraction given: $\frac{3}{4}$
Answer
View full question & answer→$\frac{3}{4}$
Question 311 Mark
Subtract the sum of $\frac{2}{3}$ and $\frac{1}{2}$ from the sum of $\frac{5}{6},\frac{7}{12}$ and $\frac{4}{15}.$
Answer
View full question & answer→Sum of $\frac{2}{3}$ and $\frac{1}{2}$ is: $\frac{2}{3}+\frac{1}{2}=\frac{2\times2}{3\times2}+\frac{1\times3}{2\times3}$ (because LCM of 3 and 2 is 6)$=\frac{4}{6}+\frac{3}{6}$
$=\frac{4+3}{6}$
$=\frac{7}{6}$
Sum of $\frac{5}{6},\frac{7}{12}$ and $\frac{4}{15}$ is:$\frac{5}{6}+\frac{7}{12}+\frac{4}{15}=\frac{5\times10}{6\times10}+\frac{7\times5}{12\times5}+\frac{4\times4}{15\times4}$ (because $LCM$ of $6, 12$ and $15$ is $60)$
$=\frac{50}{60}+\frac{35}{60}+\frac{16}{60}$
$=\frac{50+35+16}{60}$
$=\frac{101}{60}$
Now, $\frac{101}{60}-\frac{7}{6}=\frac{101\times1}{60\times1}-\frac{7\times10}{6\times10}$ (because $LCM$ of $60$ and $6$ is $60) $$=\frac{101}{60}-\frac{70}{60}$
$=\frac{101-70}{60}$
$=\frac{31}{60}$
Hence, the difference of the sum of $\frac{2}{3}$ and $\frac{1}{2}$ from the sum of $\frac{5}{6},\frac{7}{12}$ and $\frac{4}{15}$ is $\frac{31}{60}.$
$=\frac{4+3}{6}$
$=\frac{7}{6}$
Sum of $\frac{5}{6},\frac{7}{12}$ and $\frac{4}{15}$ is:$\frac{5}{6}+\frac{7}{12}+\frac{4}{15}=\frac{5\times10}{6\times10}+\frac{7\times5}{12\times5}+\frac{4\times4}{15\times4}$ (because $LCM$ of $6, 12$ and $15$ is $60)$
$=\frac{50}{60}+\frac{35}{60}+\frac{16}{60}$
$=\frac{50+35+16}{60}$
$=\frac{101}{60}$
Now, $\frac{101}{60}-\frac{7}{6}=\frac{101\times1}{60\times1}-\frac{7\times10}{6\times10}$ (because $LCM$ of $60$ and $6$ is $60) $$=\frac{101}{60}-\frac{70}{60}$
$=\frac{101-70}{60}$
$=\frac{31}{60}$
Hence, the difference of the sum of $\frac{2}{3}$ and $\frac{1}{2}$ from the sum of $\frac{5}{6},\frac{7}{12}$ and $\frac{4}{15}$ is $\frac{31}{60}.$
Question 321 Mark
Replace $\Box$ of the following by the correct number:$\frac{45}{60}=\frac{15}{\Box}$
Answer
View full question & answer→$\frac{45}{60}=\frac{15}{20}$
Question 331 Mark
Replace $\Box$ of the following by the correct number:$\frac{18}{24}=\frac{\Box}{4}$
Answer
View full question & answer→$\frac{18}{24}=\frac{3}{8}$
Question 341 Mark
Shikha bought $7\frac{1}{2}\text{ litres}$ of milk. Out of this milk, $5\frac{3}{4}\text{ litres}$ was consumed. How much milk is left with her?
Answer
View full question & answer→Shikha bought total milk $=7\frac{1}{2}\text{ litres}=\Big(\frac{7\times2+1}{2}\Big)\text{litres}$
$=\frac{15}{2}\text{ litres}$
Milk consumed by Shikha $=5\frac{3}{4}\text{ litres}=\Big(\frac{5\times4+3}{4}\Big)\text{litres}$
$=\frac{23}{4}\text{ litres}$
Therefore, amount of milk left $=\Big(\frac{15}{2}-\frac{23}{4}\Big)\text{litres}$
$=\Big(\frac{15\times2}{2\times2}-\frac{23\times1}{4\times1}\Big)\text{litres}$
(because LCM of 2 and 4 is 4) $=\Big(\frac{30}{4}-\frac{23}{4}\Big)\text{litres}$
$=\Big(\frac{30-23}{4}\Big)\text{litres}$
$=\frac{7}{4}\text{ litres}$
$=1\frac{3}{4}\text{ litres}$
Thus, $1\frac{3}{4}\text{ litres}$ of milk is left with Shikha.
$=\frac{15}{2}\text{ litres}$
Milk consumed by Shikha $=5\frac{3}{4}\text{ litres}=\Big(\frac{5\times4+3}{4}\Big)\text{litres}$
$=\frac{23}{4}\text{ litres}$
Therefore, amount of milk left $=\Big(\frac{15}{2}-\frac{23}{4}\Big)\text{litres}$
$=\Big(\frac{15\times2}{2\times2}-\frac{23\times1}{4\times1}\Big)\text{litres}$
(because LCM of 2 and 4 is 4) $=\Big(\frac{30}{4}-\frac{23}{4}\Big)\text{litres}$
$=\Big(\frac{30-23}{4}\Big)\text{litres}$
$=\frac{7}{4}\text{ litres}$
$=1\frac{3}{4}\text{ litres}$
Thus, $1\frac{3}{4}\text{ litres}$ of milk is left with Shikha.
Question 351 Mark
Represent $\frac{0}{8}$ and $\frac{8}{8}$ on a number line.
View full question & answer→Question 361 Mark
Convert the following into a mixed fraction:$\frac{28}{9}$
Answer
View full question & answer→$\frac{28}{9}$Quotient $= 3$, Remainder $= 1$, Denominator $= 9$
$\Rightarrow\frac{28}{9}=3\frac{1}{9}$
$\Rightarrow\frac{28}{9}=3\frac{1}{9}$
Question 371 Mark
Write the following divisions as fractions: $6\div3$
Answer
View full question & answer→$\frac{6}{3}$
Question 381 Mark
Fill in the blanks: $8\frac{1}{8}-\ ....=\frac{7}{8}$
Answer
View full question & answer→Given, $8\frac{1}{8}-\ ....=\frac{7}{8}$
Let the value in the blank be $x.$ $8\frac{1}{8}-\text{x}=\frac{7}{8}$
$\Rightarrow8\frac{1}{8}-\frac{7}{8}=\text{x}$
$\Rightarrow\text{x}=\frac{8\times8+1}{8}-\frac{7}{8}$
$\Rightarrow\text{x}=\frac{65}{8}-\frac{7}{8}$
$\Rightarrow\text{x}=\frac{65-7}{8}$
$\Rightarrow\text{x}=\frac{58}{8}$
$\text{x}=7\frac{2}{8}$
Let the value in the blank be $x.$ $8\frac{1}{8}-\text{x}=\frac{7}{8}$
$\Rightarrow8\frac{1}{8}-\frac{7}{8}=\text{x}$
$\Rightarrow\text{x}=\frac{8\times8+1}{8}-\frac{7}{8}$
$\Rightarrow\text{x}=\frac{65}{8}-\frac{7}{8}$
$\Rightarrow\text{x}=\frac{65-7}{8}$
$\Rightarrow\text{x}=\frac{58}{8}$
$\text{x}=7\frac{2}{8}$
Question 391 Mark
Complete the addition$-$subtraction box.
Answer
View full question & answer→
$a.$ Solving rows first,
$\frac{2}{3}+\frac{4}{3}=\frac{2+4}{3}=\frac{6}{3}=2$
$\frac{1}{3}+\frac{2}{3}=\frac{1+2}{3}=\frac{3}{3}=1$
Solving the columns,
$\frac{2}{3}-\frac{1}{3}=\frac{2-1}{3}=\frac{1}{3}$
$\frac{4}{3}-\frac{2}{3}=\frac{4-2}{3}=\frac{2}{3}$
and $2-1=1$
Hence, the complete addition$-$subtraction box is:
$b.$ Solving rows first,
$\frac{1}{2}+\frac{1}{3}=\frac{1\times3}{2\times3}+\frac{1\times2}{3\times2}=\frac{3}{6}+\frac{2}{6}=\frac{3+2}{6}=\frac{5}{6}$
$\frac{1}{3}+\frac{1}{4}=\frac{1\times4}{3\times4}+\frac{1\times3}{4\times3}=\frac{4}{12}+\frac{3}{12}=\frac{4+3}{12}=\frac{7}{12}$
Solving the columns,
$\frac{1}{2}-\frac{1}{3}=\frac{1\times3}{2\times3}-\frac{1\times2}{3\times2}=\frac{3}{6}-\frac{2}{6}=\frac{3-2}{6}=\frac{1}{6}$
$\frac{1}{3}-\frac{1}{4}=\frac{1\times4}{3\times4}-\frac{1\times3}{4\times3}=\frac{4}{12}-\frac{3}{12}=\frac{4-3}{12}=\frac{1}{12}$
and $\frac{5}{6}-\frac{7}{12}=\frac{5\times2}{6\times2}-\frac{7\times1}{12\times1}=\frac{10}{12}-\frac{7}{12}=\frac{10-7}{12}=\frac{3}{12}=\frac{1}{4}$
Hence, the complete addition$-$subtraction box is:
$\frac{2}{3}+\frac{4}{3}=\frac{2+4}{3}=\frac{6}{3}=2$
$\frac{1}{3}+\frac{2}{3}=\frac{1+2}{3}=\frac{3}{3}=1$
Solving the columns,
$\frac{2}{3}-\frac{1}{3}=\frac{2-1}{3}=\frac{1}{3}$
$\frac{4}{3}-\frac{2}{3}=\frac{4-2}{3}=\frac{2}{3}$
and $2-1=1$
Hence, the complete addition$-$subtraction box is:
$b.$ Solving rows first,
$\frac{1}{2}+\frac{1}{3}=\frac{1\times3}{2\times3}+\frac{1\times2}{3\times2}=\frac{3}{6}+\frac{2}{6}=\frac{3+2}{6}=\frac{5}{6}$
$\frac{1}{3}+\frac{1}{4}=\frac{1\times4}{3\times4}+\frac{1\times3}{4\times3}=\frac{4}{12}+\frac{3}{12}=\frac{4+3}{12}=\frac{7}{12}$
Solving the columns,
$\frac{1}{2}-\frac{1}{3}=\frac{1\times3}{2\times3}-\frac{1\times2}{3\times2}=\frac{3}{6}-\frac{2}{6}=\frac{3-2}{6}=\frac{1}{6}$
$\frac{1}{3}-\frac{1}{4}=\frac{1\times4}{3\times4}-\frac{1\times3}{4\times3}=\frac{4}{12}-\frac{3}{12}=\frac{4-3}{12}=\frac{1}{12}$
and $\frac{5}{6}-\frac{7}{12}=\frac{5\times2}{6\times2}-\frac{7\times1}{12\times1}=\frac{10}{12}-\frac{7}{12}=\frac{10-7}{12}=\frac{3}{12}=\frac{1}{4}$
Hence, the complete addition$-$subtraction box is:
Question 401 Mark
Compare the following fractions and put an appropriate: $\frac{1}{7}....\frac{1}{4}$
Answer
View full question & answer→$\frac{1}{7}<\frac{1}{4}$ because $7 > 4$; if the numerator is the same, then the fraction that has smaller denominator is greater.
Question 411 Mark
Mark $\frac{2}{6},\frac{4}{6},\frac{8}{6}$ and $\frac{6}{6}$ on the number line and put appropriate signs between fractions given below: $\frac{5}{6}....\frac{2}{6}$
Answer
$\frac{5}{6}>\frac{2}{6}$ because $5 > 2$ and denominator is the same.
View full question & answer→$\frac{5}{6}>\frac{2}{6}$ because $5 > 2$ and denominator is the same.
Question 421 Mark
Write the following divisions as fractions: $55\div11$
Answer
View full question & answer→$\frac{55}{11}$
Question 431 Mark
Write these fractions appropriately as additions or subtractions:
Answer
View full question & answer→$\frac{1}{5}+\frac{2}{5}=\frac{3}{5}$ $\Big[\because\frac{1+2}{5}=\frac{3}{5}\Big]$
Question 441 Mark
Convert the following into a mixed fraction:$\frac{145}{9}$
Answer
View full question & answer→$\frac{145}{9}$Quotient $= 16$, Remainder $= 1$, Denominator $= 9$
$\Rightarrow\frac{145}{9}=16\frac{1}{9}$
$\Rightarrow\frac{145}{9}=16\frac{1}{9}$
Question 451 Mark
Represent $\frac{0}{10},\frac{1}{10},\frac{5}{10}$ and $\frac{10}{10}$ on a number line.
View full question & answer→Question 461 Mark
Arrange the following fractions in ascending order:$\frac{13}{18},\frac{8}{15},\frac{17}{24},\frac{7}{12}$
Answer
View full question & answer→Fractions can be compared by converting them into like fractions and then arranging them in ascending or descending order. Now, $\frac{13}{18}=\frac{13\times20}{18\times20}=\frac{260}{360}$
$\frac{8}{15}=\frac{8\times24}{15\times24}=\frac{192}{360}$
$\frac{17}{24}=\frac{17\times15}{24\times15}=\frac{255}{360}$
$\frac{7}{12}=\frac{7\times30}{12\times30}=\frac{210}{360}$ We know,
$192 < 210 < 255 < 260$
$\Rightarrow\frac{192}{360}<\frac{210}{360}<\frac{255}{360}<\frac{260}{360}$
$\Rightarrow\frac{8}{15}<\frac{7}{12}<\frac{17}{24}<\frac{13}{18}$
Hence, the following fractions in ascending order is $\frac{8}{15}<\frac{7}{12}<\frac{17}{24}<\frac{13}{18}$
$\frac{8}{15}=\frac{8\times24}{15\times24}=\frac{192}{360}$
$\frac{17}{24}=\frac{17\times15}{24\times15}=\frac{255}{360}$
$\frac{7}{12}=\frac{7\times30}{12\times30}=\frac{210}{360}$ We know,
$192 < 210 < 255 < 260$
$\Rightarrow\frac{192}{360}<\frac{210}{360}<\frac{255}{360}<\frac{260}{360}$
$\Rightarrow\frac{8}{15}<\frac{7}{12}<\frac{17}{24}<\frac{13}{18}$
Hence, the following fractions in ascending order is $\frac{8}{15}<\frac{7}{12}<\frac{17}{24}<\frac{13}{18}$
Question 471 Mark
Compare the following fractions and put an appropriate: $\frac{4}{5}....\frac{0}{5}$
Answer
View full question & answer→$\frac{4}{5}<\frac{0}{5}$ because $4 > 0$ and denominator is the same.
Question 481 Mark
Colour the part according to the fraction given: $\frac{1}{3}$
Answer
View full question & answer→$\frac{1}{3}$ 
Question 491 Mark
Convert the following into an improper fraction:$5\frac{3}{10}$
Answer
View full question & answer→$5\frac{3}{10}=\frac{5\ \times\ 10\ +\ 3}{10}=\frac{53}{10}$
Question 501 Mark
Write the fraction representing the shaded portion.
Answer
View full question & answer→Fraction of the shaded portion $=\frac{\text{ Number of shaded parts}}{\text{Total number of parts}}$
Total number of parts $=15$
Number of shaded parts $=11$
Fraction of the shaded portion $ =\frac{11}{15}$
Total number of parts $=15$
Number of shaded parts $=11$
Fraction of the shaded portion $ =\frac{11}{15}$