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MATHS 2 Marks Questions

Fractions · MP Board (MPBSE) STD 6 (Madhya Pradesh - English Medium). 64 questions.

Questions · Page 2 of 2

2 Marks Questions

Question 512 Marks
Shikhas has three frocks that she wears when playing. The material is good, but the colours are faded. Her mother buys some blue dye and uses it on two of the frocks. What fraction of all of the Shikha play frocks did her mother dye$?$
Answer
Total frocks shikha has $= 3 $
Number of frocks dyed by shikha’s mother $= 2$
Fraction of the dyed frocks $= 23$
Therefore, shikha’s mother dyed $23$ of shikha’s frocks.
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Question 522 Marks
Compare the following fractions using the symbol > or <: $\frac{2}{3}$ and $\frac{8}{12}$
Answer
$\frac{8}{12}=\frac{2\times2\times2}{2\times2\times3}=\frac{2}{3}$ therefore, $\frac{2}{3}=\frac{8}{12}$
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Question 532 Marks
Amit was given $\frac{5}{7}$ of a bucket of oranges. What fraction of oranges was left in the basket?
Answer
Fraction of oranges given to amit $=\frac{5}{7}$ Fraction of oranges left in the basket $=1-\frac{5}{7}$ $=\frac{7-5}{7}$ $=\frac{2}{7}$ Therefore, fraction of oranges left in the basket is $\frac{2}{7}$
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Question 542 Marks
Write each fraction. Arrange them in ascending and descending order using correct sign '<', '=', '>' between the fractions:

Answer
Ascending order:

Descending order:

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Question 552 Marks
Solve: $\frac{16}{7}-\frac{5}{7}+\frac{9}{7}$
Answer
The given fractions are: $\frac{16}{7}-\frac{5}{7}+\frac{9}{7}$ $=\frac{16-5+9}{7}$ $=\frac{20}{7}$ Hence the answer is $\frac{20}{7}$
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Question 562 Marks
Write each fraction. Arrange them in ascending and descending order using correct sign $'<', '=', '>'$ between the fractions:
Answer
Ascending order:
Descending order:
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Question 572 Marks
Check whether the given fractions are equivalent:$\frac{2}{7},\frac{16}{42}$
Answer
$\frac{2}{7}\times\frac{8}{8}=\frac{16}{56}$ Hence, the given fraction are not equivalent.
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Question 582 Marks
Solve: $\frac{4}{13}+\frac{2}{13}+\frac{1}{13}$
Answer
The given fractions are: $\frac{4}{13}+\frac{2}{13}+\frac{1}{13}$ $=\frac{4+2+1}{13}$ $=\frac{7}{13}$ Hence the answer is $\frac{7}{13}$
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Question 592 Marks
The following fractions represent just three different numbers. Separate them in to three groups of equal fractions by changing to its simplest form: $\frac{12}{75}$
Answer
$\frac{12}{75}$
$HCF$ of $12\ \&\ 75$ is $3$ Divide both the numerator & denominator by the $HCF$ of $12\ \&\ 75$
$\frac{12\div3}{75\div3}=\frac{4}{25}$
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Question 602 Marks
Solve:
$2\frac{1}{3}-1\frac{2}{3}+4\frac{1}{3}$
Answer
The given fractions are:
$2\frac{1}{3}-1\frac{2}{3}+4\frac{1}{3}=\frac{7}{3}-\frac{5}{3}+\frac{13}{3}$
$=\frac{7-5+13}{3}$
$=\frac{15}{3}=5$
Hence the answer is $5$
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Question 612 Marks
Reduce $\frac{84}{98}$ to its lowest terms.
Answer
$\frac{84}{98}=\frac{84\div2}{98\div2}$ $=\frac{42}{49}$ $=\frac{42\div7}{49\div7}$ $=\frac{6}{7}$ Hence, the lowest term of $\frac{84}{98}$ is $\frac{6}{7}.$
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Question 622 Marks
Find the equivalent fraction of $\frac{3}{5}$, having:Denominator $40$
Answer
Consider the denominator $= 40$
$\frac{3}{5}=\frac{....}{40}$
As $5 \times 8 = 40,$ we will multiply both the numerator & denominator by $8,$ we have
$\Rightarrow\frac{3}{5}\times\frac{8}{8}=\frac{24}{40}$
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Question 632 Marks
The following fractions represent just three different numbers. Separate them in to three groups of equal fractions by changing to its simplest form: $\frac{4}{25}$
Answer
$\frac{4}{25}$
$HCF$ of $4\ \&\ 25$ is $1$ Divide both the numerator & denominator by the $HCF$ of $4\ \&\ 25$
$\frac{4\div1}{25\div1}=\frac{4}{25}$
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Question 642 Marks
Find the fraction equivalent of $\frac{35}{42}$, having:Denominator $18$
Answer
Firstly, we will reduce $\frac{35}{42}$ into the lowest term.
Now, we will divide both the numerator & denominator by the $HCFs$ of $35$ & $42.$
$\Rightarrow\frac{35\div7}{42\div7}=\frac{5}{6}$
$\frac{5}{6}=\frac{}{18}$
Consider the denominator $= 18$
As $6 × 3 = 18$, we will multiply both the numerator & denominator by $3.$
$\Rightarrow\frac{5\ \times\ 3}{6\ \times\ 3}=\frac{15}{18}$
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