MATHS M.C.Q. [1 Marks Each]

On observing all the options by using a number line, we get that there is only one pair $(-3, -5)$ in which the first integer is not on the left of the other integer.

Greatest $- 8$ digit no $99999999$
Smallest $- 9$ digit no $+ 100000000​$
$199999999​$

If a is an integer, then $a + 0 = 0 + a = a$
Here, $0$ is the additive identity element in the set of integers.
Hence, the correct option is $(c).$

$(+48) + (-53) = 53 − 48 = −5$

$36\div(-9)$
$=\frac{36}{-9}$
$= \frac{36}{9}\times(−1)$
$= -1 \times 4$
$= -4$

The integers lying between $-10$ and $-15$ are$-11, -12, -13$ and $-14.$
The greatest integer among these is $-11.$
with negative sign, smaller number is greater.

We have:$-6 - (-9)$
$= -6 + 9$
$= 3$

Here,$L.H.S. = (-13 + 6)$
$= -7$
$R.H.S. = -25 - (-9)$
$= -25 + 9$
$= -16$
$-7 > -16$
$L.H.S. > R.H.S.$

$(-9) \times 6 + (-9) \times 4$
Using distributive law:$(-9) \times (6 + 4)$
$= (-9) \times (10)$
$= -90$

$(-20) \times (-2) \times (-5) (-35)$
$\Rightarrow 40 \times (−35) [ (-) (-) = (+), (-) \times (+) = (-) ]$
$\Rightarrow -1400$

$6$ more than $-7 = (-7) + 6$
$= -( 7 - 6)$
$= -1$
Hence, the correct option is $(b).$

If x is negative integer, then $|x| = -x$
Here, a is greater than $7$, so $7$ - a is negative.
Therefore, $|7 - a| = -(7 - a) = -7 + a = a - 7$
Hence, the correct option is $(a).$

The successor of $-89$ is ​$-88$. The successor of a number lies towards its right on a number line.
$88$ lies to the right of $-89.$

Every integer less than $0$ has the negative $(-)$ sign.
Note: An integer is positive, if it is greater than zero and negative, if it is less than zero.

Here, the operation $\Delta$ is defined as $\text{a }\Delta\text{ b}=\text{a}-\text{b}-2$.
$7\ \Delta\ (-4)=7-(-4)-2$
$=7+4-2$
$=11-2=9$
Hence, the correct option is $(c).$

Temperature is decreased by $20$.
From the reference level, increase in temperature = +ve and decrease in temperature = −ve.
$\Rightarrow $ Temperature is represented as $−20.$

$x + (-8) = 12$
$\Rightarrow x - 8 = 12$
$\Rightarrow x = 12 + 8$
$\Rightarrow x = 20$

The integers lying between $-1$ and $1$ is $0$, so there is only one integer.

Let $x$ be the other integer$x + 8 = -13$
$x = -13 - 8$
$x = -21$

$-1$ is greatest negative integer.

$0$ is grater than every negativenegative integer.

We know that, one less than a given number, gives a predecessor. Predecessor of the integer $-1 = -1 -1 = -2$ Hence, predecessor of the integer $-1$ is $-2.$

Positive numbers are located above $0$ and negative numbers are located below $0$ on a vertical number line.

Here, $5$ less than $-2 = (-2) - (5) = -2 - 5 = -7.$
Hence, the correct option is $(c).$

Positive numbers are located above $0$ and negative numbers are located below $0$ on a vertical number line.

If a is an integer, then its additive inverse is $- a.$
So, additive inverse of $17 = -17$
Hence, the correct option is $(a).$

Let the number be $x$.Then according to the problem we get, $x + 18 = -34$ or, $x = -34 -18$ or, $x = -52.$

The required number is $(-34) - 18$
Now,
$(-34) - 18 = -(34 + 18)$
$= -52$
Hence, the correct option is $(b).$

$(-7) + (-9) + 12 + (-16)$
$= -7 - 9 + 12 - 16$
$= -20$