Questions

M.C.Q. [1 Marks Each]

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8 questions · timed · auto-graded

MCQ 11 Mark
Mark $(\checkmark)$ against the correct answer in the following: If $\frac{1}{3}\text{x}+5=8,$ then $\text{x}={}?$
  • A
    $3$
  • B
    $6$
  • $9$
  • D
    $12$
Answer
Correct option: C.
$9$
$\Rightarrow\frac{1}{3}\text{x}+5=8$
$\Rightarrow\frac{1}{3}\text{x}+5-5=8-5$ [Substracting $5$ from both sides]
$\Rightarrow\frac{1}{3}\text{x}\times3=3\times3$ [Multiplying both sides by $3]$
$\text{x}=9$
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MCQ 21 Mark
Mark $(\checkmark)$ against the correct answer in the following: if $\frac{\text{x}}{5}=1,$ then,
  • A
    $\text{x}=\frac{1}{5}$
  • $x = 5$
  • C
    $x = (5 + 1)$
  • D
    None of these
Answer
Correct option: B.
$x = 5$
$\frac{\text{x}}{5}=1$
$\Rightarrow\frac{\text{x}}{5}\times5=1\times5$ [Multiplying both the side by $5]$
$x = 5$
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MCQ 31 Mark
Mark $(\checkmark)$ against the correct answer in the following: The coefficient of $x$ in $-5xyz$ is:
  • A
    $-5$
  • B
    $5yz$
  • $-5yz$
  • D
    $yz$
Answer
Correct option: C.
$-5yz$
All the terms in the expression $-5xyz$ barring $x$ will be the coefficient of$ x$, i.e.$ -5yz.$
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MCQ 41 Mark
Mark $(\checkmark)$ against the correct answer in the following: $\frac{1}{3}(\text{x}+7+\text{z})$ is a:
  • A
    Monomial
  • B
    Binomial
  • Trinomial
  • D
    Quadrinomial
Answer
Correct option: C.
Trinomial
Since it contains three variables, i.e. $x, y$ and $z,$ it is a trinomial.
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MCQ 51 Mark
Mark $(\checkmark)$ against the correct answer in the following: If $x = 1, y = 2$ and $z = 3$ then $(x^2+ y^2+ z^2) =$ ?
  • A
    $6$
  • B
    $12$
  • $14$
  • D
    $15$
Answer
Correct option: C.
$14$
Substituting $x = 1, y = 2$ and $z = 3 $ in $(x^2+ y^2+ z^2)$:
$\Rightarrow (1)^2+ (2)^2+ (3)^2$
$\Rightarrow 1 + 4 + 9 = 14$
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MCQ 61 Mark
Mark $(\checkmark)$ against the correct answer in the following: By how much does I exceed $2x - 3y - 4?$
  • A
    $2x - 3y - 5$
  • B
    $2x - 3y - 3$
  • $5 - 2x + 3y$
  • D
    None of these
Answer
Correct option: C.
$5 - 2x + 3y$
$1$ exceeds $2x - 3y - 4.$
$\therefore$ $1 - (2x - 3y - 4) = 1 - 2x + 3y + 4$
$= 5 - 2x + 3y$
$\therefore$ $1$ exceeds $2x - 3y - 4$ by $5 - 2x + 3y$
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MCQ 71 Mark
Mark $(\checkmark)$ against the correct answer in the following: What must be added to $5 x^3-2 x^2+6 x+7$ to make the sum $x^3+3 x^2-x+1$ ?
  • A
    $4 x^3-5 x^2+7 x+6$
  • $-4 x^3+5 x^2-7 x-6$
  • C
    $4 x^3+5 x^2-7 x+6$
  • D
    None of these
Answer
Correct option: B.
$-4 x^3+5 x^2-7 x-6$
In order to find what must be added, we subtract $\left(5 x^3-2 x^2+6 x+7\right)$ from $\left(x^3+3 x^2-x+1\right)$
$ \Rightarrow\left(x^3+3 x^2-x+1\right)-\left(5 x^3-2 x^2+6 x+7\right)$
$\Rightarrow x^3+3 x^2-x+1-5 x^3+2 x^2-6 x-7$
$ \Rightarrow x^3-5 x^3+3 x^2+2 x^2-x-6 x+1-7$
$\Rightarrow -4 x^3+5 x^2-7 x-6$
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MCQ 81 Mark
Mark $(\checkmark)$ against the correct answer in the following: $2x - [3y - {2x - (y - x)}] = ?$
  • $5x - 4y$
  • B
    $4y - 5x$
  • C
    $5y - 4x$
  • D
    $4x - 5y$
Answer
Correct option: A.
$5x - 4y$
$2x - [3y - {2x - (y - x)}]$
$= 2x - [3y - {2x - y + x}]$
$= 2x - [3y - {3x - y}]$
$= 2x - [3y - 3x + y]$
$= 2x - [4y - 3x]$
$= 2x - 4y + 3x$
$= 5x - 4y$
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