Questions · Page 3 of 5

M.C.Q. [1 Marks Each]

MCQ 1011 Mark
Find the ratio of $Rs. 5$ to $50$ paise.
  • $10 : 1$ paise
  • B
    $100 : 1$ paise
  • C
    $20 : 1$ paise
  • D
    None of these
Answer
Correct option: A.
$10 : 1$ paise
$a)$ $RS. 5$ to $50$ paise
$1Rs = 100$ paise
$\frac{\text{Rs 5}}{50 \text{ paise}}=\frac{500 \text{ paise}}{50 \text{ paise}}=10:1 \text{ paise}$
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MCQ 1021 Mark
The perimeter of a triangle field is $144m$ and the ratio of the sides is $3 : 4 : 5.$ The area of the field is.
  • $864m^2$
  • B
    $468m^2$
  • C
    $824m^2$
  • D
    None
Answer
Correct option: A.
$864m^2$
Let the sides of triangle are $3x, 4x, 5x$ Then perimeter of
triangle $= 3x + 4x + 5x = 12x$ But peri meter is $144$
$\therefore $ $12x = 144 = 12$
So length are $36m, 48m, 60 ms$
$=\frac{36+48+60}{2}=72$
then area of triangle
$=\sqrt{72(72-36)(72-48)(72-60)}$
$=\sqrt{72\times36\times24\times12}=\sqrt{746469}=864\text{m}^2$
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MCQ 1031 Mark
Mark $(\checkmark)$ against the correct answer in the following.
Choose the correct statement:
  • A
    $(5 : 8) > (3 : 4)$
  • $(5 : 8) < (3 : 4)$
  • C
    Two ratios cannot be compared.
Answer
Correct option: B.
$(5 : 8) < (3 : 4)$
$\frac{5}{8}<\frac{3}{4}$
$\Rightarrow4\times5<3\times8$
$\Rightarrow20<24$
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MCQ 1041 Mark
The angles of a triangle are in the ratio $1 : 2 : 3$. The measure of the largest angle is:
  • A
    $30^\circ $
  • B
    $60^\circ$
  • $90^\circ$
  • D
    $120^\circ$
Answer
Correct option: C.
$90^\circ$
Let $x$ stand for the measure of angle $1$.
Then $2x$ for angle $2$ and finally $3x$ for angle $3$.
So, $x + 2x + 3x = 180$ and $6x = 180$
Therefore, $x = 30, 2x = 60$ and $3x = 90$
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MCQ 1051 Mark
The sides of a triangle are in the ratio $2 : 3 : 5$. If its perimeter is $100\ cm$, the length of its smallest side is:
  • A
    $2\ cm$
  • $20\ cm$
  • C
    $3\ cm$
  • D
    $5\ cm$
Answer
Correct option: B.
$20\ cm$
We have,
$= 2x + 3x + 5x = 100$
$= 10x = 100$
$= x = 10$
Now,
Length of the smallest side $= 2 \times 10 = 20$
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MCQ 1061 Mark
Ratio symbol is ..........and is read as ..........
  • $:,$ is to
  • B
    $::,$ equal to
  • C
    $=,$ equal to
  • D
    None
Answer
Correct option: A.
$:,$ is to

Ratio symbol is : and is read as is to.

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MCQ 1071 Mark
If $12 : 3 :: x : 1$ then the value of $x$ is.
  • A
    $\frac{1}{4}$
  • B
    $1$
  • $4$
  • D
    $5$
Answer
Correct option: C.
$4$
$12 : 3 :: x : 1$
$3x = 12$
$\text{x}=\frac{12}{3}=4$
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MCQ 1081 Mark
$5$ out of $2250$ parts of the earth is sulphur. What is the percentage of sulphur in the earth?
  • $\frac{2}{9}\%$
  • B
    $\frac{1}{9}\%$
  • C
    $\frac{2}{5}\%$
  • D
    $\frac{3}{7}\%$
Answer
Correct option: A.
$\frac{2}{9}\%$
$\%\text{ of sulphur}=\frac{5}{2250}\times100=\frac{2}{9}\%$
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MCQ 1091 Mark
Ratio is a method of comparing twoquantities by.
  • A
    Addition
  • B
    Subtraction
  • Division
  • D
    None
Answer
Correct option: C.
Division

Ratio is a method of comparing two quantities by Division.

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MCQ 1101 Mark
Find the ratio of $5\ cm$ to $10m.$
  • A
    $\frac{1}{2}$
  • B
    $\frac{1}{20}$
  • $\frac{1}{200}$
  • D
    $\frac{1}{2000}$
Answer
Correct option: C.
$\frac{1}{200}$

Since, $1m = 100\ cm$
Required ratio $=\frac{5}{10}\times100=\frac{1}{200}$

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MCQ 1111 Mark
Mark the correct alternative in the following:
If six men can do a piece of work in $6$ days, then $3$ men can do same work in,
  • A
    $10$ days.
  • $12$ days.
  • C
    $15$ days.
  • D
    $18$ days.
Answer
Correct option: B.
$12$ days.
Let the required number of days be $x$.
Number of days is inversaly proportional to the number of men.
According to the question,
$6 : 3 : : x : 6$
$\Rightarrow\frac{6}{3}=\frac{\text{x}}{6}$
$\Rightarrow\frac{6\times6}{3}=\frac{\text{x}\times6}{6}$
$\Rightarrow\frac{36}{3}=\text{x}$
$\Rightarrow\text{x}=12$
Thus, $3$ men can do same work in $12$ days.
Hence, the correct option is $(b)$.
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MCQ 1121 Mark
Mark $(\checkmark)$ against the correct answer in the following.
A rail journey of $75\ km$ costs $Rs. 215$. How much will a journey of $120\ km$ cost?
  • $Rs. 344$
  • B
    $Rs. 324$
  • C
    $Rs. 268.75$
  • D
    None of these
Answer
Correct option: A.
$Rs. 344$
Journey of $75\ km$ costs $= Rs\ 215$
Cost of $1\ km$ $=\text{Rs. }\frac{215}{75}$
And cost for $120$ for $=\text{Rs. }\frac{215\times120}{75}$
$=\text{Rs. }344$
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MCQ 1131 Mark
Mark $(\checkmark)$ against the correct answer in the following.
The sides of a triangle are in the ratio $1 : 3 : 5$ and its perimeter is $90\ cm$, the length of its largest side is:
  • A
    $40\ cm$
  • $50\ cm$
  • C
    $36\ cm$
  • D
    $54\ cm$
Answer
Correct option: B.
$50\ cm$

$\text{largest}=\frac{90\times5}{1+3+5}$
$=\frac{90\times5}{9}$
$=50\text{cm}$

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MCQ 1141 Mark
The ratio of $2m$ to $150\ cm$ is.
  • A
    $3 : 4$
  • $4 : 3$
  • C
    $1 : 4$
  • D
    $4 : 1$
Answer
Correct option: B.
$4 : 3$
$1m = 100\ cm$
$2m = 200\ cm$
$\text{ratio}=\frac{200}{150}=4:3$
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MCQ 1151 Mark
Present ages of Sameer and Anand are in the ratio of $5 : 4$ respectively. Three years hence, the ratio of their ages will become $11 : 9$ respectively. What is Anands present age in years?
  • $24$
  • B
    $27$
  • C
    $40$
  • D
    Cannot be determined
Answer
Correct option: A.
$24$
Let the present ages of Sameer and Anand be $5x$ years and $4x$ years respectively
Then, $\frac{5\text{x}+3}{4}=\frac{11}{9}$
$\Rightarrow 9(5x + 3) = 11(4x + 3)$
$\Rightarrow 45x + 27 = 44x + 33$
$\Rightarrow 45x - 44x = 33 - 27$
$\Rightarrow x = 6$
$\therefore$ Anands present age $= 4x = 24$ years.
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MCQ 1161 Mark
Mark $(\checkmark)$ against the correct answer in the following:
If $4 : 5 : : x : 45$, then the value of $x$ is:
  • A
    $54$
  • B
    $60$
  • $36$
  • D
    $30$
Answer
Correct option: C.
$36$
Given:
$4 : 5 :: x : 45$
We know:
Product of mean = Product of extremes
$5x = 4 ​\times 45$
$\text{x}=\frac{180}{5}=36$
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MCQ 1171 Mark
There are $‘b’$ boys and $‘g’$ girls in a class. The ratio of the number of boys to the total number of students in the class is:
  • $\frac{\text{b}}{\text{(b + g)}}$
  • B
    $\frac{\text{g}}{\text{(b+g)}}$
  • C
    $\frac{\text{b}}{\text{g}}$
  • D
    $\frac{\text{(b+g)}}{\text{g}}$
Answer
Correct option: A.
$\frac{\text{b}}{\text{(b + g)}}$
Given,
Number of boys in the class $= b$ and number of girls in the class $= g$
$\therefore$ Total number of students = Number of boys + Number of girls $= b + g$
Ratio of boys to the total number of students $= b : b + g$
$=\frac{\text{b}}{\text{(b+g)}} $
Hence, $(a)$ is the correct option.
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MCQ 1181 Mark
Length and width of a field are in the ratio $5 : 3$. If the width of the field is $42m$, then its length is:
  • A
    $50m$
  • $70m$
  • C
    $80m$
  • D
    $100m$
Answer
Correct option: B.
$70m$
Ratio of length and width of the field $= 5 : 3$
Let the length be $xm$.
$\because$ Width $= 42m$
$\therefore$ Length $= 5 : 3 = x : 42$
$\Rightarrow\text{x}=\frac{5}{3\times42}=70\text{m}$
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MCQ 1191 Mark
Mark the correct alternative in the following:
If $x : y = 1 : 1$, then $\frac{3\text{x}+4\text{y}}{5\text{x}+6\text{y}}=$
  • $\frac{7}{11}$
  • B
    $\frac{17}{11}$
  • C
    $\frac{17}{23}$
  • D
    $\frac{4}{5}$
Answer
Correct option: A.
$\frac{7}{11}$

It is given that,
$\frac{\text{x}}{\text{y}}=\frac{1}{1}=1\ ....(1)$
Now,
$\frac{3\text{x}+4\text{y}}{5\text{x}+6\text{y}}=\frac{(3\text{x}+4\text{y}\div\text{y})}{(5\text{x}+6\text{y})\div\text{y}}$
$=\frac{3\big(\frac{\text{x}}{\text{y}}\big)+4}{5\big(\frac{\text{x}}{\text{y}}\big)+6}$
$=\frac{3(1)+4}{5(1)+6}\ [\text{From (1)}]$
$=\frac{3+4}{5+6}$
$=\frac{7}{11}$
Hence, the correct option is $(a)$.

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MCQ 1201 Mark
If $A, B, C,$ divide $Rs. 1200$ in the ratio $2 : 3 : 5,$ then $B's$ share is:
  • A
    $Rs. 240$
  • B
    $Rs. 600$
  • C
    $Rs. 380$
  • $Rs. 360$
Answer
Correct option: D.
$Rs. 360$
$= 2x + 3x + 5x = 1200$
$= 10x = 1200$
$x = 120$
B's share $= 3x$
$= 3 \times 120 = 360$
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MCQ 1211 Mark
At present, the ratio between the ages of Arun and Deepak is $4 : 3$. After $6$ years, Aruns age will be $26$ years. What is the age of Deepak at present?
  • A
    $12$ years
  • $15$ years
  • C
    $19$ and half
  • D
    $21$ years
Answer
Correct option: B.
$15$ years
Let the present ages of Arun and Deepak be $4x$ years and $3x$ years respectively.
Then,
$4x + 6 = 26 ⇔ 4x = 20$
$x = 5$
$\therefore$ Deepaks age $= 3x = 15$ years
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MCQ 1221 Mark
Mark $(\checkmark)$ against the correct answer in the following.
In covering $111\ km$, a car consumes $6L$ of petrol. How many kilometres will it go in $10L$ of petrol?
  • A
    $172\ km$
  • $185\ km$
  • C
    $205\ km$
  • D
    $266.4\ km$
Answer
Correct option: B.
$185\ km$
In $6L$ of petrol, a car covers $= 111\ km$
In $1L$, it will cover $=\frac{111}{6}\text{km}$
And in 10L it will cover $=\frac{111\times10}{6}\text{km}$
$=185\text{km}$
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MCQ 1231 Mark
In a class there are $50$ boys and $30$ girls. The ratio of the number of boys to the number of girls in the class is:
  • A
    $\frac{80}{50}$
  • B
    $\frac{3}{5}$
  • $\frac{5}{3}$
  • D
    $\text{None}$
Answer
Correct option: C.
$\frac{5}{3}$
The number of boys $= 50$ and girls $= 30$
$\text{Ratio}=\frac{50}{30}$
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MCQ 1241 Mark
Mathematics textbook for class $VI$ has $320$ pages. The chapter ‘symmetry’ runs from page $261$ to page $272$. The ratio of the number of pages of this chapter to the total number of pages of the book is:
  • A
    $11 : 320$
  • B
    $3 : 40$
  • $3 : 80$
  • D
    $272 : 320$
Answer
Correct option: C.
$3 : 80$
Given,
Mathematics textbook for class $VI$ has pages $= 320$.
The chapter symmetry runs from page $261$ to page $272$.
$\therefore$ Number of pages of chapter ‘symmetry’ $= 272 - 260 = 12$
Ratio of the number of pages of chapter ‘symmetry’ to the total number of pages $=\frac{12}{320} $
$=\frac{3}{80}$ [On dividing numerator and denominator by $4$]
$= 3 : 80$
Hence, $(c)$ is the correct option.
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MCQ 1251 Mark
A ratio equivalent of $2 : 3$ is:
  • A
    $4 : 3$
  • B
    $2 : 6$
  • $6 : 9$
  • D
    $10 : 9$
Answer
Correct option: C.
$6 : 9$
$2 : 3$ is equivalent to $6 : 9$ (Dividing by $3$).
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MCQ 1261 Mark
If the cost of $5$ bars of a soap is $Rs. 30$, then the cost of one dozen bars is:
  • A
    $Rs. 60$
  • B
    $Rs. 120$
  • $Rs. 72$
  • D
    $ Rs. 140$
Answer
Correct option: C.
$Rs. 72$

Let the cost of one dozen bars be $Rs. x$
$\therefore$​ $30 : 5 = x : 12$
$\Rightarrow\text{x}=\frac{30}{5\times12}=\text{Rs. 72}$
Cost of one dozen $(12)$ bars $= Rs. 72$

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MCQ 1271 Mark
Mark $(\checkmark)$ against the correct answer in the following:
The first three terms of a proportion are $12, 21$ and $8$ respectively. The $4th$ term is:
  • A
    $18$
  • B
    $16$
  • $14$
  • D
    $20$
Answer
Correct option: C.
$14$
Let the $4th$ term be $x$, such that we have:
$12 : 21 :: 8 : x$
Now, we know:
Product of extremes = Product of means
$12x = 21 \times 8$
$\text{x}=\frac{128}{12}=14$
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MCQ 1281 Mark
The ratio of $Rs. 1$ to $60$ paise is
  • A
    $5 : 4$
  • B
    $5 : 2$
  • $5 : 3$
  • D
    None
Answer
Correct option: C.
$5 : 3$
$Re\ 1 = 100$ paise
$\therefore$ Ratio of $Rs. 1$ to $60$ paise $= 100$ paise : $60$ paise $= 5 : 3$
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MCQ 1291 Mark
Mark $(\checkmark)$ against the correct answer in the following:
A car travels $288\ km$ is $4$ hours and a train travels $540\ km$ in $6$ hours. The ratio of their speeds is:
  • A
    $5 : 4$
  • $4 : 5$
  • C
    $5 : 6$
  • D
    $3 : 5$
Answer
Correct option: B.
$4 : 5$
Speed of the car $=\frac{\text{Distance}}{\text{Time }}=\frac{288\text{km}}{4\text{ hour}}=72\text{km}/\text{hr}$
Speed of the train $=\frac{\text{Distance}}{\text{Time }}=\frac{540\text{km}}{6\text{ hour}}=90\text{km}/\text{hr}$
Ratio of their speeds $= 72:90$
where, $\frac{72}{90}=\frac{72\div18}{90\div18}=\frac{4}{5}$
$(H.C.F$ of $72$ and $90$ is $18)$
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MCQ 1301 Mark
The length and width of a tape are $2m$ and $28\ cm$. Write their ratio.
  • A
    $\frac{100}{14}$
  • B
    $\frac{7}{50}$
  • $\frac{50}{7}$
  • D
    $\frac{1}{8}$
Answer
Correct option: C.
$\frac{50}{7}$
Length (in cm) $200$ Width (in cm)
$=28\text{ Ratio}=\frac{200}{28}=\frac{50}{7}\text{ or }50:7$
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MCQ 1311 Mark
The ratio of the number of sides of a square to the number of edges of a cube is:
  • A
    $1 : 2$
  • B
    $3 : 2$
  • C
    $4 : 1$
  • $1 : 3$
Answer
Correct option: D.
$1 : 3$
Number of sides in a square $=4$ Number of edges in a cube $= 12$
Ratio of the number of sides of a square to number of edges $=\frac{4}{12}$
$=\frac{1}{3} =1:3$ [On dividing numerator and denominator by $4$]
Hence, $(d)$ is the correct option.
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MCQ 1321 Mark
In a football match the ratio of total number of players of both the teams to the number of referees is.
  • A
    $10 : 2$
  • B
    $11 : 2$
  • C
    $22 : 2$
  • $22 : 1$
Answer
Correct option: D.
$22 : 1$
Number of players of both the teams playing on the ground in football match $= 11 + 11 = 22$
Referies $= 1$
$22 : 1$
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MCQ 1331 Mark
A picture is $60\ cm$ wide and $1.8m$ long. The ratio of its width to its perimeter in lowest form is:
  • A
    $1 : 2$
  • B
    $1 : 3$
  • C
    $1 : 4$
  • $1 : 8$
Answer
Correct option: D.
$1 : 8$
Given,
Width of picture $(b) = 60\ cm$
Length of picture $(l) = 1.8m$
$= (1.8\times 100)\ cm$
$=\frac{18}{10}\times 100= 180\text{cm}$
Perimeter of picture $= 2 \times (1 + b)$
$= 2 \times (180 + 60)\ cm$
$= (2 \times 240)cm= 480\ cm$
Ratio of width to its perimeter $=\frac{60}{480}$
$=1$ [On dividing numerator and denominator by $60$]
$=1 : 8$
Hence, $(d)$ is the correct option.
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MCQ 1341 Mark
Find the ratio : $150$ to $175$
  • A
    $30 : 35$
  • B
    $6 : 7$
  • C
    Neither of above
  • Both $A$ and $B$ are correct
Answer
Correct option: D.
Both $A$ and $B$ are correct
The ratio is $=\frac{150}{175}$
Divide the numerator and denominator by $5$, the ratio becomes $\frac{30}{35}$
Again, Divide the numerator and denominator by $5,\frac{6}{7}$
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MCQ 1351 Mark
Nisha made $16.5L$ of rose drink for a Childrens Funfair. Sakshi made $3.5L$ more rose drink than Nisha. At the end of the day,
Sakshi had sold $\frac{3}{4}$ of her rose drink. Also, Sakshi had twice as much rose drink as Nisha had left. How much rose drink did Nisha sell?
  • $14L$
  • B
    $14.5L$
  • C
    $18L$
  • D
    $18.3L$
Answer
Correct option: A.
$14L$
Quantity of rose drink Nisha made $= 16.5L$
Quantity of rose drink Sakshi made $= (3.5 + 16.5)L = 20L$
Quantity of rose drink Sakshi sold
$\frac{3}{4}\times20=15\text{L}$
$\therefore$ Quantity of rose drink left with Sakshi
$= (20 - 15)L = 5L$
So, quantity of rose drink left with Nisha
$=\frac{5}{2}\text{L}=2.5\text{L}$
$\therefore$ Quantity of rose drink Nisha sold
$= (16.5 - 2.5)L = 14L.$
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MCQ 1361 Mark
If $\bigg(\text{x}+\frac{1}{\text{x}}\bigg):\bigg(\text{x}-\frac{1}{\text{x}}\bigg)=5:4$ then the value of $x$ is.
  • A
    $0$
  • B
    $\pm1$
  • C
    $\pm2$
  • $\pm3$
Answer
Correct option: D.
$\pm3$

$\big(\text{x}+\frac{1}{\text{x}}\big):\big(\text{x}-\frac{1}{\text{x}}\big)::5:4$
$\Rightarrow\frac{(\text{x}+\frac{1}{\text{x}})}{(\text{x}-\frac{1}{\text{x}})}=\frac{5}{4}$
$\Rightarrow\frac{\text{x}+\frac{1}{\text{x}}}{\text{x}+\frac{1}{\text{x}}}=\frac{5}{4}$
$5\text{x}^2-5=4\text{x}^2+4$
$\Rightarrow\text{x}^2=9\Rightarrow\text{x}=\pm3$

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MCQ 1371 Mark
Ravi and Kavi start a business by investing $Rs. 8000$ and $Rs. 72000$ respectively. Find the ratio of their profits at the end of year.
  • A
    $2 : 9$
  • B
    $5 : 9$
  • C
    $7 : 9$
  • $1 : 9$
Answer
Correct option: D.
$1 : 9$
Their profits must be divided in the ratio of their investment .
So, Ravis profit : Kavis profit $= 8000 : 72000 = 1 : 9$
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MCQ 1381 Mark
In the word $COMPARISON$, the ratio of number of consonants to the number of vowels is ___________.
  • A
    $4 : 7$
  • B
    $7 : 4$
  • $6 : 4$
  • D
    $4 : 6$
Answer
Correct option: C.
$6 : 4$
Number of consonants in the given word $= 6$
Number of vowels in the given word $= 4$
$\therefore$ Required ratio $= 6 : 4$
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MCQ 1391 Mark
If $(a + b) : (b + c) : (c + a) = 6 : 7 : 8$ and $a + b + c = 14$, then find the value of $c$.
  • $6$
  • B
    $8$
  • C
    $14$
  • D
    $7$
Answer
Correct option: A.
$6$
$\frac{\text{a + b}}{\text{b + c}}=\frac{6}{7}=\frac{\text{b + c}}{\text{c + a}}=\frac{7}{8}$
$\Rightarrow 7a + 7b = 6b + 6c$
$\Rightarrow 8b + 8c = 7c + 7a$
$\Rightarrow 7a + b = 6c \rightarrow 1$
$\Rightarrow 8b + c = 7a \rightarrow 2$
Putting $2$ in $1$
$\Rightarrow 8b + c + b = 6c$
$\Rightarrow\frac{9\text{b}}{5}=\text{c}$
$\therefore\text{b}=\frac{5\text{c}}{9}$
$a + b + c = 14$
$\Rightarrow\frac{\text{8b}+\text{c}}{7}+\text{b + c}=14$
$\Rightarrow\frac{8\times\frac{5\text{c}}{9}+\text{c}}{7}+\frac{5\text{c}}{9}+\text{c}=14$
Solving we get $c = 6$
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MCQ 1401 Mark
In a box, the ratio of red marbles to blue marbles is $7 : 4$. Which of the following could be the total number of marbles in the box?
  • A
    $18$
  • B
    $19$
  • C
    $21$
  • $22$
Answer
Correct option: D.
$22$
Given,
The ratio of red marbles to blue marbles $= 7 : 4$
Let the number of red marbles $= 7x$
and blue marbles $= 4x$
Then, total number of marbles $= 7x + 4x$
$= 11x$
Total number of marbles must be multiple of $11$.
By observation,
$\therefore$ $11x =22$
$\Rightarrow 11x = 11 \times 2$
Hence, $(d)$ is the correct option.
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MCQ 1411 Mark
Mark $(\checkmark)$ against the correct answer in the following.
If $Rs. 760$ is divided between $A$ and $B$ in the ratio $8 : 11,$ then $B’s$ share is:
  • $Rs. 440$
  • B
    $Rs. 320$
  • C
    $Rs. 430$
  • D
    $Rs. 330$
Answer
Correct option: A.
$Rs. 440$

Total amount $= Rs\ 760$
Ratio $A : B = 8 : 11$
$\therefore\text{B}'\text{s}\text{ share}=\frac{760\times11}{8+11}$
$=\frac{760\times11}{19}$
$=\text{Rs. }440$

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MCQ 1421 Mark
Ratio is a method of comparing two quantities by _____ .
  • A
    Addition
  • B
    Substraction
  • Division
  • D
    Multiplication
Answer
Correct option: C.
Division

$\Rightarrow $ Ratio is a method of comparing two quantities by Division.
$\Rightarrow $ A common way to express a ratio is as a fraction in simplest form.
$\Rightarrow $ A ratio is a comparison of two similar quantities obtained by dividing one quantity by the other.

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MCQ 1431 Mark
Mark the correct alternative in the following:
If $x : y = 2 : 3$ and $y : z = 2 : 3$, then $x : x =$
  • A
    $2 : 3$
  • B
    $3 : 4$
  • C
    $5 : 7$
  • $4 : 9$
Answer
Correct option: D.
$4 : 9$
It is given that,
$\frac{\text{x}}{\text{y}}=\frac{2}{3}\ ....(1)$
and
$\frac{\text{y}}{\text{z}}=\frac{2}{3}\ ....(2)$
Now,
$\frac{\text{x}}{\text{y}}=\frac{2}{3}$
$\Rightarrow\frac{\text{x}}{\text{y}}\times\frac{\text{y}}{\text{z}}=\frac{2}{3}\times\frac{\text{y}}{\text{z}}\ [\text{From (2)}]$
$\Rightarrow\frac{\text{x}}{\text{z}}=\frac{4}{9}$
$\Rightarrow\text{x}:\text{z}=4:9$
Hence, the correct option is $(d)$.
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MCQ 1441 Mark
If $a, b, c,$ are in proportion, then
  • A
    $a^2 = bc$
  • $b^2= ac$
  • C
    $c^2 = ab$
  • D
    None of these.
Answer
Correct option: B.
$b^2= ac$
$\because$ $a, b$ and $d$ are in proportion,
$\therefore$​ $a : b : : c$
$\Rightarrow ab = bc$
$\Rightarrow b2 = ac$
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MCQ 1451 Mark
Two charges of $1+\mu$ are placed $4\ cm$ apart, the ratio of the force exerted by both charges on each other will be.
  • $1 : 1$
  • B
    $1 : 5$
  • C
    $5 : 1$
  • D
    $25 : 1$
Answer
Correct option: A.
$1 : 1$
Since no other force exists so, force on both charges will be equal
Thus, Ratio $= 1 : 1$
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MCQ 1461 Mark
In a school the total number of students are $3200$ out of which $1800$ are boys. Remaining are girls. Ratio of girls to boys is.
  • A
    $\frac{1400}{1800}$
  • B
    $\frac{9}{7}$
  • $\frac{7}{9}$
  • D
    $\frac{1}{3}$
Answer
Correct option: C.
$\frac{7}{9}$

The total number of boys in school $= 1800$
The total number of student $= 3200$
Therefore the total number of girls $= 3200 - 1800 = 1400$
Therefore the ratio of $\frac{\text{girls}}{\text{boys}}=\frac{1400}{1800}$
ratio $= 7 : 9$

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MCQ 1471 Mark
If $As$ income is $20\ %$ more than $B$, then $Bs$ income is.
  • A
    Same as $As$
  • B
    $20\%$ less than $As$
  • $16\frac{2}{3}\%$ less than $As$
  • D
    $15\%$ less than $As$
Answer
Correct option: C.
$16\frac{2}{3}\%$ less than $As$
Let $Bs$ income be $Rs. 100$ $As$ income is be $20\%$ more than $Bs$ income
So $As$ income will be $Rs. 120$ $Bs$ income is $Rs. 20$ less
than $As$ income Percantage of $Bs$ income which is less than $As$ income will be
$\frac{20}{120}\times100=\frac{100}{6}=16\frac{4}{6}=16\frac{2}{3}$
$Bs$ income is $16\frac{2}{3}\%$ less than $As$ income.
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MCQ 1481 Mark
Mala and Bala got $75$ marks and $25$ marks respectively in an examination. The ratio of the marks scored by Mala to the total marks obtained by both of them is.
  • $3 : 4$
  • B
    $3 : 1$
  • C
    $1 : 3$
  • D
    $4 : 3$
Answer
Correct option: A.
$3 : 4$
Let $x$ and $yy$ denote the marks obtained by Mala and Bala
$\therefore$ $x = 75$ and $y = 25y$
Now, total marks $= x + y = 75 + 25 = 100$
$\therefore$ Ratio of Malas marks to that of total marks $= x :$ total marks $= 75 : 100 = 3 : 4$
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MCQ 1491 Mark
Mark $(\checkmark)$ against the correct answer in the following.
If $25 : 35 :: 45 : x$ then the value of $x$ is:
  • $63$
  • B
    $72$
  • C
    $54$
  • D
    None of these.
Answer
Correct option: A.
$63$
$\frac{25}{\text{35}}$
$=\frac{45}{\text{x}}$
$\Rightarrow\text{x}=\frac{45\times35}{25}$
$=9\times7=63$
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MCQ 1501 Mark
Mark $(\checkmark)$ against the correct answer in the following.
The ratio $92 : 115$ in its simplest for is:
  • A
    $23 : 25$
  • B
    $18 : 23$
  • C
    $3 : 5$
  • $4 : 5$
Answer
Correct option: D.
$4 : 5$
$\frac{92}{115}$
$=\frac{92\div23}{115\div23}=\frac{4}{5}\text{ or }4:5$
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