Questions · Page 5 of 5

M.C.Q. [1 Marks Each]

MCQ 2011 Mark
Decimal form of $ \frac{8}{1000}$
  • A
    $0.0008$
  • B
    $1000.9$
  • $0.008$
  • D
    $0.08$
Answer
Correct option: C.
$0.008$
$0.008$
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MCQ 2021 Mark
Mark $(\checkmark)$ against the correct answer in the following:
What should be subtracted from. $1$ to get $0.03?$
  • A
    $0.7$
  • $0.07$
  • C
    $0.007$
  • D
    None of these
Answer
Correct option: B.
$0.07$

$0.1 - 0.03 = 0.10 - 0.03 = 0.07$

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MCQ 2031 Mark
By what number should $1\frac{3}{4}$ be divided to get $2\frac{1}{2}?$
  • A
    $\frac{3}{7}$
  • B
    $1\frac{2}{5}$
  • $\frac{7}{10}$
  • D
    $1\frac{3}{7}$
Answer
Correct option: C.
$\frac{7}{10}$

Let the required number be $x.$
Now,
$1\frac{3}{4}\div\text{x}=2\frac{1}{2}$
$\Rightarrow\frac{7}{4}\times\frac{1}{\text{x}}=\frac{5}{2}$
$\Rightarrow\text{x}=\frac{7}{4}\times\frac{2}{5}$
$\Rightarrow\text{x}=\frac{7\times1}{2\times5}$
$\Rightarrow\text{x}=\frac{7}{10}$
Thus, the required number is $\frac{7}{10}$

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MCQ 2041 Mark
$9\times\Big(-\frac{1}{3}\Big)\times(-3)\times\Big(-\frac{1}{9}\Big)=$
  • A
    $1$
  • $-1$
  • C
    $-3$
  • D
    $3$
Answer
Correct option: B.
$-1$
Since the number of negative terms in the product is odd. Therefore, their product is negative.
$9\times\Big(-\frac{1}{3}\Big)\times(-3)\times\Big(-\frac{1}{9}\Big)$
$=9\times\Big(-\frac{1}{9}\Big)\times\Big(-\frac{1}{3}\Big)\times(-3)$
$=-\Big(9\times\frac{1}{9}\times\frac{1}{3}\times3\Big)$
$=-(1\times1)$
$=-1$
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MCQ 2051 Mark
Example for an improper Fraction is:
  • A
    $ \frac{35}{36}$
  • $ \frac{20}{10}$
  • C
    $ \frac{12}{14}$
  • D
    $ \frac{17}{20}$
Answer
Correct option: B.
$ \frac{20}{10}$
If denominator is less than the Numerator in a fraction, then it is termed as improper fraction.
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MCQ 2061 Mark
What is the multiplication of the numbers $ \text{1}\frac{1}{3}\times \text{3}\frac{1}{4}\times\frac{7}{8}?$
  • A
    $ \text{3}\frac{18}{24}$
  • B
    $ \text{2}\frac{19}{24}$
  • $ \text{3}\frac{19}{24}$
  • D
    $ \text{2}\frac{18}{24}$
Answer
Correct option: C.
$ \text{3}\frac{19}{24}$
Given, $ \text{1}\frac{1}{3}\times\text{3}\frac{1}{4}\times\frac{7}{8}$
$= \frac{4}{3}\times\frac{13}{4}\times\frac{7}{8}$
$= \frac{13}{3}\times\frac{7}{8}$
$= \frac{91}{24}$
$= \text{3}\frac{19}{24}$
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MCQ 2071 Mark
Mark $(\checkmark)$ against the correct answer in the following: By what number should $1\frac{3}{4}$ be divided to get $2\frac{1}{2}?$
  • A
    $\frac{3}{7}$
  • B
    $1\frac{2}{5}$
  • $\frac{7}{10}$
  • D
    $1\frac{3}{7}$
Answer
Correct option: C.
$\frac{7}{10}$
Required number $=1\frac{3}{4}\div2\frac{1}{2}$
$=\frac{7}{4}\div\frac{5}{2}$
$=\frac{7}{4}\times\frac{2}{5}$
$\Big[\because$ Reciprocal of $\frac{2}{5}=\frac{2}{5}\Big]$
$=\frac{7\times1}{2\times5}$
$=\frac{7}{10}$
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MCQ 2081 Mark
On dividing $7 $ by $\frac{2}{5}$, the result is:
  • A
    $\frac{14}{2}$
  • B
    $\frac{35}{4}$
  • C
    $\frac{14}{5}$
  • $\frac{35}{2}$
Answer
Correct option: D.
$\frac{35}{2}$
Given, $7+\frac{2}{5}=7\times\frac{5}{2}=\frac{35}{2}$
$\big[\because$ reciprocal of $\frac{2}{5}=\frac{5}{2}\big]$
Hence, on dividing $7 $ by $ \frac{2}{5}, $ we get $\frac{35}{2}$
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MCQ 2091 Mark
The difference between the greatest and the least fractions out of $\frac{6}{7},\frac{7}{8},\frac{8}{9}$ and $\frac{9}{10}$ is:
  • $\frac{3}{10}$
  • B
    $\frac{1}{56}$
  • C
    $\frac{1}{40}$
  • D
    $\frac{1}{72}$
Answer
Correct option: A.
$\frac{3}{10}$
$\frac{3}{10}$
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