Questions · Page 6 of 6

M.C.Q

MCQ 2511 Mark
Which one of the following is not a measure of central value?
  • A
    Mean
  • B
    Mode
  • C
    Median
  • Range
Answer
Correct option: D.
Range

We know that mean, median and mode are all measures of central tendency.

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MCQ 2521 Mark
$\text{Mode}+\frac{3}{2}(\text{Median - Mode})=$
  • A
    Mode
  • B
    Median
  • C
    None of these
  • Mean
Answer
Correct option: D.
Mean

$3$ Median = $2$ Mean + Mode
$\Rightarrow 3$ Median – Mode = $2$ Mean
$\Rightarrow\text{Mean}=\frac{3}{2}\text{ Median }-\frac{\text{Mode}}{2}$
$\Rightarrow\text{Mean}+\frac{3}{2}\text{ Median }-\frac{\text{Mode}}{2}-\text{Mode = Mean}$
$\Rightarrow\text{Mean}+\frac{3}{2}\text{(Median - }\text{Mode) = Mean}$

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MCQ 2531 Mark
The minimum value of a data is $82$ and range is $38$, then the maximum value is:
  • $120$
  • B
    $60$
  • C
    $82$
  • D
    $76$
Answer
Correct option: A.
$120$
The difference between the maximum and minimum value of the observation is called a range.
Let the maximum value be $x$.
So,
$x - 82 = 38$
$x = 82 + 38$
$x = 120$
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MCQ 2541 Mark
The mean of the below frequency distribution is $3.5$, then the value of $x$ is:
Varible
$1$
$2$
$x$
$4$
$5$
Frequency
$2$
$3$
$4$
$5$
$6$
  • A
    $2$
  • B
    $4$
  • C
    $5$
  • $3$
Answer
Correct option: D.
$3$

From the given frequency distribution table:
$3.5=\frac{2\times1+3\times2+4\text{x}+5\times4+6\times5}{2+3+4+5+6}$
$3.5=\frac{2+6+4\text{x}+20+30}{20}$
$70 + 4x + 58$
$4x = 12$
$x = 3$

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MCQ 2551 Mark
In the given graph, the number of students who scored $60$ or more marks is:
  • A
    $19$
  • B
    $20$
  • $21$
  • D
    $22$
Answer
Correct option: C.
$21$
Add the values corresponding to the height of the bar from $60$ to $100$
$10 + 5 + 3 + 3 = 21$
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MCQ 2561 Mark
The class mark of the class interval $2.4-6.6$ is:
  • $4.5$
  • B
    $4.2$
  • C
    $6.6$
  • D
    $2.4$
Answer
Correct option: A.
$4.5$
Class mark $=\frac{\text{uppar limit+lower limit}}{2}$
$=\frac{2.4+6.6}{2}$
$=\frac{9}{2}$
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MCQ 2571 Mark
The mean of the marks scored by $50$ students was found to be $39$. Later on it was discovered that a score of $43$ was misread as $23$. The correct mean is:
  • $39.4$
  • B
    $39.8$
  • C
    $39.2$
  • D
    $38.6$
Answer
Correct option: A.
$39.4$
Mean of the marks scored by $50$ students $= 39$
Sum of the marks scored by $50$ students $= (39 \times 50) = 1950$
Correct sum $= (1950 + 43 - 23) = 1970$
$\therefore$ Mean $= 19750 = 39.4$
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M.C.Q - Page 6 - MATHS STD 9 Questions - Vidyadip