Question 14 Marks
The ionic character of metallic halides tends toward covalent nature as per Fajan's rule. Such covalent halides behave as non-metal in their higher oxidation states. The property to hydrolyse to give oxy-acids of the element and corresponding hydro halogen acid for most non-metallic elements proceeds exceptionally in the way, keeping oxidation number of element and halide sam in oxo-acids.
Non-polar halides are immiscible in water, as they do not show hydrolysis, but halides of some elements with empty d-orbital undergo hydrolysis. Stability of halides of the higher state is governed by the inert-pair effect.
1. How does halide undergo hydrolysis to give oxy-acids of underlined element $PCl _3$ ? (1)
2. Out of $NCl _3$ and $BCl _3$ undergoes hydrolysis to form oxy-acids? Write the chemical reaction for the correct answer. (1)
3. Out of $PbCl _4, PbF _4, PbI _4$ and $PbBr _4$ which one doesn't exist? (2)
OR
Non-Polar halides are immiscible in water. Why? (2)
Non-polar halides are immiscible in water, as they do not show hydrolysis, but halides of some elements with empty d-orbital undergo hydrolysis. Stability of halides of the higher state is governed by the inert-pair effect.
1. How does halide undergo hydrolysis to give oxy-acids of underlined element $PCl _3$ ? (1)
2. Out of $NCl _3$ and $BCl _3$ undergoes hydrolysis to form oxy-acids? Write the chemical reaction for the correct answer. (1)
3. Out of $PbCl _4, PbF _4, PbI _4$ and $PbBr _4$ which one doesn't exist? (2)
OR
Non-Polar halides are immiscible in water. Why? (2)
Answer
View full question & answer→1. $PCl _3+3 H _2 O \rightarrow H _3 PO _3+3 HCl$
2. $BCl _3$ undergoes hydrolysis to form oxy-acids. The chemical reaction is as follows:
$
BCl_3+3 H_2 O \rightarrow H_3 BO_3+3 HCl
$
3. $PBI _4$ doesn't exist because $Pb ^{4+}$ is strong oxidant, where as $I ^{-}$is strong reductant.
OR
The non-polar halides are immiscible in water because it doesn't show hydrolysis but halides of some element with empty dorbital undergo hydrolysis.
2. $BCl _3$ undergoes hydrolysis to form oxy-acids. The chemical reaction is as follows:
$
BCl_3+3 H_2 O \rightarrow H_3 BO_3+3 HCl
$
3. $PBI _4$ doesn't exist because $Pb ^{4+}$ is strong oxidant, where as $I ^{-}$is strong reductant.
OR
The non-polar halides are immiscible in water because it doesn't show hydrolysis but halides of some element with empty dorbital undergo hydrolysis.
