Question 11 Mark
State which of the statement in True or False.
The last two digits of the numbers 3400 are 01.
The last two digits of the numbers 3400 are 01.
Answer
View full question & answer→True.
Solution:
Given that $3^{400}=(9)^{200}=(10-1)^{200}$ $\therefore(10-1)^{200}=\ ^{200}\text{C}_0(10)^{200}-\ ^{200}\text{C}_1(10)^{199}+...\\-\ ^{200}\text{C}_{199}(10)^1+\ ^{200}\text{C}_{200}(1)^{200}$ $=10^{200}-200\times10^{199}+...-10\times200+1$ So, it is clear that last two digits are 01. Hence, the given statement is True.