The real value of $\alpha$ for which the expression $\frac{1-\text{i}\sin\alpha}{1+2\text{i}\sin\alpha}$ is purely real is:
-
$(\text{n}+1)\frac{\pi}{2}$
-
$(2\text{n}+1)\frac{\pi}{2}$
-
$\text{n}\pi$
-
None of these, where $\text{n}\in\text{N}$
66 questions across 7 question groups — pick any mix to generate a MATHS paper with step-by-step answer keys.
M.C.Q (1 Marks)
16 Q→02True False[1 Marks ]
8 Q→03Fill In The Blanks[1 Marks ]
10 Q→041 Marks Question
3 Q→052 Marks Questions
6 Q→063 Marks Question
11 Q→075 Marks Questions
12 Q→One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
The real value of $\alpha$ for which the expression $\frac{1-\text{i}\sin\alpha}{1+2\text{i}\sin\alpha}$ is purely real is:
$(\text{n}+1)\frac{\pi}{2}$
$(2\text{n}+1)\frac{\pi}{2}$
$\text{n}\pi$
None of these, where $\text{n}\in\text{N}$
The value of $(\text{z}+3)(\bar{\text{z}}+3)$ is equivalent to:
If a + ib = c + id, then:
$\sin\text{x}+\text{i}\cos2\text{x}$ and $\cos\text{x}-\text{i}\sin2\text{x}$ are conjugate to each other for:
$\text{x}=\text{n}\pi$
$\text{x}=\Big(\text{n}+\frac{1}{2}\Big)\frac{\pi}{2}$
$\text{x}=0$
no value of x
The complex number z which satisfies the condition $\Big|\frac{\text{i}+\text{z}}{\text{i}-\text{z}}\Big|=1$ lies on:
Pick question groups from the list above, set marks and difficulty, and export a branded PDF with step-by-step answer keys. First 3 chapters free — no signup.