Question 11 Mark
Find the eccentricity of the hyperbola 9y2 - 4x2 = 36.
Answer
View full question & answer→We have the hyperbola 9y2 - 4x2 = 36 Or $\frac{\text{x}^2}{9}-\frac{\text{y}^2}{4}=-1$ We kanow that $\text{a}^2=\text{b}^2(\text{e}^2-1)$ $\therefore\ 9=4(\text{e}^2-1)$ $\Rightarrow\text{e}=\sqrt{1+\frac{9}{4}}$ $\Rightarrow\text{e}=\frac{\sqrt{13}}{2}$