Question 13 Marks
If $P(n)$ is the statement " $n^2+n$ is even", and if $P(r)$ is true, then $P(r+1)$ is true.
Answer
View full question & answer→$P(n): n^2+n$ is even
Given, P(r) is true
$\Rightarrow r^2 + r $is even
$\Rightarrow \text{r}^2 + \text{r} = 2\lambda \ ...(1)$
Now,
$(r + 1)^2 + (r + 1)$
$= r^2 + 1 + 2r + r + 1$
$= (r + 1)^2 + 2r + 2$
$=2\lambda + 2\text{r} + 2$ [Using equation (1)]
$=2(\lambda + \text{r} + 1)$
$=2\lambda$
$\Rightarrow (r + 1)^2 + (r + 1)$ is even
$\Rightarrow P(r + 1)$ is true
Given, P(r) is true
$\Rightarrow r^2 + r $is even
$\Rightarrow \text{r}^2 + \text{r} = 2\lambda \ ...(1)$
Now,
$(r + 1)^2 + (r + 1)$
$= r^2 + 1 + 2r + r + 1$
$= (r + 1)^2 + 2r + 2$
$=2\lambda + 2\text{r} + 2$ [Using equation (1)]
$=2(\lambda + \text{r} + 1)$
$=2\lambda$
$\Rightarrow (r + 1)^2 + (r + 1)$ is even
$\Rightarrow P(r + 1)$ is true