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Question 14 Marks
Answer
i. Total number of possible outcomes $={ }^{52} C_4$
We know that there are 12 face cards
$\therefore$ Number of favourable outcomes $={ }^{12} C_4$
$\therefore$ Required probability $=\frac{{ }^{12} C_4}{{ }^{52} C_4}$
ii. Total number of possible outcomes $={ }^{52} C_4$
We know that there are 26 red and 26 black cards.
$\therefore$ Number of favourable outcomes $={ }^{26} C_2 \times{ }^{26} C_2$
$\therefore$ Required probability $=\frac{\left({ }^{26} C_2\right)^2}{{ }^{52} C_4}$
$\begin{array}{l}\text { iii. Total number of possible outcomes }={ }^{52} C_4 \\ \therefore \text { Number of favourable outcomes }=\left({ }^{13} C_1\right)^4 \\ \therefore \text { Required probability }=\frac{(13)^4}{{ }^{52} C_4}\end{array}$
OR
Total number of possible outcomes $={ }^{52} C_4$
In playing cards there are 4 king and 4 jack cards.
$\begin{array}{l}
\because \text { Number of favourable outcomes }=\left({ }^4 C_2 \times{ }^4 C_2\right) \\
=6 \times 6=36 \\
\therefore \text { Required probability }=\frac{36}{{ }^{52} C_4}\end{array}$
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Question 24 Marks
Consider the complex number Z = 2 - 2i.
Complex Number in Polar Form 
Image

i. Find the principal argument of Z. (1)
ii. Find the value of $z \overline { Z }$ ? (1)
iii. Find the value of $| Z |$. (2) 
OR
Find the real part of Z. (2)
Answer

$\begin{array}{l}\text { i. } r =|Z|=2 \sqrt{2} \\ x =2, y =-2 \\ \cos \theta=\frac{x}{r}=\frac{2}{2 \sqrt{2}}=\frac{1}{\sqrt{2}} \\ \sin \theta=\frac{y}{r}=\frac{-2}{2 \sqrt{2}}=\frac{-1}{\sqrt{2}} \\ \operatorname{Arg}( Z )=\frac{-\pi}{4}\end{array}$
ii. $z \bar{z}=|z|^2=(2 \sqrt{2})^2=8$
$\begin{array}{l}\text { iii. }|Z|=\sqrt{2^2+(-2)^2} \\ \quad=\sqrt{8}=2 \sqrt{2}\end{array}$
OR
Real part of 2 - 2i = 2
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Question 34 Marks
Consider the graphs of the functions f(x), h(x) and g(x). 
Image
Image
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i. Find the range of h(x). (1)
ii. Find the domain of f(x). (1)
iii. Find the value of f(10). (2)
OR
Find the range of g(x). (2)
Answer
i. $h(x)=[x]$ is the greatest integer function. Its range is $Z$ (set of integers)
ii. $f(x)=|x|$. The domain of $f(x)$ is $R$.
iii. Since 10 > 0, f(10) = 1. 
OR
g(x) is the signum function. Its range is {-1, 0, 1}.
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Case study (4 Marks) - MATHS STD 11 Science Questions - Vidyadip