Question 14 Marks
Answer
View full question & answer→i. Total number of possible outcomes $={ }^{52} C_4$
We know that there are 12 face cards
$\therefore$ Number of favourable outcomes $={ }^{12} C_4$
$\therefore$ Required probability $=\frac{{ }^{12} C_4}{{ }^{52} C_4}$
ii. Total number of possible outcomes $={ }^{52} C_4$
We know that there are 26 red and 26 black cards.
$\therefore$ Number of favourable outcomes $={ }^{26} C_2 \times{ }^{26} C_2$
$\therefore$ Required probability $=\frac{\left({ }^{26} C_2\right)^2}{{ }^{52} C_4}$
$\begin{array}{l}\text { iii. Total number of possible outcomes }={ }^{52} C_4 \\ \therefore \text { Number of favourable outcomes }=\left({ }^{13} C_1\right)^4 \\ \therefore \text { Required probability }=\frac{(13)^4}{{ }^{52} C_4}\end{array}$
OR
Total number of possible outcomes $={ }^{52} C_4$
In playing cards there are 4 king and 4 jack cards.
$\begin{array}{l}
\because \text { Number of favourable outcomes }=\left({ }^4 C_2 \times{ }^4 C_2\right) \\
=6 \times 6=36 \\
\therefore \text { Required probability }=\frac{36}{{ }^{52} C_4}\end{array}$
We know that there are 12 face cards
$\therefore$ Number of favourable outcomes $={ }^{12} C_4$
$\therefore$ Required probability $=\frac{{ }^{12} C_4}{{ }^{52} C_4}$
ii. Total number of possible outcomes $={ }^{52} C_4$
We know that there are 26 red and 26 black cards.
$\therefore$ Number of favourable outcomes $={ }^{26} C_2 \times{ }^{26} C_2$
$\therefore$ Required probability $=\frac{\left({ }^{26} C_2\right)^2}{{ }^{52} C_4}$
$\begin{array}{l}\text { iii. Total number of possible outcomes }={ }^{52} C_4 \\ \therefore \text { Number of favourable outcomes }=\left({ }^{13} C_1\right)^4 \\ \therefore \text { Required probability }=\frac{(13)^4}{{ }^{52} C_4}\end{array}$
OR
Total number of possible outcomes $={ }^{52} C_4$
In playing cards there are 4 king and 4 jack cards.
$\begin{array}{l}
\because \text { Number of favourable outcomes }=\left({ }^4 C_2 \times{ }^4 C_2\right) \\
=6 \times 6=36 \\
\therefore \text { Required probability }=\frac{36}{{ }^{52} C_4}\end{array}$
i


