Question types

PART - 1 CH - 7 Binomial Theorem question types

25 questions across 6 question groups — pick any mix to generate a MATHS paper with step-by-step answer keys.

25
Questions
6
Question groups
5
Question types
Sample Questions

PART - 1 CH - 7 Binomial Theorem questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

If the sum of even and odd terms of the expansion of $(x+a)^n$ are A and B respectively, $(x+a)^{2 n}-(x$ $-a)^{2 n}$ is equal to :
  • A
    $4 (A + B)$
  • B
    $AB$
  • C
    $4 (A – B)$
  • $4AB$

Answer: D.

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If $C _0, C _1, C _2 \ldots . . C _n$ are the coefficients of different terms of the expansion of $(1+x)^n$, then $C _0+ C _2+$ $C _4+\ldots .$. is equal to :
  • A
    $2^n$
  • B
    $2^n-1$
  • $2^{n-1}$
  • D
    $2^{n+1}$

Answer: C.

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If $C _0, C _1, C _2, \ldots \ldots . C _n$ are the binomial coefficients in the expansion of $(1+x)^n$, then prove that :
$C_0-\frac{C_1}{2}+\frac{C_2}{3}-\frac{C_3}{4}+\ldots \ldots \ldots+\frac{(-1)^n \cdot C_n}{n+1}=\frac{1}{n+1}$
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If $C_0, C_1, C_2, \ldots \ldots \ldots . C_n$ are the binomial coefficients in the expansion of $(1+x)^n$, then prove that :
$2 C_0+\frac{2^2 C_1}{2}+\frac{2^3 C_2}{3}+\ldots \ldots  +\frac{2^{n+1} \cdot C_n}{n+1}=\frac{3^{n+1}-1}{n+1}$
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If the expansion of $\left(1+x-2 x^2\right)^6$ is $1+a_1 x+$ $a_2 x^2+a_3 x^3+$ $\ldots\ldots\ldots$ $+a_{12} x^{12}$, then prove that $a_2$ $+a_4+a_6+\ldots \ldots \ldots .+a_{12}=31$.
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Part (a)Part (b)
1. Number of terms in the expansion of $\left(4 x^2+12 x y+9 y^2\right)^9$(a) $\sum_{r=0}^n{ }^n C _r x^{n-r} y^r$
2. $(2+\sqrt{5})^5+(2-\sqrt{5})^5$(b) 9
3. $999^3$(c) 1364
4. Number of terms in the expansion of $(a+b x)^{17} -(a-b x)^{17}$(d) 19
5. $(x+y)^{ n }$(e) 997002999
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