Fill In The Blanks[1 Marks ]

Question 11 Mark

Fill in the blanks.
The probability that the home team will win an upcoming football game is 0.77, the probability that it will tie the game is 0.08, and the probability that it will lose the game is __________.

Answer

The probability that the home team will win an upcoming football game is 0.77, the probability that it will tie the game is 0.08, and the probability that it will lose the game is 0.15
Solution:
P(losing) = 1 - (0.77 + 0.08) = 0.15

View full question & answer→

Question 21 Mark

Fill in the blanks.
If A and B are two events associated with a random experiment such that P(A) = 0.3, P(B) = 0.2 and $\text{P}(\text{A}\cap\text{B})=0.1,$ then the value of $\text{P}(\text{A}\cap\bar{\text{B}})$ is ____________.

Answer

If A and B are two events associated with a random experiment such that P(A) = 0.3, P(B) = 0.2 and $\text{P}(\text{A}\cap\text{B})=0.1,$ then the value of $\text{P}(\text{A}\cap\bar{\text{B}})$ is 0.2

Solution:

$\text{P}(\text{A}\cap\bar{\text{B}})=\text{P(A)}-\text{P}(\text{A}\cap\text{B})$

$=0.3-0.1=0.2$

View full question & answer→

Question 31 Mark

Fill in the blanks.
Let S = {1, 2, 3, 4, 5, 6} and E = {1, 3, 5}, then $\bar{\text{E}}$ is __________.

Answer

Let S = {1, 2, 3, 4, 5, 6} and E = {1, 3, 5}, then $\bar{\text{E}}$ is {2, 4, 6}.
Solution:
Here, S = {1, 2, 3, 4, 5, 6}
and E = {1, 3, 5}
$\therefore\ \bar{\text{E}}=\text{S}-\text{E}=\{2,4,6\}$

View full question & answer→

Question 41 Mark

Fill in the blanks.
If e₁, e₂, e₃, e₄ are the four elementary outcomes in a sample space and P(e₁) = 0.1, P(e₂) = 0.5, P (e₃) = 0.1, then the probability of e₄ is ___________.

Answer

If e₁, e₂, e₃, e₄ are the four elementary outcomes in a sample space and P(e₁) = 0.1, P(e₂) = 0.5, P (e₃) = 0.1, then the probability of e₄ is 0.3

Solution:

$\text{P}(\text{E}_1)+\text{P}(\text{E}_2)+\text{P}(\text{E}_3)+\text{P}(\text{E}_4)=1$

$\Rightarrow0.1+0.5+0.1+\text{P}(\text{E}_4)=1$

$\Rightarrow0.7+\text{P}(\text{E}_4)=1$

$\therefore\ \text{P}(\text{E}_4)=0.3$

View full question & answer→

Question 51 Mark

Fill in the blanks.
The probability of happening of an event A is 0.5 and that of B is 0.3. If A and B are mutually exclusive events, then the probability of neither A nor B is __________.

Answer

The probability of happening of an event A is 0.5 and that of B is 0.3. If A and B are mutually exclusive events, then the probability of neither A nor B is 0.2

Solution:

$\text{P}(\bar{\text{A}}\cap\bar{\text{B}})=\text{P}(\overline{\text{A}\cup\text{B}})$

$=1-\text{P}(\text{A}\cup\text{B})$

$=1-\big[\text{P(A)}+\text{P(B)}\big]$ [Since, A and B are mutually exclusive]

$=1-(0.5+0.3)$

$=1-0.8=0.2$

View full question & answer→

MATHS Fill In The Blanks[1 Marks ]

Take a timed test