Fill In The Blanks[1 Marks ]

Question 11 Mark

$\text{Cofficient of variation}=\frac{......}{\text{Mean}}\times100$

Answer

$\text{Cofficient of variation}=\frac{\text{SD}}{\text{Mean}}\times100$
Solution:
$\text{CV}=\frac{\text{SD}}{\text{Mean}}\times100$
Hence, the value of the filler is SD.

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Question 21 Mark

The mean deviation of the data is _______ when measured from the median.

Answer

The mean deviation of the data is least when measured from the median.
Solution:
The mean deviation of the data is least when measured from the median.

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Question 31 Mark

The standard deviation of a data is _________ of any change in orgin, but is _________ on the change of scale.

Answer

The standard deviation of a data is independent of any change in orgin, but is dependent on the change of scale.
Solution:
The standard deviation of a data is independent of any change in origin but is dependent of charge of scale.

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Question 41 Mark

The standard deviation is _________ to the mean deviation taken from the arithmetic mean.

Answer

The standard deviation is greater than or equal to the mean deviation taken from the arithmetic mean.
Solution:
The standard deviation is greater than or equal to the mean deviation taken from the arithmetic mean.

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Question 51 Mark

If the variance of a data is 121, then the standard deviation of the data is _______.

Answer

If the variance of a data is 121, then the standard deviation of the data is 11.
Solution:
We know that $\text{SD}=\sqrt{\text{variance}}=\sqrt{121}=11$
Hence, the value of the filler is 11

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Question 61 Mark

The sum of the squares of the deviations of the values of the variable is _______ when taken about their arithmetic mean.

Answer

The sum of the squares of the deviations of the values of the variable is minimum when taken about their arithmetic mean.
Solution:
The sum of the squares of the deviations of the values of the variable is minimum when taken about their arithmetic mean.

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Question 71 Mark

If $\bar{\text{x}}$ is the mean of n values of x, then $\sum\limits^{\text{M}}_{\text{i}=1}(\text{x}_\text{i}-\bar{\text{x}})$ is always equal to _______. If a has any value other than $\bar{\text{x}}$ then $\sum\limits^{\text{n}}_{\text{i}=1}(\text{x}_\text{i}-\bar{\text{x}})^2$ is _______ then $\sum(\text{x}_\text{i}-\text{a})^2$

Answer

If the mean of n values of x, then $\sum\limits^{\text{M}}_{\text{i}=1}(\text{x}_\text{i}-\bar{\text{x}})$ is always equal to 0. If a has any value other than $\bar{\text{x}}$ then $\sum\limits^{\text{n}}_{\text{i}=1}(\text{x}_\text{i}-\bar{\text{x}})^2$ is less than $\sum(\text{x}_\text{i}-\text{a})^2$
Solution:
If the mean of n values of x, then $\sum\limits^{\text{M}}_{\text{i}=1}(\text{x}_\text{i}-\bar{\text{x}})$ is always equal to 0. If a has any value other than $\bar{\text{x}}$ then $\sum\limits^{\text{n}}_{\text{i}=1}(\text{x}_\text{i}-\bar{\text{x}})^2$ is less than $\sum(\text{x}_\text{i}-\text{a})^2$

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