Physics 2 Marks Questions

The direction of the vector $(\vec{\text{B}}\times\vec{\text{C}})$ will be perpendicular to the plane containing by vectors $\vec{\text{B}}$ and $\vec{\text{C}}$ by Right-hand thumb or Right-hand grip rule (RHGR).

The direction of the vector $\vec{\text{A}}\times(\vec{\text{B}}\times\vec{\text{C}})$ will be perpendicular to $\vec{\text{A}}$ and in a plane containing $\vec{\text{B}}$ and $\vec{\text{C}}$ by Right-hand grip rule.

The path of the cyclist at R is circular of constant radius 1km with centre O and he is moving with constant speed 10m/ s. So his motion is uniform circular motion at R.

Hence, the R = 1000m, v =10m/ s

$\therefore\ \text{a}_\text{c}=\frac{\text{v}^2}{\text{R}}=\frac{10\times10}{1000}=\frac{1}{10}=0.1\text{m/ s}^2$ along RO.