Match List $I$ with List $II$
| List $I$ | List $II$ |
| $A$. Clostridium butylicum | $1$. Ethanol |
| $B$.Saccharomycescerevisiae | $II$. Streptokinase |
| $C$.Trichodermapolysporum | $III$. Butyric acid |
| $D$. Streptococcus sp. | $IV$.Cyclosporin-$A$ |
Choose the correct answer from the options given below:
- A$A-II, B-IV, C-III, D-I$
- ✓$A-III, B-I, C-IV, D-II$
- C$A-IV, B-I, C-III, D-II$
- D$A-III, B-I, C-II, D-IV$
Answer: B.
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