Question 11 Mark
In a reaction, $2A \rightarrow$ Products, the concentration of A decreases from $0.5 \ \ce{mol L^{–1}}$ to $0.4 \ \ce{mol L^{–1}}$ in $10$ minutes. Calculate the rate during this interval?
Answer
View full question & answer→$\text{Average Rate}=\frac{-1}{2}\frac{\triangle\ [\text{A}]}{\triangle\ \text{t}}$
$=\frac{-1}{2}\frac{\text{[A]}_2-\text{[A]}}{\text{t}_2-\text{t}_1}$
$=\frac{-1}{2}\frac{(0.4-0.5)}{10}$
$=\frac{-1}{2}\frac{(-0.1)}{10}$
$= 5 \times 10^{-3} \ce{M min^{-1}}$
$=\frac{-1}{2}\frac{\text{[A]}_2-\text{[A]}}{\text{t}_2-\text{t}_1}$
$=\frac{-1}{2}\frac{(0.4-0.5)}{10}$
$=\frac{-1}{2}\frac{(-0.1)}{10}$
$= 5 \times 10^{-3} \ce{M min^{-1}}$