Question 12 Marks
Based on solute$-$solvent interactions, arrange the following in order of increasing solubility in $n-$octane and explain. Cyclohexane, $\ce{KCl, CH_3OH, CH_3CN}.$
Answer
View full question & answer→$n-$octane is a non$-$polar solvent.
Therefore, the solubility of a non$-$polar solute is more than that of a polar solute in the $n-$octane.
The order of increasing polarity is:
Cyclohexane $\ce{< CH_3CN < CH_3OH < KCl}$
Therefore, the order of increasing solubility is:
$\ce{KCl < CH_3OH
Therefore, the solubility of a non$-$polar solute is more than that of a polar solute in the $n-$octane.
The order of increasing polarity is:
Cyclohexane $\ce{< CH_3CN < CH_3OH < KCl}$
Therefore, the order of increasing solubility is:
$\ce{KCl < CH_3OH

