Question 11 Mark
Maximise the function $\text{Z}=11\text{x}+7\text{y},$ subject to the constraints: $\text{x}\leq3,\text{y}\leq2,\text{x}\geq0,\text{y}\geq0.$
Answer
View full question & answer→Maximise $\text{Z}=11\text{x}+7\text{y},$ subject to the constraints $\text{x}\leq3,\text{y}\leq2,\text{x}\geq0,\text{y}\geq0.$

The shaded region as shown in the figure as OABC is bounded and the coordinates of corner points are (0, 0), (3, 0), (3, 2), and (0, 2), respectively.
Hence, Z is maximise at (3, 2) and its maximum value is 47.

The shaded region as shown in the figure as OABC is bounded and the coordinates of corner points are (0, 0), (3, 0), (3, 2), and (0, 2), respectively.
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Corner points
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Corresponding value of Z
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(0, 0)
(3, 0)
(3, 2)
(0, 2)
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0
33
47 (Maximum)
14
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