Question 11 Mark
The probability distribution of random variable X is given below:
Find $\text{P}(\text{X}\leq2)+\text{P}(\text{X}>2)$
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$\text{X}$
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$0$
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$1$
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$2$
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$3$
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$\text{P}(\text{X})$
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$\text{k}$
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$\frac{\text{k}}{2}$
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$\frac{\text{k}}{4}$
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$\frac{\text{k}}{8}$
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Answer
View full question & answer→$\text{P}(\text{X}\leq2)+\text{P}(\text{X}>2)$
$=\text{P}(0)+\text{P}(1)+\text{P}(2)+\text{P}(3)$
$=1$
$=\text{P}(0)+\text{P}(1)+\text{P}(2)+\text{P}(3)$
$=1$