Question 11 Mark
Assertion (A): Consider the function defined as $f(x)=|x|+|x-1|, x \in R$. Then $f(x)$ is not differentiable at x = 0 x = 1
Reason (R): Suppose f be defined and continuous on $(a, b)$ and $c \in(a, b)$, then $f(x)$ is not differentiable at $x=c$ if $\lim _{h \rightarrow 0^{-}} \frac{f(c+h)-f(c)}{h} \neq \lim _{h \rightarrow 0^{+}} \frac{f(c+h)-f(c)}{h}$.
Reason (R): Suppose f be defined and continuous on $(a, b)$ and $c \in(a, b)$, then $f(x)$ is not differentiable at $x=c$ if $\lim _{h \rightarrow 0^{-}} \frac{f(c+h)-f(c)}{h} \neq \lim _{h \rightarrow 0^{+}} \frac{f(c+h)-f(c)}{h}$.
Answer
View full question & answer→Both (A) and (R) are true and (R) is the correct explanation of (A).