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Assertion (A) & Reason (B) MCQ

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2 questions · self-marked practice — reveal the answer and mark yourself.

Question 11 Mark
Assertion $(A)$ : If manufacturer can sell $x$ items at a price of $₹ \left(5-\frac{x}{100}\right)$ each.
The cost price of $x$ items is $₹ \left(\frac{x}{5}+500\right)$
Then, the number of items he should sell to earn maximum profit is $240$ items.
Reason $(R)$ : The profit for selling x items is given by $\frac{24}{5} x-\frac{x^2}{100}-300$
Answer
$(c) \ A$ is true but $R$ is false.
Explanation : Let $S\ (x)$ be the selling price of $x$ items and let $C\ (x)$ be the cost price of $x$ items.
Then, we have
$S(x)=\left(5-\frac{x}{100}\right) x=5 x-\frac{x^2}{100}$
and $C(x)=\frac{x}{5}+500$
Thus, the profit function $P(x)$ is given by
$P ( x )= S ( x )- C ( x )=5 x -\frac{x^2}{100}-\frac{x}{5}-500$
i.e. $ P ( x )=\frac{24}{5} x-\frac{x^2}{100}-500$
On differentiating both sides $\text{w.r.t. x,}$ we get
$P ^{\prime}( x )=\frac{24}{5}-\frac{x}{50}$
Now, $P ^{\prime}( x )=0$ gives $x =240$.
Also, $P ^{\prime}( x )=\frac{-1}{50}$.
So, $P ^{\prime}(240)=\frac{-1}{50}<0$
Thus $, x = 240$ is a point of maxima.
Hence, the manufacturer can earn maximum profit, if he sells $240$ items.
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Question 21 Mark
Assertion (A): Let $A =\{1,5,8,9\}, B =\{4,6\}$ and $f =\{(1,4),(5,6),(8,4),(9,6)\}$, then f is a bijective function.
Reason (R): Let $A=\{1,5,8,9\}, B=\{4,6\}$ and $f=\{(1,4),(5,6),(8,4),(9,6)\}$, then $f$ is a surjective function.
Answer
(d) A is false but R is true.
Explanation: We have, $A=\{1,5,8,9\}, B=\{4,6\}$ and $f=\{(1,4),(5,6),(8,4),(9,6)\}$
So, all elements of B has a domain element on A or we can say elements 1 and 8 5 and 9 have some range 4 6, respectively.
Therefore, $f : A \rightarrow B$ is a surjective function not one to one function.
Also, for a bijective function, f must be both one to one onto.
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Assertion (A) & Reason (B) MCQ - MATHS STD 12 Science Questions - Vidyadip