Question 11 Mark
Assertion $(A)$ : Minimum value of $(x-5)(x-7)$ is -1 .
Reason $(R)$ : Minimum value of $ax ^2+ bx + c$ is $\frac{4 a c-b^2}{4 a}$.
Reason $(R)$ : Minimum value of $ax ^2+ bx + c$ is $\frac{4 a c-b^2}{4 a}$.
Answer
View full question & answer→$(a)$ Both $A$ and $R$ are true and $R$ is the correct explanation of $A.$
Explanation : We have $, (x - 5)(x - 7)$
$\Rightarrow x^2-12 x+35$
We know that, $ax ^2+ bx + c$ has minimum value $\frac{4 a c-b^2}{4 a}$.
Here $, a = 1 b = - 12$ and $c = 35$
$\therefore$ Minimum value of $(x-5)(x-7)$
$=\frac{4.1 \cdot 35-(-12)^2}{4.1}$
$=\frac{140-144}{4}$
$=-\frac{4}{4}$
$=-1$
Explanation : We have $, (x - 5)(x - 7)$
$\Rightarrow x^2-12 x+35$
We know that, $ax ^2+ bx + c$ has minimum value $\frac{4 a c-b^2}{4 a}$.
Here $, a = 1 b = - 12$ and $c = 35$
$\therefore$ Minimum value of $(x-5)(x-7)$
$=\frac{4.1 \cdot 35-(-12)^2}{4.1}$
$=\frac{140-144}{4}$
$=-\frac{4}{4}$
$=-1$