Question types

The plane question types

235 questions across 4 question groups — pick any mix to generate a MATHS paper with step-by-step answer keys.

235
Questions
4
Question groups
5
Question types
Sample Questions

The plane questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

The distance between the planes $2x + 2y - z +2 = 0$ and $4x + 4y - 2z + 5 = 0$ is :
  • A
    $\frac{1}{2}$
  • B
    $\frac{1}{4}$
  • $\frac{1}{6}$
  • D
    None of these

Answer: C.

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The equation of the plane parallel to the lines x - 1 = 2y - 5 = 2z and 3x = 4y - 11 = 3z -4 and passing through the point (2, 3, 3) is:
  1. x - 4y + 2z + 4 = 0
  2. x + 4y + 2z + 4 = 0
  3. x - 4y + 2z - 4 = 0
  4. None of these
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The distance between the point (3, 4, 5) and the point where the line $\frac{\text{x}-3}{\text{1}}=\frac{\text{y}-4}{\text{2}}=\frac{\text{z}-5}{\text{2}}$ meets the plane x + y + z = 17 is:
  1. 1
  2. 2
  3. 3
  4. None of these
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The distance of the line $\vec{\text{r}}=2\hat{\text{i}}-2\hat{\text{j}}+3\hat{\text{k}}+\lambda(\hat{\text{i}}-\hat{\text{j}}+4\hat{\text{k}})$ from the plane $\vec{\text{r}}.(\hat{\text{i}}+5\hat{\text{j}}+\hat{\text{k}})=5$ is:
  1. $\frac{5}{3\sqrt{3}}$
  2. $\frac{10}{3\sqrt{3}}$
  3. $\frac{25}{3\sqrt{3}}$
  4. $\text{None of these}$
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The plane $2\text{x}-(1-\lambda)\text{y}+3\lambda\text{z}=0$ passes through the intersection of the planes:
  1. 2x - y = 0 and y- 3z = 0
  2. 2x + 3z = 0 and y = 0
  3. 2x - y + 3z = 0 and y - 3z = 0
  4. None of these
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Find the cartesian form of the equation of a plane whose vector equation is:
$\vec{\text{r}}\cdot\big(12\hat{\text{i}}-3\hat{\text{j}}+4\hat{\text{k}}\big)+5=0$ 
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Q 113 Marks Question3 Marks
A plane meets the coordinate axes at A, B and C, respectively, such that the centriod of triangle ABC is (1, -2, 3). Find the equation of the plane.
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Q 133 Marks Question3 Marks
Find the angle between the given planes.
$\vec{\text{r}}\cdot(2\hat{\text{i}}-\hat{\text{j}}+2\hat{\text{k}})=6$ and $\vec{\text{r}}\cdot(3\hat{\text{i}}+6\hat{\text{j}}-2\hat{\text{k}})=9$
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If the lines $\frac{\text{x}-1}{-3}=\frac{\text{y}-2}{-2\text{k}}=\frac{\text{z}-3}{2}$ and $\frac{\text{x}-1}{\text{k}}=\frac{\text{y}-2}{1}=\frac{\text{z}-3}{5}$ are perpendicular, find the value of $k$ and, hence find the equation of the plane containing these lines.
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