Question 12 Marks
A carrier wave of peak voltage 15 V is used to transmit a message signal. Find the peak voltage of the modulating signal in order to have a modulation of 60%.
Answer
View full question & answer→Peak voltage =15 V
Modulation index $= 60\% = 0.60$
Amplitude of modulating wave $= A_{m}$
Amplitude of carrier wave $= A_{c}$
$\mu = \frac{A_{m}}{A_{c}}$
$0.60 = \frac{A_{m}}{15}$
$0.60 \times 15 = A_{m}$
$9 V = A_{m}$.
Modulation index $= 60\% = 0.60$
Amplitude of modulating wave $= A_{m}$
Amplitude of carrier wave $= A_{c}$
$\mu = \frac{A_{m}}{A_{c}}$
$0.60 = \frac{A_{m}}{15}$
$0.60 \times 15 = A_{m}$
$9 V = A_{m}$.