Question 11 Mark
If the intensity of sound is doubled, by how many decibels does the sound level increase?
Answer
View full question & answer→We know that, $\beta=10\log_{10}\frac{\text{J}}{\text{I}_0}$ According to the questions$\beta_\text{A}=10\log_{10}\Big(\frac{2\text{I}}{\text{I}_0}\Big)$
$\Rightarrow\beta_\text{B}-\beta_\text{A}=10\log\Big(\frac{2\text{I}}{\text{I}}\Big)$
$=10\times0.3010$
$=3\text{dB}.$
$\Rightarrow\beta_\text{B}-\beta_\text{A}=10\log\Big(\frac{2\text{I}}{\text{I}}\Big)$
$=10\times0.3010$
$=3\text{dB}.$