A galaxy is observed to be moving with a velocity of $8600 \mathrm{~km}-\mathrm{sec}^{-1}$. If it is at a distance of $430$ million light year from us, Hubble constant and corresponding age of the universe are respectively
- A$2 \times 10^{-5} \frac{\mathrm{kms}^{-1}}{\mathrm{ly}} \times 10^{10}$ year
- ✓$2 \times 10^{-6} \frac{\mathrm{kms}^{-1}}{\mathrm{ly}} \times 10^3$ year
- C$10^6 \frac{\mathrm{kms}^{-1}}{\mathrm{ly}}, 1.49 \times 10^{10}$ year
- DNone of these
Answer: B.
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