MATHS M.C.Q. [1 Marks Each]

$\text{Arithmetic Mean}=\frac{10+20+30+40}{4}=\frac{100}{4}=25$

Number of A appearing in list are $9$ Number of $B$ appearing in list are $8$ Number of $G$ appearing in
list are $7$ Number of $M$ appearing in list are $10$ Number of $O$ appearing in list are $8$
So, $M$ appeared most, a and $M$ stands for Mango. So, Mango $M$ is the fruit which is liked by most student

Given, arithmetic mean of $x$ and $\text{y}=\frac{\text{x+y}}{2}=40$
$\Rightarrow x + y = 80$ And given,$ z = 30$
$\therefore$ The the sumofx, $y$ and $z$ is $110$

Khilona earned scores of $97, 73$ and $88$ respectively in her first three examinations.
Average score of Khilona in first three exam $= \frac{(97 + 73 + 88)}{3} = \frac{258}{3} = 86$
Now she scored $80$ in the fourth examination.
Now Average score of Khilona in all four exams $= \frac{(97 + 73 + 88 + 80)}{4} = \frac{338}4 = 84.5$
So there is decrement in her average score
Now decresment in average score $= 86 - 84.5 = 1.5$

$\Rightarrow $ Number of government employees in Delhi $= 4200$
$\Rightarrow $ Number of $\square$ represent government employees in Delhi $= 7$
$\Rightarrow $ Number of employee $\square$ represents $=\frac{4200}{7}=600$

$A, B, C, D, E$

A symbol is used to represent $10$ flowers
Symbol use to drawn $60$ flowers $=\frac{60}{10}=6$

$20 + 20 = 40$

One $\Uparrow$ represents $5$ houses. There are total $4$ such symbols
$\therefore$ $\Uparrow\ \Uparrow\ \Uparrow \ \Uparrow$ represents $4 \times 5 = 20$

Total number of card in the set of playing card $= 52$
Total number ace in the set of playing card $= 4$
So, probability of picking up an ace card from a set of playing card $= \frac{4}{52} = \frac{1}{13}$

First 5 odd numbers $= 1, 3, 5, 7, 9$
Mean $=\frac{\big(1+3+5+7+9\big)}{5}=\frac{25}{5}=5$

We know that, Range = highest value - lowest value
Thus, range of height $= 164 - 154 = 10$

=Given, mean of $8, 4, x, 6, 2, 7$ is $5$
$\Rightarrow  \frac{(8 + 4 + \text{x} + 6 + 2 + 7)}{6} = 5$
$\Rightarrow 27 + x = 6 \times 5$
$\Rightarrow 27 + x = 30$
$\Rightarrow x = 30 - 27$
$\Rightarrow x = 3$

$3 : 6 = 1 : 2$

$95, 78, 75$

The upper limit of class interval is the uppermost value of class interval, and the lower limit if the lowermost value of class interval.
Therefore, in $75 - 85$ the upper limit is $85$

$95 - 25 = 70$

From the table of question $2$, we can calculate the number of students who scored marks less than $4.$
Number of students who scored less than $4$ marks $= 4 + 2 + 2 + 2 = 10$

Given that one square box represents $10$ letters. On Tuesday there are $5$ boxes.
Therefore, number of letters collected on Tuesday are $10 \times 5 = 50$ On Wednesday there are $4$ boxes.
Therefore, number of letters collected on Wednesday are $10 \times 4 = 40$
There are $50 - 40 = 10$ letters less on Wednesday than on Tuesday.

$2 \times 10 = 20$

$\text{Average}=\frac{88+74+86+87+70}{5}=\frac{405}{5}=81$

$O$ represents $5$ eggs eggs $OOOO$ represents represents $5 \times 4 = 20$eggs

Tally ma'ks are used for $\infty$ unting things. And, it is shown by'
Every fifth mark is drawn across the last four marks that make the tally marks easer to count as they build up, in blooks of five

We knew that, Range = highest value - lowest value
Thus, range of age $= 9 - 3 - 6$

$x$ 10Monday $= 7$ Tuesdday $= 5$ wednesday $= 4$ thrusday $= 6$ friday $= 8$ saturday $= 3$
Hence saturday least letter were collected.

The probability of an event which is certain to happen is $1$
Ex: The sun rises in the east.
Since this event is certain happen. So, its probability is $1.$

The difference between the highest and lowest observations in a data is its range.
Ex : Given marks are:
$20, 30, 17, 45, 40, 33, 37, 47, 27, 48$
Arrange them in ascending order, we get
$17, 20, 27, 30, 33, 37, 40, 45, 47, 48$
The highest mark $= 48$
The lowest mark $= 17$
Now, Range $= 48 - 17 = 31$

$\begin{aligned} & \text { Hyderabad }=7 \odot=4200 \odot=\frac{4200}{7}=600 \text { chenna } 5 \odot=3000 \\ & 1 \bigodot=\frac{3000}{5}=600\end{aligned}$

Table with tally marks from the given information is shown below:

From the table, we can observe that banana and grapes are liked by equal number of students, i.e. $8.$

$700 + 600 + 500 + 400 + 400 = 2600$

$\text{Delhi}=\Box\times7=4200\ \Box\times1=\frac{4200}{7}=600\ \Box=600$

Total electricity produced during the last two years
i.e., in year $2006$ and year $2007 = 50.28 + 75.53 = 125.81$ million kilcwatt.

$700 - 600 = 100$

$55, 36, 42, 25$

$12 + 7 = 19$

$6 : 12 = 1 : 2$

Both have $6$ frequency

We have given that $7$ smiley is equal to $4200.$
So one smiley $=\frac{4200}{7}=600$

$40 - 10 = 30$

$400 : 400 = 1 : 1$

$C \rightarrow 20, D \rightarrow 20$

From the table of question $4$, we can observe that mango is liked by most of the students.