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Question 13 Marks
Namita travels $20 \ km$ $50 m$ everyday. Out of this she travels $10 \ km$ $200 m$ by bus and the rest by auto. How much distance does she travel by auto?
Answer
Distance travelled everyday $= 20 \ km$
$50\ m = 20 \ km + 50 m$
$= 20 \ km +$ $\frac{50}{1000}$
$km = 20\ km + 0.050\ km ...$[$\because$$1 m$ $=\;\frac1{1000}$$km = 0.001\ km]$
$= (20 + 0.050) \ km = 20.050 \ km$
Distance travelled by bus$ = 10 km$
$200 m = 10 km + 200 m$
$= 10 \ km +$$\frac{200}{1000}$$km$
$= 10 \ km + 0.200 \ km ...$[$\because$$1 m$ $=\;\frac1{1000}$ $\ km = 0.001\ km]$
$= (10 + 0.200) \ km = 10.200 \ km$
$\therefore$ Distance travelled by auto $= 20.050 \ km - 10.200 \ km = 9.850 \ km$​​​​​​​
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Question 23 Marks
Tina had $20 m$ $5\ cm$ long cloth. she cuts $4 m$ $50 \ cm$ length of cloth from this for making a curtain. How much cloth is left with her ?
Answer
Length of cloth Tina had $= 20 m 5\ cm = 20 m + 5\ cm$
$= 20 m +$ $\frac{5}{100}$ $m = 20 m + 0.05 m ...[$$\because$ $=\frac{1}{100}$$cm = 0.01m]$
$= (20 + 0.05) m = 20.05 m$
Length of cloth cut $= 4 m 50 cm = 4 m + 50\ cm$
$= 4 m +$ $\frac{50}{100}$ $m = 4 m + 0.50 m ...[$$\because$ $=\frac{1}{100}$ $cm = 0.01m]$
$= (4 + 0.50) m = 4.50 m$
$\therefore$ Length of cloth left $= 20.05 m – 4.50 m = 15.55 m$
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Question 33 Marks
Samson travelled $5 km$ $52 m$ by bus, $2 km$ $265 m$ by car and the rest $1km$ $30 m$ he walked. How much distance did he travel in all?
Answer
Distance travelled by bus $= 15 \ km$
$268 m = 15 \ km + 268 m$
$= 15 \ km +$ $\frac{268}{1000}$ $km = 15 \ km + 0.268 \ km ...[$$\because$ $1m$ $=\;\frac1{1000}$ $km]$
$= (15 + 0.268) \ km = 15.268 \ km$
Distance travelled by car$ = 7 \ km$ $7 m = 7 \ km + 7 m$
$= 7 km +$ $\frac{7}{1000}$$km = 7 km + 0.007 km ...[$$\because$ $1m$ $=\;\frac1{1000}$ $km]$
$= (7 + 0.007) km = 7.007 km$
Distance travelled by foot $= 500 m =$ $\frac{500}{1000}$$km = 0.500 km ...[$$\because$ $1m$ $=\;\frac1{1000}$ $km]$
$\therefore$ Distance of school from residence $= 15.268 \ km + 7.007 \ km + 0.500 \ km = 22.775 \ km$
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