3 Marks Question

Question 13 Marks

What number added to $3.56$ gives $23.018$?

Answer

Let the required number be $x.$
According to the question,
$3.56 + x = 23.018$
$\Rightarrow x = 23.018 - 3.5$

$\Rightarrow x = 19.458$
Hence, $19.458$ when added to $3.56$ gives $23.018.$

Question 23 Marks

Sunita travels $15\ km$ $268m$ by bus, $7\ km$ $7m$ by car and $500m$ by foot in order to reach her school. How far is her school from her residence?

Answer

Distance travelled by bus $= 15\ km$ $268m = 15.268\ km$
Distance travelled by car $= 7\ km$ $7m = 7.007\ km$
Travel on foot $= 500m = 0.500\ km$
Total distance travelled by sunita $= (15.268 + 7.07 + 0.500)km = 22.775\ km$
Therefore, the total distance covered by sunita is $22.775\ km$

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Question 33 Marks

Ruby bought a watermelon weighing $5\ kg$ $200g$. Out of this she gave $2\ kg$ $750g$ to her neighbour. What is the weight of the watermelon left with Ruby?

Answer

Weight of the watermelon when bought $= 5\ kg$ $200g = 5.200\ kg$
Weight of the watermelon given to the neighbor$ = 2\ kg$ $750g = 2.750\ kg.$
Therefore, weight of the watermelon left with ruby = Weight of the watermelon when bought - Weight of the watermelon when given to the neighbor, $= (5.200 - 2.750)kg = 2.450\ kg$
So, the weight of the water melon left with ruby $= 2.450\ kg.$

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Question 43 Marks

Tina had $20m$ $5\ cm$ long cloth. She cuts $4m$ $50\ cm$ length of cloth form this for making a curtain. How much cloth is left with her?

Answer

Length of cloth originally $= 20m$ $5\ cm = 2.05m$
Length of cloth cut for curtain $= 4m$ $50\ cm = 4.50m$
Therefore, length of cloth left with tina = length of cloth originally - length of cloth cut for curtain,
$= 20.05 - 4.50m = 15.55m$
Length of the cloth left with tina $= 15.55m.$

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Question 53 Marks

Tanuj walked $8.62\ km$ on Monday, $7.05\ km$ on Tuesday, and some distance on Wednesday. If he walked $21.01\ km$ in three days, how much distance did he walk on Wednesday?

Answer

Distance travelled on Monday $= 8.62\ km$
Distance travelled on Tuesday $= 7.05\ km$
Suppose the distance travelled on Wednesday $= x \ km$
Total distance covered,
$= 21.01 = 8.62 + 7.05 + x$
$= x = 21.01 - 15.67$
$= x = 5.34$
Therefore, Tanuj walked $5.34\ km$ on Wednesday.

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Question 63 Marks

Shikha bought $2m$ $5\ cm$ cloth for her salwar and $3m$ $35\ cm$ cloth for her shirt. Find the total length of cloth bought by her.

Answer

Cloth required for salwar $= 2m$ $05\ cm = 2.05m$
Cloth required for shirt $= 3m$ $35\ cm = 3.35m$
Total cloth required is: $\underline{\ \ \ \ \ \ \ _1\\\ \ \ \ 2.05\text{m}\\+3.35\text{m}}\\\underline{\ 5\ .\ 40\text{m}}$
Hence, the total length of cloth bought by Shikha is $5.4m.$

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Question 73 Marks

What number subtracted from $18.5$ gives $6.2376$?

Answer

Let the required number be $x.$ According to the question,
$18.5 - x = 6.2376 $
$\Rightarrow x = 18.5 - 6.2376$

$\Rightarrow x = 12.2624$
Hence, $12.2624$ subtracted from $18.5$ gives $6.2376.$

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Question 83 Marks

By how much should $27.354$ be increased to get $52$?

Answer

Let the required value be $x$. According to the question,
$27.354 + x = 52 $
$\Rightarrow x = 52 - 27.354$

$\Rightarrow x = 24.646$
Hence, $24.646$ should $27.354$ be increased to get $52.$

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Question 93 Marks

Gopal travelled $125.5\ km$ by bus, $14.25\ km$ by pony and the rest of distance of Kedarnath on foot. If he covered a total distance of $150\ km$, how much did he travel on foot?

Answer

Distance travelled by bus $= 125.5\ km$
Distance travelled by pony $= 14.25\ km$
Suppose the distance travelled on foot $= x$
Total distance $= 150\ km$ = distance travelled by bus + distance travelled on pony + distance travelled travelled on foot
$= 150 = 125.5 + 14.25 + x $
$= 150 = 139.75 + x$
$= x= 10.25\ km$
Therefore, distance travelled on foot $= 10.25\ km.$

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Question 103 Marks

Suman purchased $5\ kg$ $75g$ of fruits and $3\ kg$ $465g$ of vegetables, and put them in a bag. If this bag with these contents weighs $9\ kg$, find the weight of the empty bag.

Answer

Weight of fruits $= 5\ kg$ $75g = 5.075\ kg$. Weight of vegetables$ = 3\ kg$ $465g = 3.465\ kg.$
Total weight of fruits and vegetables is:
$\underline{\ \ \ \ \ \ \ _1\ _1\\\ \ \ \ 5.075\text{kg}\\+3.465\text{kg}}\\\underline{\ \ \ \ 8.540\text{kg}}$
Now, the bag with these contents weighs $9\ kg.$
Therefore, the weight of empty bag is:

Hence, the weight of the empty bag is $460g.$

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Question 113 Marks

Vineeta bought a book for $Rs. 18.80$, a pen for $Rs. 8.50$ and some papers for $Rs. 5.05$. She gave fifty rupee to the shopkeeper. How much balance did she get back?

Answer

Price of the book $= Rs. 18.90$
Price of the pen $= Rs. 8.50$
Price of the paper $= Rs. 5.05$
Total price of three items $= Rs. (18.90 + 8.50 + 5.05)$
$= Rs. 32.45$
Total amount given to the shopkeeper $= Rs. 50$
Balance received $= Rs. (50 - 32.45)$
$= Rs. 17.55$

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Question 123 Marks

Evaluate the following: $36.36 - 28.4237 - 9.78 + 7.7$

Answer

$36.36 - 28.4237 - 9.78 + 7.7$
$= 36.36 + 7.7 - (28.4237 + 9.78)$
$\underline{\ \ _1\ _1\\\ \ 36.36\\+7.70}\\\underline{\ \ 44.06}$
$\underline{\ \ \ _1\ _1\ _1\\\ \ \ 28.4237\\+\ 9.7800}\\\underline{\ \ \ 38.2037}$
$=44.06-38.2037$

$= 5.8563$

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Question 133 Marks

Convert $2\frac{9}{40}$ into a decimal fraction.

Answer

$2\frac{9}{40}=2+\frac{9}{40}$
$=2+\frac{9\times25}{40\times25}$
$=2+\frac{225}{1000}$
$=2+0.225$
$=2.225$
Hence, the value of $2\frac{9}{40}$ into a decimal fraction is $2.225.$

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