Question 13 Marks
Write six distinct integers whose sum is $7$.
Answer
View full question & answer→Let the six distinct integers be $1, 2, -2, 3, -3$ and $6$.
Now, sum of the above six distinct integers $= 1 + 2 + (-2) + 3 + (-3) + 6.$
We can arrange the numbers, so that the positive integers and negative integers are grouped together.
We have, $1 + 2 + 3 + 6 + (-2) + (-3)$
$= 12 - 2 - 3 = 12 - 5 = 7$
Hence, the required integers are $1, 2, -2, 3, -3$ and $6$.
Note: There are infinite combinations exist.
Now, sum of the above six distinct integers $= 1 + 2 + (-2) + 3 + (-3) + 6.$
We can arrange the numbers, so that the positive integers and negative integers are grouped together.
We have, $1 + 2 + 3 + 6 + (-2) + (-3)$
$= 12 - 2 - 3 = 12 - 5 = 7$
Hence, the required integers are $1, 2, -2, 3, -3$ and $6$.
Note: There are infinite combinations exist.
Flence, $3$ less than $2$ is $-1$.
Flence, $2$ less than $2$ is $-4$.