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Question 15 Marks
Using number line, how do you compare:
$a.\ $Two negative integers?
$b.\ $Two positive integers?
$c.\ $One positive and one negative integer?
Answer
 
We know that, on the number line, points to the right of zero are positive integers and points to the left of zero are negative integers. Also, if move from left to the right on the number line, then number increases and if we move from right to the left on the number line, then number decreases.
$a.\ $If we compare two negative integers on the number line, then the number which is on the right of the other number, will be greater.
e.g.

Here, we see that $-2$ is on the right of $-3,$ so $-2$ is greater and $-3$ is smaller.
$b.\ $If we compare two positive integers on the number line, then the number which is on the right of the other number, will be greater.
e.g.

Here, we see that $3$ is on the right of $1,$ so $3$ is greater and $1$ is smaller.
$c.\ $If we compare one positive and one negative integers on the number line, then a positive integer is always greater than the negative integer.
e.g

Here, we see that $2$ is on the right of $-1,$ so $2$ is greater and $-1$ is smaller.
 
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Question 25 Marks
Match the items of Column $I$ with that of Column $II:$
S.No.
Column $I$
S.No.
Column $II$
$i.$
The additive inverse of $+2$
$A.$
$0$
$ii.$
The greatest negative integer
$B.$
$-2$
$iii.$
The greatest negative even integer
$C.$
$2$
$iv.$
The smallest integer greater than every negative integer
$D.$
$1$
$v.$
Sum of predecessor and successor of $-1$
$E.$
$-1$
Answer
S.No. Column $I$ S.No. Column $II$
$i.$ The additive inverse of $+2$ $B.$ $-2$
$ii.$ The greatest negative integer $E.$ $-1$
$iii.$ The greatest negative even integer $B.$ $-2$
$iv.$ The smallest integer greater than every negative integer $A.$ $0$
$v.$ Sum of predecessor and successor of $-1$ $B.$ $-2$
 
Solution:
$i.\ (B)$
Additive inverses are negatives of each other. So, additive inverse of $+2$ is $-2.$
$ii.\ (E)$
In case of negative integers, the one closer to zero is always greater. $-1$ is closest to zero.

$iii.\ (B)$
Negative even integers are $-2, -4, -6,...$ Out of them, $-2$ is greatest.

$iv.\ (A)$
$0$ is the smallest integer greater than every negative integer.
$v.\ (B)$
Predecessor of $-1$ is $-2$
Successor of $-1$ is $0.$

Sum of predecessor and successor of $-1 = -2 + 0 = -2.$
 
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