2 Marks Questions

Question 12 Marks

Bajinder runs ten times around a square track and covers $4\ km.$ Find the length of the track.

Answer

Given, total length of track covered by Bajinder $= 4\ km = 4000m [\therefore 1\ km = 1000m]$
\therefore Length of track covered in $10$ rounds $= 4000m$
Length of track covered in $1$ round $=\frac{4000}{10}=400\text{m}$
Hence, the length of the track is $400m.$

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Question 22 Marks

The region given in Fig. is measured by taking $\Box$ as a unit. What is the area of the region?

Answer

Given, $\Box = 1$unit
and total region $= 13$
$\therefore$ Area of region $= 13 \times \Box$
$= 13 \times 1$
$= 13\ sq$ units

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Question 32 Marks

Length of a rectangle is three times its breadth. Perimeter of the rectangle is $40\ cm.$ Find its length and width.

Answer

Let width of rectangle $(b) = x \ cm$
Then, length of rectangle $(l) = 3x \ cm.$
As we know, Perimeter of rectangle $= 2(Z + b) $
$\Rightarrow 40 = 2(3x + x) $
$\Rightarrow 8x = 40$
$\Rightarrow\text{x}=\frac{40}{8}=5\text{cm}$
Hence, the length is $15\ cm$ and the width is $5\ cm.$

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Question 42 Marks

Perimeter of an isosceles triangle is $50\ cm.$ If one of the two equal sides is $18\ cm$, find the third side.

Answer

Given, perimeter $= 50\ cm$
Perimeter of an isosceles triangle $=$ Sum of its all sides
$\Rightarrow $ Perimeter $= a + b + c $
$\Rightarrow 50 = 18 + 18\ +$ Third side
$\Rightarrow 50 - 36 =\ $ Third side
Third side $= 14\ cm$

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Question 52 Marks

The perimeter of a square garden is $48m.$ A small flower bed covers $18\ sq-m$ area inside this garden. What is the area of the garden that is not covered by the flower bed? What fractional part of the garden is covered by flower bed? Find the ratio of the area covered by the flower bed and the remaining area.

Answer

Given, perimeter of hexagon $= 60\ cm$ and total sides in hexagon $= 6$
Now, length of each side $=\frac{\text{Perimeter of haxagon}}{\text{Total number of sides}}$
$=\frac{60}{6}=10\text{cm}$

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MATHS 2 Marks Questions

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