Question 11 Mark
Find the side of the square whose perimeter is: $16m$
Answer
View full question & answer→Side of a square = Perimeter $4$ Perimeter $= 16m$ Side of this square $=\frac{16}{4}$ $=4\text{m}$
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Question 21 Mark
Fill in the blanks: The length and breadth of a rectangle are $12\ cm$ and $5\ cm$, respectively, then its diagonal is ________ $cm.$
Answer
View full question & answer→The length and breadth of a rectangle are $12\ cm$ and $5\ cm$, respectively, then its diagonal is $13 \ cm$.
We have, Length of the rectangle $= 12\ cm$ and
Breadth of the rectangle $= 5\ cm$
Now, the diagonal of the rectangle $=\sqrt{(\text{Length})^{2}+(\text{Breadth})^{2}}$
$=\sqrt{12^{2}+5^{2}}$
$=\sqrt{144+25}$
$=\sqrt{169}$
$=13\text{cm}$
We have, Length of the rectangle $= 12\ cm$ and
Breadth of the rectangle $= 5\ cm$
Now, the diagonal of the rectangle $=\sqrt{(\text{Length})^{2}+(\text{Breadth})^{2}}$
$=\sqrt{12^{2}+5^{2}}$
$=\sqrt{144+25}$
$=\sqrt{169}$
$=13\text{cm}$
Question 31 Mark
Find the perimeter of the following shape:
Answer
View full question & answer→Perimeter = Sum of lengths of all sides of a closed figure.
Perimeter $= (3 + 3 + 3 + 3 + 3)cm = 15\ cm$
Perimeter $= (3 + 3 + 3 + 3 + 3)cm = 15\ cm$
Question 41 Mark
Which of the following are closed curves? Which of them are simple?
Answer
View full question & answer→Closed curves: Figure $(ii), (iii), (iv), (vi)$, and $(vii)$ are closed curves.
Simple closed curves: whereas Figure $(ii), (iii), (iv)$ and $(vi)$ are simple closed curves.
Simple closed curves: whereas Figure $(ii), (iii), (iv)$ and $(vi)$ are simple closed curves.
Question 51 Mark
Fill in the blanks: The area of a rectangle is $120\ cm^2$, If the breadth is 6\ cm, then its length is _________.
Answer
View full question & answer→The area of a rectangle is $120\ cm^2$, If the breadth is 6\ cm, then its length is $60m.$
We have,
Area of the rectangle $= 120\ cm^2$ and
Breadth of the rectangle $ = 6\ cm$
As, the length of the rectangle $=\frac{\text{Area}}{\text{Breadth}}$
$=\frac{120}{6}$
$=20\text{cm}$
We have,
Area of the rectangle $= 120\ cm^2$ and
Breadth of the rectangle $ = 6\ cm$
As, the length of the rectangle $=\frac{\text{Area}}{\text{Breadth}}$
$=\frac{120}{6}$
$=20\text{cm}$
Question 61 Mark
Fill in the blanks: The perimeter of a square $16\ cm$, then its area is ________ $cm^2$.
Answer
View full question & answer→The perimeter of a square $16\ cm$, then its area is $16 \ cm^2$.
As, the perimeter of the square $= 16\ cm$
So, the side of the square $=\frac{\text{Perimeter}}{4}$
$=\frac{16}{4}$ $=4\text{cm}$ Now, the area of the square = (Side $\times $ Side) $= 4 \times 4 = 16\ cm^2$
As, the perimeter of the square $= 16\ cm$
So, the side of the square $=\frac{\text{Perimeter}}{4}$
$=\frac{16}{4}$ $=4\text{cm}$ Now, the area of the square = (Side $\times $ Side) $= 4 \times 4 = 16\ cm^2$
Question 71 Mark
Find the perimeter of the following shape:
Answer
View full question & answer→Perimeter = Sum of lengths of all sides of a closed figure.
Perimeter $= (23 + 35 + 40 + 35)cm = 133\ cm$
Perimeter $= (23 + 35 + 40 + 35)cm = 133\ cm$
Question 81 Mark
Find the perimeter of the following shape:
Answer
View full question & answer→Perimeter = Sum of lengths of all sides of a closed figure.
Perimeter $= (15 + 15 + 15 + 15)cm $
$= 60\ cm$
Perimeter $= (15 + 15 + 15 + 15)cm $
$= 60\ cm$
Question 91 Mark
Fill in the blanks: The perimeter of a square whose area is $225m^2$ is ________.
Answer
View full question & answer→The perimeter of a square whose area is $225m^2$ is 60 m.
As, the area of the square $= 225m^2$ So, the side of the square $=\sqrt{\text{Area}}$
$=\sqrt{225}$ $=15\text{m}$
Now, the perimeter of the square $= 4 \times $ Side $= 4 \times 15 = 60m$
As, the area of the square $= 225m^2$ So, the side of the square $=\sqrt{\text{Area}}$
$=\sqrt{225}$ $=15\text{m}$
Now, the perimeter of the square $= 4 \times $ Side $= 4 \times 15 = 60m$
Question 101 Mark
Define perimeter of a closed figure.
Answer
View full question & answer→The length of the boundary of a closed figure is known as its permieter.
Question 111 Mark
Find the perimeter of the following shape:
Answer
View full question & answer→Perimeter = Sum of lengths of all sides of a closed figure.
Perimeter $= (4 + 2 + 1 + 5)cm = 12\ cm.$
Perimeter $= (4 + 2 + 1 + 5)cm = 12\ cm.$
Question 121 Mark
Fill in the blanks: If the ratio between the length and perimeter of a rectangular plot is $1 : 3$, then the ratio between the length and breadth of the plot is _________.
Answer
View full question & answer→If the ratio between the length and perimeter of a rectangular plot is $1 : 3$,
then the ratio between the length and breadth of the plot is 2 : 1.
Let the length of the rectangular plot be $x$ and its perimeter be $3x.$
As, the breadth of the rectangular plot $=\Big(\frac{\text{Perimeter}}{2}\Big)-\text{Length}$
$=\frac{3\text{x}}{2}-\text{x}$
$=\frac{3\text{x}-2\text{x}}{2}$
$=\frac{\text{x}}{2}$
Now, the ratio between the length and breadth of the plot $=\frac{\text{Length}}{\text{Breadth}}$
$=\frac{\text{x}}{\big(\frac{\text{x}}{2}\big)}$
$=\frac{2\text{x}}{\text{x}}$
$=\frac{2}{1}$
$=2:1$
then the ratio between the length and breadth of the plot is 2 : 1.
Let the length of the rectangular plot be $x$ and its perimeter be $3x.$
As, the breadth of the rectangular plot $=\Big(\frac{\text{Perimeter}}{2}\Big)-\text{Length}$
$=\frac{3\text{x}}{2}-\text{x}$
$=\frac{3\text{x}-2\text{x}}{2}$
$=\frac{\text{x}}{2}$
Now, the ratio between the length and breadth of the plot $=\frac{\text{Length}}{\text{Breadth}}$
$=\frac{\text{x}}{\big(\frac{\text{x}}{2}\big)}$
$=\frac{2\text{x}}{\text{x}}$
$=\frac{2}{1}$
$=2:1$