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17 questions · timed · auto-graded

Question 12 Marks
In a city, polio drops were given to $212583$ children on Sunday in March $2008$ and to $216813$ children in the next month. Find the difference of the numbers of children getting polio drops in the two months.
Answer
Given, polio drops given in March $2008 = 212583$
polio drops given in April $2008 = 216813$
Now, difference of the numbers of children $= 216813 - 212583$
$= 4230$
Hence, the difference of the number of children getting polio drops in the two months is $4230.$
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Question 22 Marks
How many lakh make five billion?
Answer
We know that, $10$ lakh $= 1$ million
$100$ lakh $= 10$ million
$100$ lakh $= 1$ crore
$1000$ million $= 100$ crore
$1$ billion $= 100$ crore $= 100 \times 100$ lakh $= 10000$ lakh
​​​​​​​So, $5$ billion $= 5 \times 10000 = 50000$ lakh
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Question 32 Marks
Find the sum of the greatest and the least six-digit numbers formed by the digits $2, 0, 4, 7, 6, 5,$ using each digit only once.
Answer
Given digits are $2, 0, 4, 7, 6$ and $5.$
Using each digit only once,
The greatest six-digit number $= 765420$
The smallest six-digit number $= 204567$
Now, the sum of these numbers $= 765420 + 204567 $
$= 969987$
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Question 42 Marks
A garment factory produced $216315$ shirts, $182736$ trousers and $58704$ jackets in a year. What is the total production of all the three items in that year$?$
Answer
Given, a garment factory produced shirts $= 216315$
Produced trousers $= 182736 $
Produced jackets $= 58704$
Total production of all the three items in that year $=$ Sum of all items $= 216315 + 182736 + 58704 = 457755 $
Hence, the total production of all the three items in that year is $457755.$
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Question 52 Marks
The population of a town is $450772.$ In a survey, it was reported that one out of every $14$ persons is illiterate. In all how many illiterate persons are there in the town$?$
Answer
Given,total population of town $= 450772$
One out of every $14$ persons is illiterate.
Now, total illiterate persons $=\frac{\text{Total population of town}}{14}$
$=\frac{450772}{14}$
$=32198$
Hence, the number of illiterate persons in the town is $32198.$
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Question 62 Marks
Out of $180000$ tablets of vitamin $A.\ 18734$ are distributed among the students in a district. Find the number of the remaining vitamin tablets.
Answer
We have, Total tablets of vitamin $A = 180000$
Tablets distributed among children $= 18734$
 Now, remaining vitamin A tablets $= 180000 - 18734 = 161266$
Hence, the number of the remaining vitamin $A$ tablets is $161266.$
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Question 72 Marks
Arrange the following numbers in descending order. $8435, 4835, 13584, 5348, 25843$
Answer
We have, $8435, 4835, 13584, 5348, 25843$
For arranging the numbers in descending order,
we have to compare the numbers and arrange them from highest to lowest. $25843 > 13584 > 8435 > 5348 > 4835$
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Question 82 Marks
A person had $Rs. 1000000$ with him. He purchased a colour $TV$ for $Rs. 16580,$ a motorcycle for $Rs. 45890$ and a flat for $Rs. 870000.$ How much money was left with him$?$
Answer
Given, total money $= Rs. 1000000$
Money spent on a colour $TV = Rs. 16580$
Money spent on a motorcycle $= Rs. 45890$ and
money spent on a flat $= Rs. 870000$
Total amount spent $= 16580 + 45890 + 870000 = Rs. 932470 $
Money left with him $= 1000000 - 932470 = Rs. 67530 $
Hence, $Rs. 67530 $ was left with him.
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Question 92 Marks
Make the greatest and the smallest $5$-digit numbers using different digits, in which $5$ appears at ten’s place.
Answer
According to the question, $5$ must appear at ten’s place.
Now, for the greatest number, digits $(0-9)$ should be arranged in descending order, i.e. $9, 8, 7, 6, 5, 4, 3, 2, 1, 0$
The greatest number of $5$ digits $= 98756$
and for the smallest number, digits $(0-9)$ should be arranged in ascending order, i.e. $0,1, 2, 3, 4, 5, 6, 7, 8, 9$
The smallest number of $5$ digits $= 10253$
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Question 102 Marks
In $2001,$ the populations of Tripura and Meghalaya were $3,199,203$ and $2,318,822,$ respectively. Write the populations of these two states in words.
Answer
Population of Tripura $= 3,199,203$
In words, three million, one hundred ninty-nine thousand, two hundred three.
population of Meghalaya $= 2,318,822$
In words, two million, three hundred eighteen thousand, eight hundred twenty two.
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Question 112 Marks
How many grams should be added to $2\ kg\ 300\ g$ to make it $5\ kg\ 68\ g?$
Answer
Let $x$ be added to $2\ kg\ 300\ g$ or $2300\ g$ to make it $5\ kg\ 68\ g$ or $5068\ g.$
Then, $2 \ kg\ 300\ g + x = 5\ kg\ 68 $
$g [1\ kg = 1000\  g] $
$\Rightarrow 2300\ g + x = 5068\ g$
$ \Rightarrow x = 5068\ g - 2300\ g$
$ \Rightarrow x = 2768\ g$
Hence, $2\ kg\ 768\ g$ should be added to $2\ kg\ 300\ g$ to make it $5\ kg\ 63\ g.$
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Question 122 Marks
The population of a town was $78787$ in the year $1991$ and $95833$ in the year $2001.$ Estimate the increase in population by rounding off each population to nearest hundreds.
Answer
$78787$ rounded off to the nearest hundreds $= 7880095833$
rounded off to the nearest hundreds $= 95800$
The estimated increase in population $= 95800 - 78800$
$= 17000$
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Question 132 Marks
How many million make $3$ crore$?$ 
Answer
We know that, $1$ crore $= 10$ million $3$ crore $=3 \times 10$ million $= 30$ million
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Question 142 Marks
Estimate the product $758 \times 6784$ using the general rule.
Answer
We have, $758 \times 6784$ Rounded off $758$ to nearest hundreds $= 800$ and rounded off $6784$ to nearest hundreds $= 7000$ So, estimated product $= 800 \times 7000 = 5600000$
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Question 152 Marks
Find the difference between the largest number of seven digits and the smallest number of eight digits.
Answer
The largest $7-$digit number $= 9999999$
 The smallest $8-$digit number $= 10000000$
Now, difference between the smallest $8-$digit number and the largest $7-$digit number $= 10000000 - 9999999 = 1$
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Question 162 Marks
The diameter of Jupiter is $142800000$ metres. Insert commas suitably and write diameter according to International System of Numeration.
Answer
Given, diameter of Jupiter $= 142800000m$
According to International System of Numeration, Diameter of Jupiter $= 142,800,000$ metres.
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Question 172 Marks
A box contains $50$ packets of biscuits each weighing $120g.$ How many such boxes can be loaded in a van, which cannot carry beyond $900\ kg?$
Answer
Given, total number of packets $= 50$
Weight of each packet $= 120g$
Weight of a box $= 50 \times 120g = 6000g $
$= 6\ kg [1000g = 1\ kg]$
Required number of boxes $=\frac{900}{6}=150$
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