3 Marks Question

Question 13 Marks

What is a trapezium? When do you call a trapezium an isosceles trapezium? Draw an isosceles trapezium. Measure its side and angles.

Answer

A
trapezium has only one pair of parallel sides.
A trapezium is said to be an isosceles trapezium if its non-parallel sides are equal.
Following are the measures of the isosceles trapezium:
$AB = 5.4\ cm$
$BC = 3\ cm$
$DC = 7.4\ cm$
$AD = 3\ cm$
$\angle\text{A}=\angle\text{B}=110^{\circ}$
$\angle\text{D}=\angle\text{C}=70^{\circ}$

View full question & answer→

Question 23 Marks

Two sides of a parallelogram are in the ratio $4 : 3.$ If its perimeter is 56cm, find the lengths of its sides.

Answer

Two sides of a parallelogram are in the ratio $4 : 3.$
Let the two sides be $4x$ and $3x.$
In a parallelogram, opposite sides are equal and parallel.
So, they are also in the ratio of $4 : 3$,
i.e. $4x$ and $3x.$
Perimeter $= 4x + 3x + 4x + 3x$
$\Rightarrow 56 = 14x$
$\Rightarrow x = 5614$
$\Rightarrow x = 4$
Therefore, $4x = 16$ and $3x = 12$
Lengths of its sides are $16\ cm, 12\ cm, 16\ cm$ and $12\ cm.$

View full question & answer→

Question 33 Marks

In the adjacent figure, a quadrilateral has been shown.

Name:
$i.\ $Its diagonals.
$ii.\ $Two pairs of opposite sides.
$iii.\ $Two pairs of opposite angles.
$iv.\ $Two pairs of adjacent sides.
$v.\ $Two pairs of adjacent angles.

Answer

$i.\ $The diagonals are $AC$ and $BD.$
$ii.\ AB$ and $CD$, and $AD$ and $BC$ are the two pairs of opposite sides.
$iii.\ \angle\text{A}$ and $\angle\text{C},$ and $\angle\text{B}$ and $\angle\text{D}$ are the two pairs of opposite angles.
$iv.\ AB$ and $BC$, and $AD$ and $DC$ are the two pairs of adjacent sides.
$v.\ \angle\text{A}$ and $\angle\text{B},$ and $\angle\text{C}$ and $\angle\text{D}$ are the two pairs of adjacent angles.

View full question & answer→

Question 43 Marks

Draw a parallelogram $ABCD$ in which $AB = 6.5\ cm, AD = 4.8\ cm$ and $\angle\text{BAD}=70^{\circ.}$ Measure its diagonals.

Answer

Since $ABCD$ is a parallelogram, $AB = DC = 6.5cm$ and $AD = BC = 4.8cm.$
Given:$\angle\text{A}=70^{\circ}$

Steps of construction:
$1.$Draw $AD$ equal to $4.8\ cm.$
$2.$Make an angle of $70^\circ $ at $A$ and cut an arc of $6.5\ cm$. Name it $B.$
$3.$Cut an arc of $4.8\ cm$ from $B$ and $6.5\ cm$ from $D$. Name it $C.$
$4.$Join $AB, BC$ and $CD.$
$5.$Measuring the diagonal $AC$ and $BD$, we get $AC$ equal to $9.2\ cm$ and $BD$ equal to $6.6\ cm.$

View full question & answer→

MATHS 3 Marks Question

Take a timed test