MCQ 511 Mark
Rashmi borrowed $Rs. 25,500$ from a bank for one year if the bank charge interest of $10 \%$ per annum compounded half-yearly what amount will he have to pay after the given time period.
- ✓
$Rs. 28113.75$
- B
$Rs. 28619$
- C
$Rs. 28115.50$
- D
$Rs. 27115.75$
AnswerCorrect option: A. $Rs. 28113.75$
Principal $(P) = Rs 25,500$ Rate of interest $(R) = 10 \%$ Time $(T) = 1$ year
As the Principal is compounded half-yearly rate will be halved and time becomes twice
Now Amount $(\text{A})=\text{P}\Bigg(1+\frac{\frac{\text{R}}{2}}{100}\Bigg)^{2\times\text{r}}=\text{P}\Big(1+\frac{\text{R}}{200}\Big)^{2\text{r}}$
$\Rightarrow\text{A}=25500\Big(1+\frac{10}{200}\Big)^2$
$\Rightarrow\text{A}=25500\Big(\frac{210}{200}\Big)^2$
$\Rightarrow\text{A}=28113.75$
View full question & answer→MCQ 521 Mark
Tick $(\checkmark)$ the correct answer in the following:
What percent of $92$ is $120$?
- A
$75 \%$
- B
$33\frac{1}{3}\%$
- ✓
$133\frac{1}{3}\%$
- D
AnswerCorrect option: C. $133\frac{1}{3}\%$
$\Big(\frac{120}{90}\times100\Big)\%=133\frac{1}{3}\%$
View full question & answer→MCQ 531 Mark
The $S.I.$ of $Rs. 100$ of $1$ year at the rate of $3$ paise per rupee per month is:
- A
$Rs. 30$
- ✓
$Rs. 36$
- C
$Rs. 24$
- D
$Rs. 48$
AnswerCorrect option: B. $Rs. 36$
$S.I = 100 \times 1 \times (3 \times 12) = 3600$ paise $= Rs. 36$
View full question & answer→MCQ 541 Mark
In what time will a sum of $Rs. 800$ at $5 \%$ $p.a. Cl$ amounts to $Rs. 882$?
- A
$1$ year
- ✓
$2$ years
- C
$4$ years
- D
$5$ years
AnswerCorrect option: B. $2$ years
$2$ years
View full question & answer→MCQ 551 Mark
On what a discount is calculated?
AnswerDiscount refers to the condition of the price of a bond that is lower than the face value. The discount equals the difference between the price paid for and it’s par value.
Discount is a kind of reduction or deduction in the cost price of a product. It is mostly used in consumer transactions, where people are provided with discounts on various products. The discount rate is given in percentage.
Example: Find the $S.P.$ if
$M.P. = 1300$
Discount $= 10 \%$
By using the formulas
$SP$ = Marked price $(MP)$ - Discount
$\text{Discount}= \frac{(\text{MP }\times\text{ Discount}\%)}{100}$
$\text{Discount}\%= \frac{(\text{Discount})}{\text{MP}\times100}$
By using,
$\text{Discount}=\frac{(\text{MP}\times\text{Discount}\%)}{100}$
$= \frac{(1300\times10)}{100}$
$=\text{Rs. }130$
$SP = MP$ - Discount
$= (1300 - 130)$
$= Rs. 1170$
View full question & answer→MCQ 561 Mark
Which of the following statement is true?
- A
Sales tax is always calculated on the cost price of an item and is added to the value of the bill
- ✓
Sales tax is always calculated on the selling price of an item and is added to the value of the bill
- C
Sales tax is always calculated on the cost price of an item and is subtracted from the value of the bill.
- D
Sales tax is always calculated on the selling price of an item and is subtracted from the value of the bill.
AnswerCorrect option: B. Sales tax is always calculated on the selling price of an item and is added to the value of the bill
The sale tax is charged by the government on the sale of an item. It is collected by the shopkeepers from the customers and given to the government.
View full question & answer→MCQ 571 Mark
Tick $(\checkmark)$ the correct answer in the following: The marked price of an article is $10 \%$ more than the cost price and a discount of $10 \%$ is given on the marked price. The seller has.
- A
- B
$1 \%$ gain
- ✓
$1 \%$ loss
- D
AnswerCorrect option: C. $1 \%$ loss
Let the $CP$ be $Rs. 100$
Then, marked price = $Rs. 110$
Discount $= 10 \%$ of $MP$
$= (10 \%$ of $Rs. 110)$
$=\text{Rs. }\Big(110\times\frac{10}{100}\Big)$
$= Rs. 11$
Now, $SP = (MP$ - (discount)
$= Rs (110 - 11) = Rs. 99$
$\therefore$ Loss percentage $= (100 - 99) \% = 1 \%$
View full question & answer→MCQ 581 Mark
Tick $(\checkmark)$ the correct answer in the following: What percent of $\frac{2}{7}$ is $\frac{1}{35}$
- A
$2.5 \%$
- ✓
$10 \%$
- C
$20 \%$
- D
$25 \%$
AnswerCorrect option: B. $10 \%$
Required percentage $=\Big(\frac{1}{35}\times\frac{7}{2}\times100\Big)\%=10\%$
View full question & answer→MCQ 591 Mark
Tick $(\checkmark)$ the correct answer in the following: $6 : 5$ when expressed as a percentage, is.
- A
$83\frac{1}{3}\%$
- B
$90 \%$
- ✓
$120 \%$
- D
$6.5 \%$
AnswerCorrect option: C. $120 \%$
$6:5=\frac{6}{5}\times100=120\%$
View full question & answer→MCQ 601 Mark
The ratio of 10km per hour to $30\ km$ per hour is:
- A
$3 : 1$
- B
$1 : 2$
- ✓
$1 : 3$
- D
$2 : 1$
AnswerCorrect option: C. $1 : 3$
$10 : 30 = 1 : 3$
View full question & answer→MCQ 611 Mark
A sofa-set was bought for $Rs. 10000$ Its value depreciated at the rate of $10 \%$ per annum. Find its value after one year.
- A
$Rs. 11000$
- ✓
$Rs. 9000$
- C
$Rs. 10000$
- D
$Rs. 1000$
AnswerCorrect option: B. $Rs. 9000$
Depreciation in $1$ year $=10000\times\frac{10}{100}=\text{Rs.}1000$
$\therefore$ Value after $1$ year
$= 10000 - 1000 = Rs. 9000$
View full question & answer→MCQ 621 Mark
During a sale, a shop offered a discount of $10 \%$ on the marked prices of all the items. What would a customer have to pay for a pair of jeans marked at $Rs. 1450$ and two shirts marked at $Rs. 850$ each?
- A
$Rs. 2,635$
- ✓
$Rs. 2,835$
- C
$Rs. 2,735$
- D
AnswerCorrect option: B. $Rs. 2,835$
$Rs. 2,835$
View full question & answer→MCQ 631 Mark
The cost of a vehicle is $Rs. 1,75,000$. If its value depreciates at the rate of $20 \%$ per annum, then the total depreciation after $3$ years was:
- A
$Rs. 82,500$
- B
$Rs. 84,500$
- C
$Rs. 86,400$
- ✓
$Rs. 85,400$
AnswerCorrect option: D. $Rs. 85,400$
$Rs. 85,400$
View full question & answer→MCQ 641 Mark
Tick $(\checkmark)$ the correct answer in the following:
A man sold two chairs for Rs. $500$ each. On one he gains $20 \%$ and on the other he loses $12 \%$. His net gain or loss percent is:
- ✓
$1.5 \%$ gain
- B
$2 \%$ gain
- C
$1.5 \%$ loss
- D
$2 \%$ loss
AnswerCorrect option: A. $1.5 \%$ gain
$SP$ of the first chair $= Rs. 500$
Gain percentage $= 20 \%$
$CP$ of the first chair $=\Big\{\frac{100}{100+\text{gain}\%}\times\text{SP}\Big\}$
$=\text{Rs. }\Big\{\frac{100}{100+20}\times500\Big\}$
$=\text{Rs. }\Big(\frac{100}{120}\times500\Big)$
$=\text{Rs. }416.67$
$SP$ of the second chair $= Rs. 500$
Loss percentage $= 12 \%$
$\therefore$ $CP$ of the second chair $=\frac{100}{(100-\text{loss}\%)}\times\text{SP}\%$
$=\text{Rs. }\Big\{\frac{100}{100-12}\times500\Big\}$
$=\text{Rs. }\Big(\frac{100}{88}\times500\Big)$
$=\text{Rs. }568.18$
Total $CP$ of the two chairs $= Rs. (416.67 + 568.18) = Rs.984.8$
Total $SP$ of the two chairs $= Rs. (500 \times 2) = Rs. 1000$
Since $SP > CP$, there is a gain in the whole transaction.
Now, gain $= Rs. (1000 - 984.85)$
$= Rs. 15.15$
$\therefore$ Gain percentage $=\Big(\frac{\text{gain}}{\text{CP}}\times100\Big)\%$
$=\Big(\frac{15.15}{984.85}\times100\Big)\%$
$=1.5\%$
View full question & answer→MCQ 651 Mark
The correct relationship is.
- A
$A+C.I=P$
- B
$C.I−P=A$
- ✓
$C.I=A−P$
- D
AnswerCorrect option: C. $C.I=A−P$
Compound Interest$(C.I)$=Amount$(A)$−Principal$(P)$
$C.I=A−P$
View full question & answer→MCQ 661 Mark
Tick $(\checkmark)$ the correct answer in the following: $5 \%$ of a number is $9$. The number is.
AnswerLet the required number be $x$. Then,
$5\% \text{ of x} = 9$
$\Rightarrow\frac{5}{100}\times\text{x}=9$
$\Rightarrow5\text{x}=900$
$\Rightarrow\text{x}=180$
View full question & answer→MCQ 671 Mark
A dealer lists his goods at $20 \%$ above cost price and allows a discount of $10 \%$. His gain percent is:
- A
$10 \%$
- B
$9 \%$
- ✓
$8 \%$
- D
$12 \%$
AnswerCorrect option: C. $8 \%$
Let the $CP$ be Rs. $100.$
Then, marked price = Rs. $120$
Discount $= 10 \%$ of MP
$= (10 \%$ of Rs.$120)$
$=\text{Rs. }\Big(120\times\frac{10}{100}\Big)$
$= $Rs. $12$
Now, $SP = (MP)$ - (discount)
$=$ Rs. $(120 - 12)$
$=$ Rs. $108$
Gain percentage $= (108 - 100) \%$
$= 8 \%$
View full question & answer→MCQ 681 Mark
A sum of money doubles itself in $3$ years at $CI$, when the interest is compounded annually. In how many years will it amount to $16$ times of itself?
- A
$6$ years
- B
$8$ years
- C
$16$ years
- ✓
$12$ years
AnswerCorrect option: D. $12$ years
$12$ years
View full question & answer→MCQ 691 Mark
If $a \%$ is the discount per cent on a marked price $x$, then discount is:
- A
$\frac{\text{x}}{\text{a}}\times100$
- B
$\frac{\text{a}}{\text{x}}\times100$
- ✓
$\text{x}\times\frac{\text{a}}{100}$
- D
$\frac{100}{\text{x}\times\text{a}}$
AnswerCorrect option: C. $\text{x}\times\frac{\text{a}}{100}$
Since, discount can be calculated always on marked price, when discount percentage is given.
Discount = Discount $ \%$ on marked price$=\text{x}\times\frac{\text{a}}{100}$
Hence, option $(c)$ is correct.
View full question & answer→MCQ 701 Mark
What will the. ratio of $60$ paise to Rs. $10$?
- ✓
$3 : 50$
- B
$50 : 3$
- C
$25 : 4$
- D
$1 : 2$
AnswerCorrect option: A. $3 : 50$
We know that $1$ rupe = $100$ paise
Therefore, Rs. $10 = 1000$ paise
So the ratio of $60$ paise to Rs. $10$ $=\frac{60}{1000}=\frac{3}{50}$
View full question & answer→MCQ 711 Mark
Suppose a certain sum doubles in $2$ years at $r \%$ rate of simple interest per annum or at $R \%$ rate of interest per annum compounded annually. We have
- A
$r < R$
- ✓
$R < r$
- C
$R = r$
- D
AnswerCorrect option: B. $R < r$
If the total amount received after $2$ yr is same for both simple interest and compound interest on same principal, then the rate of simple interest is greater than the rate of compound interest. i.e., $R < r$
Hence, option $(b)$ is correct.
View full question & answer→MCQ 721 Mark
Waheeda bought an air cooler for Rs. $3300$ including a tax of $10 \%$. The price of the air cooler before $VAT$ was added is:
- A
Rs. $2500$
- B
Rs. $2000$
- C
Rs. $2800$
- ✓
Rs. $3000$
AnswerCorrect option: D. Rs. $3000$
$10 \%$ $VAT$ on Rs. $100$ will make it Rs. $110$
So, for price including $VAT$ Rs. $110$, the original price is Rs. $100$
Then, Price including $VAT$ Rs. $3300$, the original price
$=\text{Rs.}\Big(\frac{100}{110}\Big)\times3300=\text{Rs. }3000$
View full question & answer→MCQ 731 Mark
Tick $(\checkmark)$ the correct answer in the following: A sum of $Rs. 25000$ was given as loan on compound interest for $3$ years compounded annually at $5%$ per annum during the first year, $6%$ per annum during the second year and $8%$ per annum during the third year. The compound interest is.
- A
$Rs. 5035$
- ✓
$Rs. 5051$
- C
$Rs. 5072$
- D
$Rs. 5150$
AnswerCorrect option: B. $Rs. 5051$
Principal $(P) = Rs. 25000$
Rate $(R_1) = 5\% $ for the first year
$R_2= 6\% $ for the second year
$R_3= 8\% $ for the third year
$\therefore$ Amount $(A)$ $=\text{P}\Big(1+\frac{\text{R}_1}{100}\Big)\Big(1+\frac{\text{R}_2}{100}\Big)\Big(1+\frac{\text{R}_3}{100}\Big)$
$=\text{Rs. }25000\Big(1+\frac{5}{100}\Big)\Big(1+\frac{6}{100}\Big)\Big(1+\frac{8}{100}\Big)$
$=\text{Rs. }25000\times\frac{21}{20}\times\frac{53}{50}\times\frac{27}{25}$
$=\text{Rs. }30051$
$\therefore$ $C.I = A - P = Rs. 30051 - 25000$
$= Rs. 5051$
View full question & answer→MCQ 741 Mark
The price of a motar bike was Rs. $40,000$ two years before. Now its price has dropped by $38 \%$. What is its cost now?
- A
Rs. $34,234$
- ✓
Rs. $24,800$
- C
Rs. $21,500$
- D
Rs. $20,800$
AnswerCorrect option: B. Rs. $24,800$
The price of the molar bike was Rs. $40,000$
The price dropped by $38 \%$.
The amount by which its cost dropped $=\frac{38}{100}\times40000=15200$
Therefore, the cost of the molar bike now $= 40,000 - 15,200 =$ Rs. $24,800$
View full question & answer→MCQ 751 Mark
Tick $(\checkmark)$ the correct answer in the following:
$\frac{3}{5}=?$
- A
$30 \%$
- B
$40 \%$
- C
$45 \%$
- ✓
$60 \%$
AnswerCorrect option: D. $60 \%$
$\frac{3}{5}=\frac{3}{5}\times100=60\%$
View full question & answer→MCQ 761 Mark
Tick $(\checkmark)$ the correct answer in the following: By selling a radio for Rs. $950$, a man loses $5 \%$. What percent shall he gain by selling it for Rs. $1040$?
- ✓
$4 \%$
- B
$4.5 \%$
- C
$5 \%$
- D
$9 \%$
AnswerCorrect option: A. $4 \%$
$SP$ of the radio = Rs. $950$
Loss $= 5 \%$
$\text{CP}=\Big\{\frac{100}{100-\text{loss}}\times\text{SP}\Big\}$
$=\text{Rs. }\Big\{\frac{100}{100-5}\times950\Big\}$
$=\text{Rs. }\Big(\frac{100}{95}\times950\Big)$
$=\text{Rs.}1000$
Now, gain = Rs. $(1040 - 1000)$ = Rs. $40$
$\therefore$ Gain percentage $=\Big(\frac{\text{gain}}{\text{CP}}\times100\Big)\%$
$=\Big(\frac{40}{1000}\times100\Big)\%=4\%$
View full question & answer→MCQ 771 Mark
Tick $(\checkmark)$ the correct answer in the following: $0.05$ is what percent of $20$?
- A
$25 \%$
- B
$2.5 \%$
- ✓
$0.25 \%$
- D
$0.025 \%$
AnswerCorrect option: C. $0.25 \%$
Required percentage $=\Big(\frac{0.05}{20}\times100\Big)\%=0.25\%$
View full question & answer→MCQ 781 Mark
The ratio of speed of a motorbike $50\ km$ per hour and speed of cycle $20 \km$ per hour is:
- A
$5 : 1$
- B
$2 : 5$
- C
$1 : 2$
- ✓
$5 : 2$
AnswerCorrect option: D. $5 : 2$
$\frac{\text{Speed of motorbike is 50km}}{\text{hr}}$
$\frac{\text{Speed of of cycle is 20km}}{\text{hr}}$
Ratio of their speeds are $=\frac{50}{20}=\frac{5}{2}=5 : 2$
View full question & answer→MCQ 791 Mark
A shopkeeper purchased $2$ refrigerators for Rs. $9800$ and Rs. $8200$ respectively. He sold them for Rs. $16920$ Find loss%.
- A
$2 \%$
- B
$4 \%$
- C
$5 \%$
- ✓
$6 \%$
AnswerCorrect option: D. $6 \%$
Total. $C.P, = 9800 + 8200 =$ Rs. $18000$
$S.P.$ = Rs. $16920$
$\therefore$ Loss = Rs. $18000$ - Rs. $16920$ = Rs. $1080$
$\therefore$ Loss $ \%$ $=\frac{1080}{18000}\times100\%=6\%$
View full question & answer→MCQ 801 Mark
Tick $(\checkmark)$ the correct answer in the following: Bananas are bought at $3$ for Rs. $2$ and sold at $2$ for Rs. $3$. The gain percent is:
- A
$25 \%$
- B
$50 \%$
- C
$75 \%$
- ✓
$125 \%$
AnswerCorrect option: D. $125 \%$
Cost price of a banana $=\text{Rs. }\frac{2}{3}$
Selling price of a banana $=\text{Rs. }\frac{3}{2}$
Now, profit $=\text{Rs. }\Big(\frac{3}{2}-\frac{2}{3}\Big)=\text{Rs.}\frac{9-4}{6}=\text{Rs. }\frac{5}{6}$
Gain percentage $=\frac{\text{gain}}{\text{CP}}\times100$
$=\frac{\big(\frac{5}{6}\big)}{\big(\frac{2}{3}\big)}\times100$
$=\frac{5}{6}\times\frac{3}{2}\times100$
$=\frac{5}{4}\times100$
$=5\times25$
$=125\%$
View full question & answer→MCQ 811 Mark
The sale price of a shirt is Rs. $176$. If a discount of $20 \%$ is allowed on its marked price, what is the marked price of the shirt?
- A
Rs. $160$
- B
Rs. $180$
- C
Rs. $200$
- ✓
Rs. $220$
AnswerCorrect option: D. Rs. $220$
Rs. $220$
View full question & answer→MCQ 821 Mark
Find the rate of sales tax if an article marked at Rs. $5000$ is sold for Rs. $5200$?
- A
$3 \%$
- ✓
$4 \%$
- C
$5 \%$
- D
$7 \%$
AnswerCorrect option: B. $4 \%$
$4 \%$
View full question & answer→MCQ 831 Mark
Tick $(\checkmark)$ the correct answer in the following: One-third of $1206$ is what percent of $134$?
- A
$3 \%$
- B
$30 \%$
- C
$20 \%$
- ✓
$300 \%$
AnswerCorrect option: D. $300 \%$
Required percentage $=\Big(\frac{1206}{3}\times\frac{1}{134}\times100\Big)\%=300\%$
View full question & answer→MCQ 841 Mark
Tick $(\checkmark)$ the correct answer in the following: The compound interest on Rs. $6250$ at $8 \%$ per annum for $1$ year, compounded half yearly, is.
- A
Rs. $500$
- ✓
Rs. $510$
- C
Rs. $550$
- D
Rs. $512.50$
AnswerCorrect option: B. Rs. $510$
Principal $(P)$ = Rs. $6250$
Rate $(R) = 8 \%$ p.a or $4 \%$ half yearly
Period $(n) = 1$ years or $2$ half years
$\therefore$ Amount $(A)$ $=\text{P}\Big(1+\frac{\text{R}}{100}\Big)^{\text{n}}$
$=\text{Rs. }6250\Big(1+\frac{4}{100}\Big)^2$
$=\text{Rs. }6250\times\frac{26}{25}\times\frac{26}{25}$
$=\text{Rs. }6760$
$\therefore$ $C.I = A - P =$ Rs. $6760 - 6250$
= Rs. $510$
View full question & answer→MCQ 851 Mark
Tick $(\checkmark)$ the correct answer in the following: If the selling price of 10 pens is the same as the cost price of 12 pens then gain percent is:
- A
$2 \%$
- B
$12 \%$
- ✓
$20 \%$
- D
$25 \%$
AnswerCorrect option: C. $20 \%$
Let Rs. $x$ be the $SP$ of each pen
$SP$ of $10$ pens = $CP$ of $12$ pens = Rs. $12x$
$CP$ of $10$ pens = Rs. $10x$
Now, gain = Rs. $(12x - 10x)$ = Rs. $2x$
$\therefore$ Gain percentage $=\Big(\frac{\text{gain}}{\text{CP}}\times100\Big)\%$
$=\Big(\frac{2\text{x}}{10\text{x}}\times100\Big)\%$
$=20\%$
View full question & answer→MCQ 861 Mark
On selling $100$ pens, a man gains the selling price of $20$ pens. The gain percent is:
- A
$20 \%$
- ✓
$25 \%$
- C
$16\frac{2}{3}\%$
- D
$15 \%$
AnswerCorrect option: B. $25 \%$
Let Rs. $x$ be the $SP$ of $100$ pens.
$SP$ of $1$ pen $=\text{Rs. }\frac{\text{x}}{100}$
Profit on $100$ pens = selling price of $20$ pens
$=\frac{20}{100}\times\text{x}$
$=\frac{\text{x}}{5}$
Now, $CP = SP$ - Profit
$=\text{x}-\frac{\text{x}}{5}$
$=\frac{4\text{x}}{5}$
$\therefore$ Profit percent on $100$ pens $=\frac{\text{Profit}}{\text{CP}}\times100$
$=\frac{\frac{\text{x}}{5}}{\frac{4\text{x}}{5}}\times100$
$=25\%$
View full question & answer→MCQ 871 Mark
Find which of the following represents $3 : 4$?
- A
$25 \%$
- B
$40 \%$
- C
$50 \%$
- ✓
$75 \%$
AnswerCorrect option: D. $75 \%$
$75 \%$
View full question & answer→MCQ 881 Mark
If the compound interest on a certain sum for $2$ years at $10 \%$ per annum is Rs $1050$, the sum is:
- A
Rs. $3000$
- B
Rs. $4000$
- ✓
Rs. $5000$
- D
Rs. $6000$
AnswerCorrect option: C. Rs. $5000$
Here, $\text{A}=\text{P}\times\Big(1+\frac{\text{R}}{100}\Big)^\text{n}$
$=\text{P}\times\Big(1+\frac{10}{100}\Big)^2$
$=\text{P}\times\Big(\frac{110}{100}\Big)^2$
$=\text{P}\times\Big(\frac{11}{10}\Big)\times\Big(\frac{11}{10}\Big)$
Now, $\text{CI}=\text{A}-\text{P}$
$\Rightarrow\text{Rs. }1050=\frac{121\text{p}}{100}-\text{P}$
$=\frac{121\text{P}-100\text{P}}{100}$
$=\frac{12\text{P}}{100}$
$\therefore\text{P}=\text{Rs. }\frac{1050\times100}{21}=\text{Rs. }5000$
View full question & answer→MCQ 891 Mark
$A$ bought a tape recorder for Rs. $8,000$ and sold it to $B$. $B$ in turn sold it to $C$, each earning a profit of $20 \%$. Which of the following is true:
- A
$A$ and $B$ earn the same profit.
- B
$A$ earns more profit than $B$.
- ✓
$A$ earns less profit than $B$.
- D
AnswerCorrect option: C. $A$ earns less profit than $B$.
Cost price of tape recorder for Rs. $8000$
Cost price of tape recorder for $B =20 \%$ profit on cost price for $A$
$=\frac{20}{100}\times9600+9600$$=1929+9600=\text{Rs}. 11520$
Here, profit for $A= Rs. 1600$
Profit for $B = Rs. 1920$
So, $A$ earns less profit than $B$.
Hence, option $(c)$ is correct.
View full question & answer→MCQ 901 Mark
The list price of an article is Rs. $220$. If it is sold at a discount of $20 \%$. What is its selling price:
View full question & answer→MCQ 911 Mark
Tick $(\checkmark)$ the correct answer in the following: The selling price of an article is $6565$ of the cost price. The gain percent is:
- ✓
$20 \%$
- B
$25 \%$
- C
$30 \%$
- D
$120 \%$
AnswerCorrect option: A. $20 \%$
Let Rs. $x$ be the $CP$ of each article
$SP$ of an article $=\text{Rs. }\frac{6}{5}\text{x}$
Now, gain $= (SP - CP)$
$=\text{Rs. }\Big(\frac{6}{5}\text{x}-\text{x}\Big)=\text{Rs. }\frac{\text{x}}{5}$
$\therefore$ Gain percentage $\Big(\frac{\text{gain}}{\text{CP}}\times100\Big)\%$
$=\Big(\frac{\frac{\text{x}}{5}}{\text{x}}\times100\Big)\%$
$=\Big[\big(\frac{\text{x}}{5}\times\frac{1}{\text{x}}\big)\times100\Big]\%=20\%$
View full question & answer→MCQ 921 Mark
A jacket was sold for Rs. $1,120$ after allowing a discount of $20 \%$. The marked price of the jacket is:
- A
Rs. $1440$
- ✓
Rs. $1400$
- C
Rs. $960$
- D
Rs. $866.66$
AnswerCorrect option: B. Rs. $1400$
Let the marked price of the jacket be Rs. $x$.
Discount $ \%$ on marked price $= 20 \%$
Selling price of jacket = Rs. $1120$
Then, $1120=\text{x}-\text{x}\times\frac{20}{100}$
$1120=\text{x}-\frac{\text{x}}{5}$
$1120=\frac{4\text{x}}{5}$
$\text{x}=\frac{1120\times5}{4}=280\times5=\text{Rs.} 1400$
So, marked price of jacket is Rs. $1400$
Hence, option $(b)$ is correct
View full question & answer→MCQ 931 Mark
Tick $(\checkmark)$ the correct answer in the following: At what rate percent per annum will a sum of Rs. $7500$ amount to Rs. $8427$ in $2$ years, compounded annually?
- A
$4 \%$
- B
$5 \%$
- ✓
$6 \%$
- D
$8 \%$
AnswerCorrect option: C. $6 \%$
Here $\text{A}=\text{P}\times\Big(1+\frac{\text{R}}{100}\Big)$
$=\text{Rs. }7500\times\Big(1+\frac{\text{R}}{100}\Big)^2$
$=\text{Rs. }7500\times\Big(1+\frac{\text{R}}{100}\Big)^2$
However, amount = Rs. $8427$
Now, Rs. $8427$
$=\text{Rs. }7500\times\Big(1+\frac{\text{R}}{100}\Big)^2$
$\Rightarrow\frac{\text{Rs. }8427}{\text{Rs. }7500}=\Big(1+\frac{\text{R}}{100}\Big)^2$
$\Rightarrow\Big(\frac{53}{50}\Big)^2=\Big(1+\frac{\text{R}}{100}\Big)^2$
$\Rightarrow\Big(1+\frac{\text{R}}{100}\Big)=\Big(\frac{53}{50}\Big)$
$\Rightarrow\frac{\text{R}}{100}=\frac{53}{50}-1$
$\Rightarrow\frac{\text{R}}{100}=\frac{53-50}{50}=\frac{3}{50}$
$\therefore\text{R}=\frac{300}{50}=6\%$
View full question & answer→MCQ 941 Mark
The difference between Compound Interest and Simple Interest on Rs. $24,000$ at $20 \%$ per annum for $2$ years is:
- A
Rs. $480$
- B
Rs. $954$
- ✓
Rs. $960$
- D
Rs. $879$
AnswerCorrect option: C. Rs. $960$
Given that. $P =$ Rs. $24,000$ $R = 20 \%$ per annum $T$ or $n$ = $2$ years
Now, for simple interest:
$\text{SI}=\text{SI}=\frac{\text{P}\times\text{R}\times\text{T}}{100}=\frac{24000\times20\times2}{100}=9,600$
For $CI$, we first calculate amount$(A)$
$\text{A}=\text{P}\Big[1+\frac{\text{R}}{100}\Big]^\text{n}$
$\Rightarrow\text{A}=24000\Big[1+\frac{20}{100}\Big]^2$
$\Rightarrow\text{A}=24000\Big[1+\frac{120}{100}\Big]^2$
$\Rightarrow\text{A}=34560$
Now compound interest $(CI) = A - p = 34650 - 24,000 = 10,560$
Clearly, difference between $CI$ and $Si$ = Rs. $(10,560 - 9,600)$ = Rs. $960$
View full question & answer→MCQ 951 Mark
$5 \%$ of which number is $12$?
AnswerLet the required number be $x$.
Then, we have:
$(5 \%$ of $x) = 12$
$\Rightarrow\Big(\text{x}\times\frac{5}{100}\Big)=12$
$\Rightarrow\frac{5\text{x}}{100}=12$
$\Rightarrow\text{x}=\Big(12\times\frac{100}{5}\Big)$
$\Rightarrow\text{x}=240$
View full question & answer→MCQ 961 Mark
Tick $(\checkmark)$ the correct answer in the following:On selling an article for Rs. $48$, a shopkeeper loses $20 \%$. In order to gain $20 \%$, what would be the selling price?
- A
Rs. $52$
- B
Rs. $56$
- C
Rs. $68$
- ✓
Rs. $72$
AnswerCorrect option: D. Rs. $72$
$SP$ = Rs. $48$
Loss $= 20 \%$
Now, $CP$ $=\frac{100}{100-\text{loss}\%}\times\text{SP}$
$\text{Rs.}=\frac{100}{100-\text{loss}\%}\times\text{SP}$
$\text{Rs.}=\Big(\frac{100}{100-20}\times48\Big)$
$\text{Rs.}=\Big(\frac{100}{80}\times48\Big)=\text{Rs. }60$
$\therefore$ Desired $SP$ $=\Big\{\frac{100+\text{gain}\%}{100}\times\text{CP}\Big\}$
$=\Big\{\frac{(100+20)}{100}\times60\Big\}$
$=\text{Rs. }\Big(\frac{12}{10}\times60\Big)$
$=\text{Rs. }72$
View full question & answer→MCQ 971 Mark
Tick $(\checkmark)$ the correct answer in the following: $40 \%$ of? $= 240.$
Answer$\frac{\text{x}}{100}\times400=60$
$\Rightarrow400\text{x}=6000$
$\Rightarrow\text{x}=15$
View full question & answer→MCQ 981 Mark
The ratio $1 : 4$ converted to percentage is:
- A
$50 \%$
- ✓
$25 \%$
- C
$75 \%$
- D
$4 \%$
AnswerCorrect option: B. $25 \%$
$1:4=\frac{1}{4}\times100\%=25\%$
View full question & answer→MCQ 991 Mark
To gain $25 \%$ after allowing a discount of $10 \%$, the shopkeeper must mark the price of the article which costs him Rs. $360$ as:
- ✓
Rs. $500$
- B
Rs. $450$
- C
Rs. $460$
- D
Rs. $486$
AnswerCorrect option: A. Rs. $500$
Let the marked price of the article be Rs. $x$.
Cost price of the article = Rs. $360$st
According to the question,
$\text{x}-\text{x}\times\frac{10}{100}-\frac{25\times360}{100}=360$
$\text{x}-\frac{\text{x}}{10}-90=360$
$\frac{9\text{x}}{10}=360+90$
$\text{x}=\frac{450\times10}{9}$
$\frac{9\text{x}}{10}=450$
$x =$ Rs. $500$
So, the marked price is Rs. $500$
Hence, option $(a)$ is correct.
View full question & answer→MCQ 1001 Mark
Tick $(\checkmark)$ the correct answer in the following: A bat is bought for Rs. $120$ and sold for Rs. $105$. The loss percent is:
- A
$15\%$
- ✓
$12\frac{1}{2}\%$
- C
$16\frac{2}{3}\%$
- D
$14\frac{1}{5}\%$
AnswerCorrect option: B. $12\frac{1}{2}\%$
$CP$ = Rs. $120$
$SP$ = Rs. $120$
Loss = Rs. $(120- 105)$ = Rs. $15$
$\therefore$ Loss percentage $=\Big(\frac{\text{loss}}{\text{CP}}\times100\Big)$
$=\Big(\frac{15}{120}\times100\Big)$
$=12\frac{1}{2}\%$
View full question & answer→