Questions

[1 Mark Questions]

🎯

Test yourself on this topic

10 questions · timed · auto-graded

Question 11 Mark
Find the slope of the line which is parallel to y = 0.7x – 11
Answer
y = 0.7x – 11
Slope = 0.7 ...(Comparing with y = mx + c)
View full question & answer
Question 21 Mark
Find the slope of the line which is perpendicular to the line x = – 11
Answer
Perpendicular to the line x = – 11
Slope is undefined ...(Since the line is intersecting the X-axis)
View full question & answer
Question 31 Mark
Find the slope of the following straight line
5y – 3 = 0
Answer
$\begin{aligned} & 5 y-3=0 \\ & 5 y=3 \\ & \Rightarrow y=\frac{3}{5} \\ & \text { Slope }=0\end{aligned}$
View full question & answer
Question 41 Mark
Find the slope of the following straight line
$
7 x-\frac{3}{17}=0
$
Answer
$7 x-\frac{3}{17}=0 \quad \ldots($ Comparing with $y = mx + c )$
$
7 x=\frac{3}{17}
$
Slope is undefined
View full question & answer
Question 51 Mark
Find the slope of a line joining the points $(5, \sqrt{5})$ with the origin
Answer
The given points is $(5, \sqrt{5})$ and $(0,0)$
$
\begin{aligned}
& \text { Slope of a line }=\frac{y_2-y_1}{x_2-x_1} \\
& =\frac{0-\sqrt{5}}{0-5} \\
& =\frac{\sqrt{5}}{5} \\
& =\frac{1}{\sqrt{5}}
\end{aligned}
$
View full question & answer
Question 61 Mark
Find the slope of a line joining the points
(sin θ, – cos θ) and (– sin θ, cos θ)
Answer
The given points is $(\sin \theta,-\cos \theta)$ and $(-\sin \theta, \cos \theta)$
$
\begin{aligned}
& \text { Slope of a line }=\frac{y_2-y_1}{x_2-x_1} \\
& =\frac{\cos \theta+\cos \theta}{-\sin \theta-\sin \theta} \\
& =\frac{2 \cos \theta}{-2 \sin \theta} \\
& =-\cot \theta
\end{aligned}
$
View full question & answer
Question 91 Mark
What is the slope of a line whose inclination with positive direction of x-axis is 90°
Answer
Here θ = 90°
Slope (m) = tan θ
Slope = tan 90°
= undefined.
View full question & answer
Question 101 Mark
What is the slope of a line whose inclination with positive direction of x-axis is 0°
Answer
Here θ = 0°
Slope (m) = tan θ
Slope = tan 0°
= 0
View full question & answer
[1 Mark Questions] - MATHS STD 10 Questions - Vidyadip