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Question 14 Marks
Find the concentration of a solution in terms of weight per cent if $20$ g of common salt is dissolved in $50$ g of water.
Answer
$\text { Weight percent }=\frac{\text { Weight of the solute }}{\text { Weight of the solute }+ \text { Weight of the solvent }} \times 100 $
$ \text { Weight of the common salt (solute) } =20 g$
$\text { Weight of water (solvent) } =50 g$
$ \therefore \text { Weight percent } =\frac{20}{20+50} \times 100 $
$ \text =\frac{20}{70} \times 100=28.57 \%$
$\therefore \text { Weight percent } =28.57 \%$
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Question 24 Marks
Write a note on the type of solution based on the amount of solute present in a solution.
Answer
Based on the amount of solute, in the given amount of solvent, solutions are classified into the following types.
(i) Saturated solution : A solution in which no more solute can be dissolved in a definite amount of the solvent at a given temperature is called saturated solution. Eg: 36 g of sodium chloride in 100 g of water at 25°C forms saturated solution.Further addition of sodium chloride, leave it undissolved.

(ii) Unsaturated solution : Unsaturated solution is one that contains less solute than that of the saturated solution at a given temperature. Eg: 10 g or 20 g or 30 g of Sodium chloride in 100 g of water at 25°C forms an unsaturated solution.

(iii) Super saturated solution : Supersaturated solution is one that contains more solute than the saturated solution at a given temperature. Eg: 40 g of sodium chloride in 100 g of water at 25°C forms super saturated solution. This state can be achieved by altering any other conditions liken temperature, pressure. Super saturated solutions are unstable, and the solute is reappearing as crystals when the solution is disturbed.

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Question 34 Marks
Distinguish between the saturated and unsaturated solution at a temperature of 25°C using the data given below (Note: Solubility of NaCl is 36 g).
  1. 16 g NaCl in 100 g water
  2. 36 g NaCl in 100 g water
Answer
The solubility of NaCl is 36g.
  1. 16 g NaCl in 100 g water is an unsaturated solution.
  2. 36 g NaCl in 100 g water is a saturated solutio
    Saturated SolutionUnsaturated Solution
    1. A solution in which no more solute can be dissolved in a definite amount of the solvent at a given temperature is called a saturated solution.1. A solution in which the solute is lesser in the amount in the solvent is called unsaturated solution.
    2. In this solution, no more solute can be dissolved. If more of solute is added, it will not dissolve to give a supersaturated solution.2. More of solute can be dissolved to get a saturated solution.
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Question 44 Marks
From the table given below, furnish your points of inference.
SubstanceSolubility at 25°C
NaCl36 g
NaBr95 g
NaI184
Answer
  • At 25°C, 36g NaCl is dissolved in 100 g water to give a saturated solution.
  • At 25°C, 95 g NaBr is dissolved in 100 g water to get a saturated solution.
  • At 25°C, 184g Nal is dissolved in 100 g water to get a saturated solution.
  • The solubility of a solute at a given solvent at a particular temperature is defined as the number of grams of solute necessary to saturate 100 g of the solvent at that temperature.
  • In the above tabular column, we infer that the solubility of NaI is the highest and the solubility of NaCl is the lowest.
  • All the NaCl, NaBr, Nal solution in water are called aqueous solutions.
  • Depending upon the amount of the solute, the solutions are classified as a saturated and unsaturated solution.
  • The above solutions are saturated solutions.
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[4 Mark Questions] - Science STD 10 Questions - Vidyadip