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Maths 3 marks

T2 CH2 Measurments · Tamil Nadu Board STD 6 (Tamil - English Medium). 19 questions.

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19 questions · timed · auto-graded

Question 13 Marks
Make a calendar for the month of February 2020. (Hint: January $1^{\text {st }} 2020$ is Wednesday)
Answer
Given Jan $1^{\text {st }} 2020$ is Wednesday.
$1^{\text {st }}+7=8^{\text {th }}$ Wednesday
$8^{\text {th }}+7=15^{\text {th }}$ Wednesday
$15^{\text {th }}+7=22^{\text {nd }}$ Wednesday
$22^{\text {nd }}+7=29^{\text {th }}$ Wednesday
Jan $=30^{\text {th }}$ Thursday
Jan $31^{\text {st }}$ Friday
Feb $1^{\text {st }}$ Saturday
February has 29 days as 2020 is a leap year.
February 2020
Sun Mon Tue Wed Thur Fri Sat
            1
2 3 4 5 6 7 8
9 10 11 12 13 14 15
16 17 18 19 20 21 22
23 24 25 26 27 28 29
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Question 23 Marks
The departure and arrival timing of the Vaigai Superfast Express (No. 12635) from Chennai Egmore to Madurai Junction are given. Read the details and answer the following.
Station Arrival Departure
Chennai Egmore − 13:40
Tambaram 14:08 14:10
Chengalpattu 14:38 14:40
Villupuram 15:50 15:55
Virudhachalam 16:28 16:30
Ariyalur 17:04 17:05
Trichy 18:30 18:35
Dindigul 20:03 20:05
Sholavandan 20:34 20:35
Madurai 21:20 −
(i) At what time does the Vaigai Express start from Chennai and arrive at Madurai?
(ii) How many halts are there between Chennai and Madurai?
(iii) How long does the train halt at the Villupuram junction?
(iv) At what time does the train come to Sholavandan?
(v) Find the journey time from Chennai Egmore to Madurai?
Answer
(i) It starts from Chennai at $13: 40 hrs$ and arrives at Madurai at 21:20 hrs
(ii) There are 8 halts
(iii) Departure from Villupuram = 15 hours 55 minutes
Arrival at Villupuram $=15$ hours 50 minutes
The train halt at Villupuram for $=05$ minutes
(iv) At 20:34 hours the train come to Sholavandan
(v) Arrival time at Madurai $=20$ hours $80(20+60)$ minutes
Departure time from Chennai Egmore $=13$ hours 40 minutes
Journey Time $=07$ hours 40 minutes
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Question 33 Marks
Calculate the duration of time.
from 17:00 hours to 5:15 hours
Answer
from 17:00 hours to 5:15 hours
From 17:00 hours to midnight = 24 hours − 17 hours
= 7 hours
Next day upto 5.15 hours = 5 hours 15 minutes
Duration of time = 12 hours 15 minutes
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Question 43 Marks
Calculate the duration of time.
from 5.30 pm to 12.40 p.m
Answer
from 5.30 a.m to 12.40 p.m
Duration of time from 5.30 a.m to noon = 12:00 – 5:30
= 6:30 i.e 6 hours 30 minutes
From noon to 12.40 p.m the duration = 00 hours 40 minutes
Total duration = 6 hours 30 minutes + 00 hours 40 minutes
= 6 hours 70 minutes
= 6 hours + (60 + 10) minutes
= 6 hours + 1 hr 10 minutes
= 7 hours 10 minutes
∴ Duration of time from 5:30 am to 12:40 pm = 7 hours 10 minutes
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Question 53 Marks
Calculate the duration of time.
from 1.30 pm to 10.25 p.m
Answer
from 1.30 pm to 10.25 p.m
10 hours 25 minutes
Duration of time = 9 hours 85 minutes
−1 hours 30 minutes
8 hours 55 minutes
Duration of time = 8 hrs 55 min.
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Question 63 Marks
Calculate the duration of time.
from 20:00 hours to 4:00 hours
Answer
from 20:00 hrs to 4:00 hrs
Duration of time upto midnight is = 24 hours −
20 hours
= 4 hours
From midnight to 4 hours = 4 hours
Total time = 8 hours ...[∵ 4 hours + 4 hours]
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Question 73 Marks
The duration of electricity consumed by the farmer for his pump set on Monday and Tuesday was 7 hours 20 minutes 35 seconds and 3 hours 44 minutes 50 seconds respectively. Find the total duration of consumption of electricity.
Answer
Electricity consumption on Monday $=7$ hours +20 minutes +35 seconds
Electricity consumption on Tuesday $=3$ hours +44 minutes +50 seconds
Total consumption $=10$ hours +64 minutes +85 seconds
$=10$ hours $+(60+4)$ minutes $+(60+25)$ seconds
$=10$ hours +1 hrs 4 minutes +1 minutes 25 seconds
$=11$ hours 5 minutes 25 seconds
$\therefore$ Total consumption of electricity $=11$ hours 5 minutes 25 seconds
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Question 83 Marks
Convert the following:
5 hours 35 minutes 40 seconds into seconds
Answer
5 hours 35 minutes 40 seconds into seconds
Hours Minutes Seconds Total seconds
5 5 × 60 5 × 60 × 60 18000
35 35 × 60 2100
40 40
Total 20140
∴ 5 hours 35 minutes 40 seconds = 20140 seconds
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Question 93 Marks
Convert the following:
$3 \frac{1}{2}$ hours into minutes
Answer
$3 \frac{1}{2} \text { hours into minutes }$
$3 \frac{1}{2} \text { hours }=3 \text { hours } 30 \text { minutes }$
$=3 \times 60 \text { minutes }+30 \text { minutes }$
$=180 \text { minutes }+30 \text { minutes }$
$=210 \text { minutes }$
$\therefore 3 \frac{1}{2} \text { hours }=210 \text { minutes }$
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Question 103 Marks
Match the following:
Column A Column B
(i) 9.55 a. 20 minutes past 2
(ii) 11.50 b. quarter past 4
(iii) 4.15 c. quarter to 8
(iv) 7.45 d. 5 minutes to 10
(v) 2.20 e. 10 minutes to 12
Answer
Column A Column B
(i) 9.55 d. 5 minutes to 10
(ii) 11.50 e. 10 minutes to 12
(iii) 4.15 b. quarter past 4
(iv) 7.45 c. quarter to 8
(v) 2.20 a. 20 minutes past 2
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Question 113 Marks
Convert 480 days into years
Answer
Convert 480 days into years. We know that 1 year $=365$ days. $\ldots[\because 480-365=115$ days $]$
480 days $=1$ year 115 days
115 days $=\frac{115}{30}$ months
$=3$ months 25 days
$\therefore 480$ days $=1$ year 3 months 25 days.
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Question 123 Marks
If $11^{\text {th }}$ of January 2018 is Thursday, what is the day on $20^{\text {th }}$ July of the same year?
Answer
January - 21 Days $(31-10)$
February - 28 Days
March - 31 Days
April - 30 Days
May - 31 Days
June - 30 Days
July - 19 Days
Total - 190 Days
190 days $\div 7$
190 days $=27$ weeks +1 day
Required day is the first day after Thursday.
$\therefore 20^{\text {th }}$ of July is Friday.
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Question 133 Marks
Find the number of days between the Republic day and Kalvi Valarchi Day in 2020
Answer
In 2020 Republic Day will be celebrated on $26^{\text {th }}$
January and Kalvi Valarchi Day will be celebrated on $15^{\text {th }}$ July
Number of days between 26.01.2020 and 15.07.2020
January - 6 Days ...(from 26.01.2020)
February - 29 Days ...(2020 is a leap year)
March - 31 Days
April - 30 Days
May - 31 Days
June - 30 Days
July - 15 Days ...(upto 15.07.2020)
Total - 172 Days
$\therefore$ Total number of days $=172$
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Question 143 Marks
A clock gains 3 minutes every hour. If the clock is set correctly at 5 a.m, find the time shown by the clock at 7 p.m?
Answer
Time gained for 1 hour = 3 min
Time duration from 5 a.m to 7 p.m = 14 hours
Time gained for 14 hours = 14 × 3 minutes
= 42 minutes
So, at 7 p.m, the clock shows 7 hrs 42 minutes
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Question 153 Marks
Thenmozhi’s height is $1.25\ m$ now. She grows $5\ cm$ every year. What would be her height after $6$ years?
Answer
Thenmozhi's present height $=1.25 m$
Rate of growth per year $=5 cm$
Her growth in $6$ years $=5 cm \times 6=30 cm$.
After $6$ years her height $=1.25 m +30 cm$
$ =1.25 \times 100+30 cm$
$=125+30 cm$
$=155 cm . $
$\therefore$ After $6$ years Thenmozhi's height will be $155 cm$.
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Question 163 Marks
Geetha brought 2 l and 250 ml of water in a bottle. Her friend drank 300 ml from it. How much of water is remaining in the bottle?
Answer
Quantity of water Geetha brought $=2$ I $250 ml$
$=2 \times 1000+250 ml$
$=2000+250 ml$
$=2250 ml$
Quantity of water her friend drank $=300 ml$
Remaining water $=2250-300$
$=1950 ml$
$=1 \text { litre } 950 ml$
Remaining water $=1$ litre $950 ml$.
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Question 173 Marks
Convert into lower units:
$15$ km (m, cm, mm)
Answer
$15 km ( m , cm , mm )$
$15 km =15 \times 1000 m$
$=15,000 m$
$15 km =15 \times 1,00,000 cm$
$=15,00,000 cm$
$15 km =15 \times 10,00,000 mm$
$=1,50,00,000 mm$
$15 km =15,000 m$
$=15,00,000 cm$
$=1,50,00,000 mm .$
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Question 183 Marks
Convert into higher units:
$13000$ mm (km, m, cm)
Answer
$ 13000 mm =13000.0 \times \frac{1}{10} cm =1,300 cm$
$13000 mm =13000.0 \times \frac{1}{1000} m =13 m$
$13000 mm =013000.0 \times \frac{1}{10,00,000 km }=0.013 km$
$13000 mm =13000 cm$
$=13 m$
$=0.013 km $
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Question 193 Marks
Convert into higher units:
$8257$ ml (kl, l)
Answer
$ 8257 ml =8257.0 \times \frac{1}{1000} l =8.257 l$
$8257 ml =008257.0 \times \frac{1}{1000000} kl =0.008257 kl$
$8257 ml =8.257 l$
$=0.008257 kl $
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