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7 questions · timed · auto-graded

Question 15 Marks
Draw a line segment AB of length 6 cm. At each end of this line segment AB, draw a line perpendicular to the line AB. Are these lines parallel?
Answer
Here CA and DB are perpendicular to AB.
Yes CA and DB are parallel.

Construction:

(i) Drawn a line segment AB of length 6 cm.
(ii) Place the set square on the line in such a way that the vertex of its right angle coincides with B first and A next and one arm of the right angle coincides with the line AB.
(iii) Drawn lines DB and CA through B and A, the other arm of the right angle of the set square.
(iv) The line CA and DB are perpendicular to AB at A and B.
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Question 25 Marks
Study the given figure and identify the following triangles.
Image
(a) equilateral triangle
(b) isosceles triangles
(c) scalene triangles
(d) acute triangles
(e) obtuse triangles
(f) right triangles
Answer
(a) BC = 1 + 1 + 1 + 1 = 4 cm
AB = AC = 4 cm
∆ABC is an equilateral triangle.
(b) ∆ABC and ∆AEF are isosceles triangles.
Since AB = AC = 4 cm
Also AE = AF.
(c) In a scalene triangle, no two sides are equal.
∆AEB, ∆AED, ∆ADF, ∆AFC, ∆ABD, ∆ADC, ∆ABF and ∆AEC are scalene triangles.
(d) In an acute-angled triangle all the three angles are less than 90°
∆ABC, ∆AEF, ∆ABF and ∆AEC are acute-angled triangles.
(e) In an obtuse-angled triangle any one of the angles is greater than 90°
∆AEB and ∆AFC are obtuse angled triangles.
(f) In a right triangle, one of the angles is 90°
∆ADB, ∆ADC, ∆ADE and ∆ADF are right-angled triangles.
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Question 35 Marks
Draw a line and mark a point R below it at a distance of 5.4 cm Through R draw a line parallel to the given line
Answer

Step 1: Using a scale draw a line AB and mark a point Q on the line.
Step 2: Place the set square in such a way that the vertex of the right angle coincides with Q and one of the edges of right angle lies along AB.
Mark the point R such that QR = 5.4 cm
Step 3: Place the scale and the set square as shown in the figure.
Step 4: Hold the scale firmly and slide the set square along the edge of the scale until the other edge touches the point R.
Draw a line RS through R.
Step 5: The line RS is parallel to AB. That is, RS || AB.figure.
Step 4: Hold the scale firmly and slide the set square along the edge of the scale until the other edge touches the point R.
Draw a line RS through R.
Step 5: The line RS is parallel to AB.
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Question 45 Marks
Draw a line segment measuring 7.8 cm. Mark a point B above it at a distance of 5 cm. Through B draw a line parallel to the given line segment
Answer

Step 1: Draw a line. Mark two points M and N on the line such that MN = 7.8 cm.
Mark a point B any where above the line.
Step 2: Place the set square below B in such a way that one of the edges that form a right angle lies along MN Place the scale along the other edge of the set square.
Step 3: Holding the scale firmly, Slide the set square along the edge of the scale until the other edge of the set square reaches the point B.
Through B draw a line.
Step 4: The line MN is parallel to AB.
That is, MN || AB.
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Question 55 Marks
Find the distance between the given lines using a set square at two different points on each of the pairs of lines and check whether they are parallel.
Answer
Making the points P, Q, R, S and A, B, C, D on the given lines
PQ = RS = 0.9 cm
AB = CD = 1 cm
Distance between the two lines are equal.
They are parallel lines.
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Question 65 Marks
Draw a line segment LM = 6.5 cm and take a point P not lying on it. Using a set square construct a line perpendicular to LM through P
Answer

Step 1: Draw a line LM = 6.5 cm and take a point X anywhere above the line LM.
Step 2: Place one of the arms of the right angle of a set square along with the line LM and the other arm of its right angle touches the point X.
Step 3: Draw a line through the point X meeting LM at Y.
Step 4: The line XY is perpendicular to the line LM at Y.
That is, LM ⊥ XY.
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Question 75 Marks
Draw a line segment AB = 7 cm and mark a point P on it. Draw a line perpendicular to the given line segment at P
Answer

Step 1: Draw a line AB = 7 cm and take a point P anywhere on the line.
Step 2: Place the set square on the line in such a way that the vertex which forms right angle coincides with P and one arm of the right angle coincides with the line AB.
Step 3: Draw a line PQ through P along the other arm of the right angle of the set square.
Step 4: The line PQ is perpendicular to the line AB at P.
That is, PQ ⊥ AB
∠APQ = ∠BPQ = 90°
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