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9 questions · timed · auto-graded

Question 11 Mark
Divide the following:
$\frac{3}{7} \div 4$
Answer
$\frac{3}{7} \div 4=\frac{3}{7} \times \frac{1}{4}$
$=\frac{3}{28} \ldots\left[\text { Reciprocal of } 4 \text { is } \frac{1}{4}\right]$
$\frac{3}{7} \div 4=\frac{3}{28}$
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Question 21 Mark
Multiply the following:
$3 \frac{5}{7} \times 1 \frac{1}{13}$
Answer
$3 \frac{5}{7} \times 1 \frac{1}{13}=\frac{26}{7} \times \frac{14}{13}$
$3 \frac{5}{7} \times 1 \frac{1}{13}=4$
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Question 41 Mark
Multiply the following:
$\frac{3}{8} \times \frac{4}{5}$
Answer
$\frac{3}{8} \times \frac{4}{5}=\frac{3 \times 4}{8 \times 5}$
$=\frac{12}{40}$
$=\frac{3}{10}$
$\frac{3}{8} \times \frac{4}{5}=\frac{3}{10}$
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Question 51 Mark
Convert mixed fraction into improper fraction and vice versa:
$12 \frac{1}{9} 6$
Answer
$12 \frac{1}{9} \text { is the given mixed fraction }$
$\text { Improper fraction }=\frac{(\text { Whole number } \times \text { Denominator })+\text { Numerator }}{\text { Denominator }}$
$=\frac{(12 \times 9)+1}{9}$
$=\frac{108+1}{9}$
$=\frac{109}{9}$
$12 \frac{1}{9}=\frac{109}{9}$
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Question 61 Mark
Convert mixed fraction into improper fraction and vice versa:
$3 \frac{7}{18}$
Answer
$3 \frac{7}{18} \text { is the given mixed fraction }$
$\text { Improper fraction }=\frac{(\text { Whole number } \times \text { Denominator })+\text { Numerator }}{\text { Denominator }}$
$=\frac{(3 \times 18)+7}{18}$
$=\frac{54+7}{18}$
$=\frac{61}{18}$
$3 \frac{7}{18}=\frac{61}{18}$
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Question 71 Mark
Convert mixed fraction into improper fraction and vice versa:
$\frac{99}{7}$
Answer
$\frac{99}{7}$ is the given improper fraction
14 - Quotient
Dividing Divisor 7) $\overline{99}$
$\frac{7}{29}$
28
1 - Remainder
$\frac{99}{7}=$ Quotient $\frac{\text { Remainder }}{\text { Divisor }}$
$=14 \frac{1}{7}$
$\frac{99}{7}=14 \frac{1}{7}$
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Question 81 Mark
Convert mixed fraction into improper fraction and vice versa:
$\frac{47}{6}$
Answer
$\frac{47}{6}$ is the given improper fraction Mixed fraction $=$ Quotient $\frac{\text { Remainder }}{\text { Divisor }}$
6) $\frac{7}{47}$
6) $\frac{42}{5}$
$
\frac{47}{6}=7 \frac{5}{6}
$
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Question 91 Mark
Find the sum of $\frac{1}{7}$ and $\frac{3}{9}$
Answer
To find $\frac{1}{7}+\frac{3}{9}$
$ \frac{1}{7}=\frac{1 \times 9}{7 \times 9}=\frac{9}{63}$
$\frac{3}{9}=\frac{3 \times 7}{9 \times 7}=\frac{21}{63}$
$\frac{1}{7}+\frac{3}{9}=\frac{9}{63}+\frac{21}{63}=\frac{30}{63} $
Simplifying $\frac{30}{63}=\frac{30 \div 3}{63 \div 3}=\frac{10}{21}$
$\therefore \frac{1}{7}+\frac{3}{9}=\frac{10}{21}$
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1 marks Question - Maths STD 6 Questions - Vidyadip