Question 12 Marks
Numerical problem.
At an orbital height of 400 km, find the orbital period of the satellite.
Answer
View full question & answer→h = 400 × 103m, R = 6371 × 103m,
v = 7616 × 103 kms– 1.
Substituting the values,
$\begin{aligned} T & =\frac{2 \pi( R + h )}{ v } \\ T & =6.28 \times \frac{6771}{7616} \\ T & =5.583 \times 10^3 S =5583 \\ T & \approx 93 min \end{aligned}$