MCQ 11 Mark
Directions : In the following questions, a statement of assertion $(A)$ is followed by a statement of reason $(R)$. Mark the correct choice as:
Assertion : In the figure, if $BC = 20m,$ then height $AB$ is $11.56m.$
Reason : $\tan\theta=\frac{\text{AB}}{\text{BC}}=\frac{\text{perpendicular}}{\text{base}}$ where $\theta$ is the $\angle\text{ACB}$

Assertion : In the figure, if $BC = 20m,$ then height $AB$ is $11.56m.$
Reason : $\tan\theta=\frac{\text{AB}}{\text{BC}}=\frac{\text{perpendicular}}{\text{base}}$ where $\theta$ is the $\angle\text{ACB}$

- ✓Both assertion $(A)$ and reason $(R)$ are true and reason $(R)$ is the correct explanation of assertion $(A)$.
- BBoth assertion $(A)$ and reason $(R)$ are true but reason $(R)$ is not the correct explanation of assertion $(A)$.
- CAssertion $(A)$ is true but reason $(R)$ is false.
- DAssertion $(A)$ is false but reason $(R)$ is true.
Answer
View full question & answer→Correct option: A.
Both assertion $(A)$ and reason $(R)$ are true and reason $(R)$ is the correct explanation of assertion $(A)$.
Both the assertion and reason are correct, reason is the correct explanation of the assertion.
$\tan30^\circ=\frac{\text{AB}}{\text{BC}}=\frac{\text{AB}}{20}$
$\text{AB}=\frac{1}{\sqrt{3}}\times20=\frac{20}{1.73}=11.56\text{m}$
$\tan30^\circ=\frac{\text{AB}}{\text{BC}}=\frac{\text{AB}}{20}$
$\text{AB}=\frac{1}{\sqrt{3}}\times20=\frac{20}{1.73}=11.56\text{m}$




