From a light house the angles of depression of two ships on opposite sides of the light house are observed to be $30^\circ$ and $45^\circ$ . If the height of the light house is $h$ metres, the distance between the ships is :
- ✓$(\sqrt{3}+1)\text{h meters}$
- B$(\sqrt{3}-1)\text{h meters}$
- C$\sqrt{3}\text{h meters}$
- D$1+\Big(1+\frac{1}{\sqrt{3}}\Big)\text{h meters}$
Answer: A.
View full solution →