Question types

Hyperbola question types

64 questions across 3 question groups — pick any mix to generate a MATHS paper with step-by-step answer keys.

64
Questions
3
Question groups
5
Question types
Sample Questions

Hyperbola questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Equation of the hyperbola whose vertices are $(\pm3,0)$ and foci at $(\pm5,0),$ is
  • $16x^2 - 9y^2 = 144$
  • B
    $9x^2 - 16y^2 = 144$
  • C
    $25x^2 - 9y^2 = 225$
  • D
    $9x^2 - 25y^2 = 81$

Answer: A.

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If $e_1$ and $e_2$ are respectively the eccentricities of the ellipse $\frac{\text{x}^2}{18}+\frac{\text{y}^2}{4}=1$ and the hyperbola $\frac{\text{x}^2}{9}-\frac{\text{y}^2}{4}=1,$ then the relation between $e_1$ and $e_2$ is
  • A
    $3\text{e}_1^2 + \text{e}_2^2 = 2$
  • B
    $\text{e}_1^2 + 2\text{e}_2^2 = 3$
  • $2\text{e}_1^2 +\text{e}_2^2 = 3$
  • D
    $\text{e}_1^2 + 3\text{e}_2^2 = 2$

Answer: C.

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The eccentricity of the hyperbola $x^2 - 4y^2 = 1$
  • A
    $\frac{\sqrt3}{2}$
  • ${\frac{\sqrt5}{2}}$
  • C
    ${\frac{2}{\sqrt3}}$
  • D
    $\frac{2}{\sqrt5}$

Answer: B.

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The distance between the directrices of the hyperbola $\text{x}=8\sec\theta,\text{y}=8,$ is
  • $8\sqrt2$
  • B
    $16\sqrt2$
  • C
    $4\sqrt2$
  • D
    $6\sqrt2$

Answer: A.

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The equation of the conic with focus at $(1, -1)$ directrix along $x - y + 1 = 0$ and eccentricity $\sqrt2$ is
  • $xy = 1$
  • B
    $2xy + 4x - 4y - 1 = 0$
  • C
    $x^2 - y^2 = 1$
  • D
    $2xy - 4x + 4y + 1 = 0$

Answer: A.

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If the foci of the ellipse $\frac{\text{x}^{2}}{16}+\frac{\text{y}^{2}}{\text{b}^{2}}=1$ and the hyperbola $\frac{\text{x}^{2}}{144}-\frac{\text{y}^{2}}{81}=\frac{1}{25}$ coincide, value of $\text{b}^{2}$
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If the latus-rectum throught one focus of a hyperbola subtends a right angle at the farther vertex, then write the eccentricity of the hyperbola.
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If e and e are respectively the eccentricities of the ellipse $\frac{\text{x}^2}{18}+\frac{\text{y}^2}{4}=1$ and the hyperbola $\frac{\text{x}^2}{9}-\frac{\text{y}^2}{4}=1,$ then write the value of $2\text{e}_1^2 +\text{e}_2^2.$
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