Case study (4 Marks)

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Question 14 Marks

No part of India is situated on the equator. Is it possible to have a geostationary satellite which always remains over New Delhi?

Answer

No, all geostationary orbits are concentric with the equator of the Earth.

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Question 24 Marks

Find the acceleration due to gravity of the moon at a point 1000 km above the moon's surface. The mass of the moon is $7.4 \times 10^{22} \mathrm{~kg}$ and its radius is 1740 km .

Answer

$\frac{\text{GM}}{(\text{R+h})^2}=\frac{6.67\times10^{-11}\times7.4\times10^{22}}{(1740+1000)^2\times10^6}$$=\frac{49.358\times10^{11}}{2740\times2740\times10^6}$
$=\frac{49.358\times10^{11}}{0.75\times10^{13}}$
$=65.8\times10^{-2}=0.65\text{m/s}^2$

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Physics Case study (4 Marks)

Case study (4 Marks)

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